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Kth Palindrome Code Infosys SP Exam C++ #include <iostream> #include <vector> using namespace std; const int MOD = 1000000007; int v(int k) {     return (1 << k) - 1; } bool p(int n) {     while (n % 2 == 0) n /= 2;     return n == 1; } long long s(int n) {     vector<long long> dp(n + 1, 0);     dp[0] = 1;         for (int i = 1; i <= n; ++i) {         for (int k = 1; v(k) <= i; ++k) {             int l = v(k - 1) - 1;             if (i >= 2 * l + 1) {                 dp[i] = (dp[i] + dp[i - (2 * l + 1)] * k) % MOD;             }         }     }         return dp[n]; } int main() {     int n;     cin >> n;         cout << s(n) << endl;         return 0; } Kth Palindrome Code Infosys SP Exam C++