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Ko'proq ko'rsatish

Hindiston32 011 Taʼlim15 345...

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MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 13 236 obunachidan iborat bo'lib, Taʼlim toifasida 15 345-o'rinni va Hindiston mintaqasida 32 011-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 13 236 obunachiga ega bo‘ldi.

19 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -137 ga, so‘nggi 24 soatda esa -4 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

Tasdiqlash holati: Tasdiqlanmagan
Jalb etish (ER): Auditoriya o‘rtacha 2.81% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.07% ini tashkil etuvchi reaksiyalarni to‘playdi.
Post qamrovi: Har bir post o‘rtacha 372 marta ko‘riladi; birinchi sutkada odatda 142 ta ko‘rish yig‘iladi.
Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
Tematik yo‘nalishlar: Kontent placement, gaurntee, suree, capgemini, infosy kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 20 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

13 236

Obunachilar

-424 soatlar

-407 kunlar

-13730 kunlar

372

Post ko'rishlar

~ 14224 soatlar

~ 19248 soatlar

2.81%

Muloqot nisbati

~ 3

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const int MOD=1e9+7; int solve(int n, int k, int t) { vector<vector<int>> ways(k + 1, vector<int>(t + 1, 0)), temp; for (int face = 1; face <= k; face++) { if (face <= t) { ways[face][face] = 1; } } for (int step = 2; step <= n; step++) { temp.assign(k + 1, vector<int>(t + 1, 0)); for (int prev = 1; prev <= k; prev++) { for (int total = 1; total <= t; total++) { if (ways[prev][total] == 0) { continue; } if (prev - 1 >= 1 && total + prev - 1 <= t) { temp[prev - 1][total + prev - 1] = (temp[prev - 1][total + prev - 1] + ways[prev][total]) % MOD; } if (prev + 1 <= k && total + prev + 1 <= t) { temp[prev + 1][total + prev + 1] = (temp[prev + 1][total + prev + 1] + ways[prev][total]) % MOD; } } } ways = temp; } long long result = 0; for (int value = 1; value <= k; value++) { result = (result + ways[value][t]) % MOD; } return result; }. https://whatsapp.com/channel/0029VaicY2a65yD2YNehWP2j (Dice and roll Target)

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collections import defaultdict def solve(n: int, a: list) -> int: pos = defaultdict(list) for i in range(n): pos[a[i]].append(i) ml = float('inf') count = 0 for arr in pos.values(): for i in range(1, len(arr)): length = arr[i] - arr[i - 1] + 1 if length < ml: ml = length count = 1 elif length == ml: count += 1 if ml == float('inf'): return -1 return count Majority window Follow channel https://whatsapp.com/channel/0029VaicY2a65yD2YNehWP2j

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def solve(n, k, x, arr): gains = [] total = sum(arr) for num in arr: gain = (num ^ x) - num if gain > 0: gains.append(gain) gains.sort(reverse=True) for i in range(min(k, len(gains))): total += gains[i] return total n = int(input()) k = int(input()) x = int(input()) arr = [] for _ in range(n): arr.append(int(input())) print(solve(n, k, x, arr))