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MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 13 241 obunachidan iborat bo'lib, Taʼlim toifasida 15 362-o'rinni va Hindiston mintaqasida 32 092-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 13 241 obunachiga ega bo‘ldi.

18 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -138 ga, so‘nggi 24 soatda esa -2 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 2.93% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.11% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 388 marta ko‘riladi; birinchi sutkada odatda 147 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent placement, gaurntee, suree, capgemini, infosy kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

Yuqori yangilanish chastotasi (oxirgi ma’lumot 19 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

13 241
Obunachilar
-224 soatlar
-457 kunlar
-13830 kunlar
Postlar arxiv
Block Extraction C++ TCS CodeVita Zone 2 #include <bits/stdc++.h> using namespace std; int main() { int x, y; cin >> x >> y; vector<vector<int>> z(x, vector<int>(y)); for (int i = 0; i < x; ++i) { for (int j = 0; j < y; ++j) { cin >> z[i][j]; } } int w; cin >> w; map<int, vector<pair<int, int>>> a; set<int> b; for (int i = 0; i < x; ++i) { for (int j = 0; j < y; ++j) { int c = z[i][j]; a[c].emplace_back(i, j); b.insert(c); } } set<int> d; for (int i = 0; i < x; ++i) { vector<int> e; for (int j = 0; j < y; ++j) { if (z[i][j] == w) { e.push_back(j); } } if (!e.empty()) { int f = *max_element(e.begin(), e.end()); for (int j = f + 1; j < y; ++j) { int g = z[i][j]; if (g != w) { d.insert(g); } } } } set<int> h = b; d.erase(w); int i = 0; for (auto j = d.begin(); j != d.end(); ++j) { if (h.find(*j) != h.end()) { h.erase(*j); i++; } } auto k = [&](const set<int>& l) -> set<int> { set<int> m; for (auto& n : l) { for (auto& [o, p] : a[n]) { if (o == x - 1) { m.insert(n); break; } } } queue<int> q; for (auto& r : m) { q.push(r); } while (!q.empty()) { int s = q.front(); q.pop(); for (auto& t : l) { if (m.find(t) != m.end()) continue; bool u = false; for (auto& [v, w] : a[t]) { if (v + 1 < x) { int x = z[v + 1][w]; if (m.find(x) != m.end()) { u = true; break; } } } if (u) { m.insert(t); q.push(t); } } } return m; }; while (true) { set<int> y = k(h); set<int> z; for (auto& aa : h) { if (y.find(aa) == y.end()) { z.insert(aa); } } if (z.empty()) break; for (auto& bb : z) { h.erase(bb); i++; } } cout << i; return 0; } Block Extraction C++ TCS CodeVita Zone 2 @codeing_are

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#include <iostream> #include <vector> #include <string> #include <climits> using namespace std; int minCostToFormString(int n, vector<pair<string, int>> &substrings, string mainString) {     int m = mainString.length();     vector<int> dp(m + 1, INT_MAX);     dp[0] = 0;     for (int i = 0; i <= m; ++i) {         if (dp[i] == INT_MAX) continue;         for (auto &sub : substrings) {             string substring = sub.first;             int cost = sub.second;             int subLen = substring.length();                  if (i + subLen <= m && mainString.substr(i, subLen) == substring) {                 dp[i + subLen] = min(dp[i + subLen], dp[i] + cost);             for (int k = 1; k < subLen; ++k) {                 if (i + k <= m && mainString.substr(i, k) == substring.substr(0, k)) {                     dp[i + k] = min(dp[i + k], dp[i] + cost);                 }             }             }              }     }     return (dp[m] == INT_MAX) ? -1 : dp[m]; } int main() {     int n;     cin >> n;     vector<pair<string, int>> substrings;     for (int i = 0; i < n; ++i) {         string substring;         int cost;         cin >> substring >> cost;         substrings.push_back({substring, cost});     }     string mainString;     cin >> mainString;     int result = minCostToFormString(n, substrings, mainString);     if (result == -1) {         cout << "Impossible" ;     } else {         cout << result ;     }     return 0; } form the string c++ code

