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𝘿𝙄𝙕𝘼𝙍𝘿 𝘿𝙀𝙀𝙋

𝘿𝙄𝙕𝘼𝙍𝘿 𝘿𝙀𝙀𝙋

Kanalga Telegram’da o‘tish

All information shared here is for educational purposes only. Personal - @dizarddeep 💼 Powered by Dizard

Ko'proq ko'rsatish

📈 Telegram kanali 𝘿𝙄𝙕𝘼𝙍𝘿 𝘿𝙀𝙀𝙋 analitikasi

𝘿𝙄𝙕𝘼𝙍𝘿 𝘿𝙀𝙀𝙋 (@dizard_deepp) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 13 119 obunachidan iborat bo'lib, Taʼlim toifasida 15 256-o'rinni va Hindiston mintaqasida 31 230-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 13 119 obunachiga ega bo‘ldi.

15 Iyul, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 0 ga, so‘nggi 24 soatda esa 0 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 0% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining N/A% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 0 marta ko‘riladi; birinchi sutkada odatda 0 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“All information shared here is for educational purposes only. Personal - @dizarddeep 💼 Powered by Dizard”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 16 Iyul, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

13 119
Obunachilar
Ma'lumot yo'q24 soatlar
Ma'lumot yo'q7 kun
Ma'lumot yo'q30 kun
Postlar arxiv
⚜⚜ *त्रिकोणमिति : महत्वपूर्ण सूत्र* ⚜⚜
+1
⚜⚜ *त्रिकोणमिति : महत्वपूर्ण सूत्र* ⚜⚜

⚜⚜ *त्रिकोणमिति : महत्वपूर्ण सूत्र* ⚜⚜

⚜⚜ *त्रिकोणमिति : महत्वपूर्ण सूत्र* ⚜⚜ 🍎 *योग सूत्र* ➭ *Sin(A+B) = SinACosB+CosASinB* ➭ *Sin(A-B) = SinACosB-CosASinB* ➭ *Cos(A+B) = CosACosB-SinASinB* ➭ *Cos(A-B) = CosACosB+SinASinB* 🍏 *अन्तर सूत्र* ➭ *tan(A+B) = tanA+tanB/1-tanAtanB* ➭ *tan(A-B) = tanA-tanB/1+tanAtanB* 🍎 *C-D सूत्र* ➭ *SinC+SinD = 2Sin(C+D/2) Cos(C-D/2)* ➭ *SinC-SinD = 2Cos(C+D/2) Sin(C-D/2)* ➭ *CosC+CosD = 2Cos(C+D/2) Cos(C-D/2)* ➭ *CosC-CosD = 2Sin(C+D/2) Sin(D-C/2)* ➭ *CosC-CosD = -2Sin(C+D/2) Sin(C-D/2)* 🍏 *रूपांतरण सूत्र* ➛ *2SinACosB = Sin(A+B)+Sin(A-B)* ➛ *2CosASinB = Sin(A+B)-Sin(A-B)* ➛ *2CosACosB = Cos(A+B)+Cos(A-B)* ➛ *2SinASinB = Cos(A-B)-Cos(A+B)* 🍎 *द्विक कोण सूत्र* ➛ *Sin2A = 2SinACosA* ➛ *Cos2A = Cos²A-Sin²A = 2Cos²-1 = 1-2Sin²A* ➛ *tan2A = 2tanA/1-tan²A* ➛ *Sin2A = 2tanA/1+tan²A* ➛ **Cos2A = 1-tan²A/1+tan²A* 🍏 *विशिष्ट सूत्र* ➛ *Sin(A+B)Sin(A-B) = Sin²A-Sin²B*                                  = *Cos²B-Cos²A* ➛ *Cos(A+B)Cos(A-B) = *Cos²A-Sin²B = Cos²B-Sin²A* 🍎 *त्रिक कोण सूत्र* ➛ *Sin3A = 3SinA-4Sin³A* ➛ *Cos3A = 4Cos³A-3CosA* ➛ *tan3A = 3tanA-tan³A/1-3tan²A* 🍏 *महत्वपूर्ण सर्वसमिकाएं* ➛ *Sin²θ+Cos²θ = 1* ➭ *Sin²θ = 1-Cos²θ* ➭ *Cos²θ = 1-Sin²θ* ➛ *1+tan²θ = Sec²θ* ➭ Sec²θ-tan²θ = 1* ➭ tan²θ = Sec²θ-1* ➛ *1+Cot²θ = Cosec²θ* ➭ *Cosec²θ-Cot²θ = 1* ➭ Cot²θ = Cosec²θ-1 @Class_11th_notes_by_KK #SHARE_WITH_YOUR_FRIENDS

