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ACCENTURE EXAM HELP ! CISCO EXAM !

ACCENTURE EXAM HELP ! CISCO EXAM !

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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📈 Telegram kanali ACCENTURE EXAM HELP ! CISCO EXAM ! analitikasi

ACCENTURE EXAM HELP ! CISCO EXAM ! (@coding_are) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 13 194 obunachidan iborat bo'lib, Taʼlim toifasida 15 280-o'rinni va Hindiston mintaqasida 31 421-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 13 194 obunachiga ega bo‘ldi.

03 Iyul, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -134 ga, so‘nggi 24 soatda esa -8 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 3.18% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.52% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 419 marta ko‘riladi; birinchi sutkada odatda 200 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 1 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent placement, gaurntee, suree, capgemini, infosy kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

Yuqori yangilanish chastotasi (oxirgi ma’lumot 04 Iyul, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

13 194
Obunachilar
-824 soatlar
-157 kunlar
-13430 kunlar
Postlar arxiv
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def solve(s1, s2): n, m = len(s1), len(s2) Z = [0] * n l, r = 0, 0 for i in range(1, n): if i < r: Z[i] = min(r - i, Z[i - l]) while i + Z[i] < n and s1[Z[i]] == s1[i+Z[i]]: Z[i] += 1 if i + Z[i] > r: l, r = i, i + Z[i] s='' last = float('-inf') ans = '' for e, i in enumerate(s2): if i == 'T': k = e-last if k < n and k + Z[k] != n: return '-1' ans = ans[:e]+s1 last = e elif len(ans) == e: ans += 'A' return ans + 'A' * ((n+m-1)-len(ans)) T=int(input()) for _ in range(T): s1 = input() s2 = input() result = solve(s1, s2) print(result) String generation ✅✅✅✅✅💯

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