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LeetCode, GeeksForGeeks Problem of the day solution

LeetCode, GeeksForGeeks Problem of the day solution

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Complete daily challenges from LeetCode, GeeksForGeeks and redeem their rewards Channel link : https://t.me/leetcode_gfg_potd

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class Solution { public: vector frequencySort(vector& nums) { unordered_map mpp;//element-->frequency int n = nums.size(); for(int i=0;i> newMap; for(auto x:mpp){ newMap.push_back({x.first,x.second}); } sort(newMap.begin(),newMap.end(),[](pair &a,pair &b){ if(a.second == b.second){ return a.first>b.first; } else{ return a.second < b.second; } }); vector ans; for(auto x:newMap){ for(int i=1;i<=x.second;i++){ ans.push_back(x.first); } } return ans; } };

LeetCode | Daily challenge :

class Solution { public: // Function to return a list of integers denoting the node // values of both the BST in a sorted order. void solve(Node *root, vector &ans) { if (!root) return; solve(root->left, ans); ans.push_back(root->data); solve(root->right, ans); } vector merge(Node *root1, Node *root2) { vector ans; solve(root1, ans); solve(root2, ans); sort(ans.begin(), ans.end()); return ans; } };

GFG | Problem of the day :

class Solution { public: vector sortPeople(vector& names, vector& heights) { unordered_map map; for(int i=0;i

LeetCode | Daily challenge :

class NodeValue{ public: int minVal, maxVal, maxSize; NodeValue(int minVal, int maxVal, int maxSize){ this->minVal = minVal; this->maxVal = maxVal; this->maxSize = maxSize; } }; class Solution{ public: /*You are required to complete this method */ // Return the size of the largest sub-tree which is also a BST NodeValue largestBSTHelper(Node* root){ if(root==NULL){ return NodeValue(INT_MAX, INT_MIN, 0); } NodeValue leftST = largestBSTHelper(root->left); NodeValue rightST = largestBSTHelper(root->right); if(root->data > leftST.maxVal && root->data < rightST.minVal){ return NodeValue(min(root->data, leftST.minVal), max(root->data, rightST.maxVal), 1+leftST.maxSize+rightST.maxSize); } return NodeValue(INT_MIN, INT_MAX, max(leftST.maxSize, rightST.maxSize)); } int largestBst(Node *root) { return largestBSTHelper(root).maxSize; } };

GFG | Problem of the day :

class Solution { public: void top_sort(unordered_map> &adj,vector &res,int &k) { queue q; vector indegree(k+1,0); for(auto x:adj) { for(auto y:x.second) { indegree[y]++; } } for(int i=1;i<=k;i++) { if(indegree[i]==0) { q.push(i); } } while(!q.empty()) { int front=q.front(); q.pop(); res.push_back(front); for(auto x:adj[front]) { indegree[x]--; if(indegree[x]==0) { q.push(x); } } } } vector> buildMatrix(int k, vector>& rowConditions, vector>& colConditions) { int i,m=rowConditions.size(),n=colConditions.size(); unordered_map> adj1; unordered_map> adj2; for(i=0;i x; vector y; top_sort(adj1,x,k); top_sort(adj2,y,k); vector> ans(k,vector (k,0)); if(x.size()!=k || y.size()!=k) { return {}; } i=0; unordered_map hash; for(auto p:x) { hash[p]=i++; } i=0; for(auto p:y) { ans[hash[p]][i]=p; i++; } return ans; } };

LeetCode | Daily challenge :

class Solution { public: int mod = 1e9+7; long long int findMaxProduct(vector& arr) { long long int p=1; long long int zerocount = 0, negativecount=0; long long int maxin = INT_MIN; if(arr.size()==1) return arr[0]; for(int i=0;i

GFG | Problem of the day :

class Solution { public: vector> restoreMatrix(vector& rowSum, vector& colSum) { int m=rowSum.size(),n=colSum.size(),i=0,j=0; vector>res(m,vector(n,0)); while(i

LeetCode | Daily challenge :

class Solution { public: void inorder(Node* root){ if(root==NULL){ return; } inorder(root->left); cout<data<<" "; inorder(root->right); } Node *RemoveHalfNodes(Node *root) { // code here if(root==NULL){ return NULL; } root->left=RemoveHalfNodes(root->left); root->right=RemoveHalfNodes(root->right); if(root->left==NULL&&root->right!=NULL){ Node* newRoot=root->right; delete root; return newRoot; } if(root->right==NULL&&root->left!=NULL){ Node* newRoot=root->left; delete root; return newRoot; } return root; } };

GFG | Problem of the day :

class Solution { public: vector luckyNumbers (vector>& matrix) { int rows = matrix.size(); int cols = matrix[0].size(); vector row_minimums(rows, INT_MAX); vector col_maximums(cols, 0); for (int row_ind = 0; row_ind < rows; ++row_ind) { for (int col_ind = 0; col_ind < cols; ++col_ind) { int el = matrix[row_ind][col_ind]; row_minimums[row_ind] = min(row_minimums[row_ind], el); col_maximums[col_ind] = max(col_maximums[col_ind], el); } } for (int row_ind = 0; row_ind < rows; ++row_ind) { for (int col_ind = 0; col_ind < cols; ++col_ind) { int el = matrix[row_ind][col_ind]; if (el == row_minimums[row_ind] && el == col_maximums[col_ind]) { return {el}; } } } return {}; } };

LeetCode | Daily challenge :

class Solution{ public: vector constructLowerArray(vectorarr) { // code here vector ans; int n= arr.size(); vector temp; for(int i=0;i

GFG | Problem of the day :