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def placementlelo(valid_digits, fd): pd = [] for digit, valid in valid_digits.items(): diff = sum(1 for a, b in zip(fd, valid) if a != b) if diff == 0: pd.append(digit) elif diff == 1: pd.append(digit) return pd def solve(): sd = [input().strip() for _ in range(3)] fad = [input().strip() for _ in range(3)] valid_digits = {} for i in range(10): valid_digits[i] = ''.join(sd[j][i*3:(i+1)*3] for j in range(3)) faulty_number = [] for i in range(len(fad[0]) // 3): fd = ''.join(fad[j][i*3:(i+1)*3] for j in range(3)) pd = placementlelo(valid_digits, fd) if not pd: print("Invalid",end='') return faulty_number.append(pd) from itertools import product ts = 0 for possible in product(*faulty_number): ts += int(''.join(map(str, possible))) print(ts,end='') solve() Toggle challenge

def process_commands(kpr): loop_counts = [] curr_iter = [] output = [] index = 0 while index < len(kpr): command = kpr[index] if command.startswith("for"): times = int(command.split(" ")[1]) loop_counts.append(times) curr_iter.append(0) elif command == "do": pass elif command == "done": current = curr_iter.pop() + 1 max_count = loop_counts.pop() if current < max_count: loop_counts.append(max_count) curr_iter.append(current) index = find_loop_start(kpr, index) continue elif command.startswith("break"): break_at = int(command.split(" ")[1]) if curr_iter[-1] + 1 == break_at: loop_counts.pop() curr_iter.pop() index = find_loop_end(kpr, index) elif command.startswith("continue"): continue_at = int(command.split(" ")[1]) if curr_iter[-1] + 1 == continue_at: max_count = loop_counts[-1] current = curr_iter.pop() + 1 if current < max_count: curr_iter.append(current) index = find_loop_start(kpr, index) continue elif command.startswith("print"): message = command[command.index("\"") + 1:command.rindex("\"")] output.append(message) index += 1 print("\n".join(output)) def find_loop_start(kpr, ci): nested_loops = 0 for i in range(ci - 1, -1, -1): if kpr[i] == "done": nested_loops += 1 elif kpr[i] == "do": if nested_loops == 0: return i nested_loops -= 1 return 0 def find_loop_end(kpr, ci): nested_loops = 0 for i in range(ci + 1, len(kpr)): if kpr[i] == "do": nested_loops += 1 elif kpr[i] == "done": if nested_loops == 0: return i nested_loops -= 1 return len(kpr) if name == "main": n = int(input()) kpr = [input().strip() for _ in range(n)] process_commands(kpr) Loop MASTER Python done ✅✅✅

#include <iostream> #include <vector> #include <set> #include <algorithm> using namespace std; int main() { int n, m, k, days = 1, activeCount = 0; cin >> n >> m; vector<set<int>> connections(n); for (int i = 0, u, v; i < m; ++i) { cin >> u >> v; connections[u].insert(v); connections[v].insert(u); } cin >> k; vector<bool> active(n, true); activeCount = n; while (activeCount < k) { vector<bool> nextState(n, false); for (int i = 0; i < n; ++i) { int neighborCount = 0; for (int neighbor : connections[i]) { neighborCount += active[neighbor]; } if (active[i] && neighborCount == 3) { nextState[i] = true; } else if (!active[i] && neighborCount < 3) { nextState[i] = true; } } active = nextState; activeCount += count(active.begin(), active.end(), true); ++days; } cout << days; return 0; }