⚜⚜ *त्रिकोणमिति : महत्वपूर्ण सूत्र* ⚜⚜ 🍎 *योग सूत्र* ➭ *Sin(A+B) = SinACosB+CosASinB* ➭ *Sin(A-B) = SinACosB-CosASinB* ➭ *Cos(A+B) = CosACosB-SinASinB* ➭ *Cos(A-B) = CosACosB+SinASinB* 🍏 *अन्तर सूत्र* ➭ *tan(A+B) = tanA+tanB/1-tanAtanB* ➭ *tan(A-B) = tanA-tanB/1+tanAtanB* 🍎 *C-D सूत्र* ➭ *SinC+SinD = 2Sin(C+D/2) Cos(C-D/2)* ➭ *SinC-SinD = 2Cos(C+D/2) Sin(C-D/2)* ➭ *CosC+CosD = 2Cos(C+D/2) Cos(C-D/2)* ➭ *CosC-CosD = 2Sin(C+D/2) Sin(D-C/2)* ➭ *CosC-CosD = -2Sin(C+D/2) Sin(C-D/2)* 🍏 *रूपांतरण सूत्र* ➛ *2SinACosB = Sin(A+B)+Sin(A-B)* ➛ *2CosASinB = Sin(A+B)-Sin(A-B)* ➛ *2CosACosB = Cos(A+B)+Cos(A-B)* ➛ *2SinASinB = Cos(A-B)-Cos(A+B)* 🍎 *द्विक कोण सूत्र* ➛ *Sin2A = 2SinACosA* ➛ *Cos2A = Cos²A-Sin²A = 2Cos²-1 = 1-2Sin²A* ➛ *tan2A = 2tanA/1-tan²A* ➛ *Sin2A = 2tanA/1+tan²A* ➛ **Cos2A = 1-tan²A/1+tan²A* 🍏 *विशिष्ट सूत्र* ➛ *Sin(A+B)Sin(A-B) = Sin²A-Sin²B*                                  = *Cos²B-Cos²A* ➛ *Cos(A+B)Cos(A-B) = *Cos²A-Sin²B = Cos²B-Sin²A* 🍎 *त्रिक कोण सूत्र* ➛ *Sin3A = 3SinA-4Sin³A* ➛ *Cos3A = 4Cos³A-3CosA* ➛ *tan3A = 3tanA-tan³A/1-3tan²A* 🍏 *महत्वपूर्ण सर्वसमिकाएं* ➛ *Sin²θ+Cos²θ = 1* ➭ *Sin²θ = 1-Cos²θ* ➭ *Cos²θ = 1-Sin²θ* ➛ *1+tan²θ = Sec²θ* ➭ Sec²θ-tan²θ = 1* ➭ tan²θ = Sec²θ-1* ➛ *1+Cot²θ = Cosec²θ* ➭ *Cosec²θ-Cot²θ = 1* ➭ Cot²θ = Cosec²θ-1 @Class_11th_notes_by_KK #SHARE_WITH_YOUR_FRIENDS

𝙝𝙩𝙩𝙥𝙨://𝙬𝙝𝙖𝙩𝙨𝙖𝙥𝙥.𝙘𝙤𝙢/𝙘𝙝𝙖𝙣𝙣𝙚𝙡/0029𝙑𝙖𝘼𝙐57𝙙𝙁1𝙔𝙡𝙋𝙟1𝙮88𝙆2𝘽 𝙟𝙤𝙞𝙣 𝙬𝙝𝙖𝙩𝙨𝙖𝙖𝙥 𝙘𝙝𝙖𝙣𝙣𝙖𝙡

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