#include <bits/stdc++.h> using namespace std; typedef long long ll; int main() { int numLines; cin >> numLines; vector<vector<pair<int, int>>> paths(numLines); map<pair<int, int>, vector<int>> pointTracker; for (int i = 0; i < numLines; i++) { int x1, y1, x2, y2; cin >> x1 >> y1 >> x2 >> y2; int dx = x2 - x1, dy = y2 - y1; int steps = max(abs(dx), abs(dy)); int stepX = (dx == 0) ? 0 : dx / abs(dx); int stepY = (dy == 0) ? 0 : dy / abs(dy); for (int j = 0; j <= steps; j++) { int curX = x1 + stepX * j; int curY = y1 + stepY * j; paths[i].emplace_back(make_pair(curX, curY)); pointTracker[{curX, curY}].emplace_back(i); } } string lineInput; getline(cin, lineInput); getline(cin, lineInput); unordered_map<string, int> limitMap; int pos = 0, lineLength = lineInput.size(); while (pos < lineLength) { size_t delimiterPos = lineInput.find(':', pos); if (delimiterPos == string::npos) break; string key = lineInput.substr(pos, delimiterPos - pos); pos = delimiterPos + 1; size_t spacePos = lineInput.find(' ', pos); if (spacePos == string::npos) spacePos = lineLength; int value = stoi(lineInput.substr(pos, spacePos - pos)); limitMap[key] = value; pos = spacePos + 1; } string query; cin >> query; ll totalCost = 0; for (auto &entry : pointTracker) { if (entry.second.size() >= 2) { int commonSize = entry.second.size(); int minCost = INT_MAX; for (auto segId : entry.second) { auto &currentPath = paths[segId]; size_t pathLength = currentPath.size(); size_t index = find(currentPath.begin(), currentPath.end(), entry.first) - currentPath.begin(); int leftDistance = index; int rightDistance = pathLength - index - 1; int cost = (leftDistance > 0 && rightDistance > 0) ? min(leftDistance, rightDistance) : max(leftDistance, rightDistance); minCost = min(minCost, cost); } totalCost += (ll)commonSize * minCost; } } if (limitMap.find(query) != limitMap.end()) { if (totalCost >= limitMap[query]) { cout << "Yes\n"; } else { cout << "No\n"; } } else { cout << "No\n"; } int validItems = 0, totalItems = limitMap.size(); for (auto &entry : limitMap) { if (totalCost >= entry.second) { validItems++; } } double successRate = (double)validItems / totalItems; cout << fixed << setprecision(2) << successRate; return 0; }

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string s; cin >> s; int n = s.length(), res = 0; vector v(n); for (int i = 0; i < n; ++i) cin >> v[i]; int lw = s[0] - '0', lwv = v[0]; for (int i = 1; i < n; ++i) { if (s[i] - '0' == lw) { res += min(lwv, v[i]); lwv = max(lwv, v[i]); } else { lw = s[i] - '0'; lwv = v[i]; } } cout << res; return 0; } Alternative string🔥🔥🔥🔥

import java.util.*; public class RitikaTask { private static int[] canFormWithDeletions(String sub, String mainStr, int maxDeletions) { int i = 0, j = 0, deletionsUsed = 0; while (i < mainStr.length() && j < sub.length()) { if (mainStr.charAt(i) == sub.charAt(j)) { i++; j++; } else { deletionsUsed++; if (deletionsUsed > maxDeletions) { return new int[] {i, deletionsUsed}; } i++; } } return new int[] {i, deletionsUsed}; } private static boolean canMatchCharacter(char c, List<String> substrings) { for (String sub : substrings) { if (sub.indexOf(c) >= 0) { return true; } } return false; } public static String solveRitikaTask(List<String> substrings, String mainStr, int k) { int n = mainStr.length(); int deletionsUsed = 0; StringBuilder formedString = new StringBuilder(); boolean isAnyMatch = false; for (int i = 0; i < n; i++) { if (!canMatchCharacter(mainStr.charAt(i), substrings)) { return "Impossible"; } } for (int i = 0; i < n;) { boolean matched = false; for (String sub : substrings) { int[] result = canFormWithDeletions(sub, mainStr.substring(i), k - deletionsUsed); int newIndex = result[0]; int usedDeletions = result[1]; if (newIndex > 0) { matched = true; isAnyMatch = true; formedString.append(mainStr.substring(i, i + newIndex)); i += newIndex; deletionsUsed += usedDeletions; break; } } if (!matched) { break; } } if (formedString.length() == n) { if (deletionsUsed <= k) { return "Possible"; } else { return formedString.toString().trim(); } } else if (isAnyMatch) { return "Nothing"; } else if (deletionsUsed > k) { return formedString.toString().trim(); } else { return formedString.toString().trim(); } } public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int N = scanner.nextInt(); scanner.nextLine(); List<String> substrings = new ArrayList<>(); for (int i = 0; i < N; i++) { substrings.add(scanner.nextLine()); } String mainStr = scanner.nextLine(); int K = scanner.nextInt(); String result = solveRitikaTask(substrings, mainStr, K); System.out.print(result); scanner.close(); } } Help ritika code with all tets caes passed 🔥🔥🔥🔥🔥 @Codeing_are

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All code with all tets caes passed 🔥🥳🥳🥳🥳