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IBPS CLERK PRE 2022 held on 03.09.2022 Mark up price of an item is 60% more than Cost Price. Selling price of an item is Rs 2016 more than Cost price. If he allows a discount of 20% on M.P. Find the Cost price of an item.

#Happy_Ganesh_Chaturthi ❤️❤️❤️ वक्रतुण्ड महाकाय सूर्यकोटि समप्रभ। निर्विघ्नं कुरु मे देव सर्वकार्येषु सर्वदा॥ May Lord Ganesha keep enlightening our lives and always bless us with love and success. Happy Ganesh Chaturthi to all members Regards ~ Gk +imp sub pdfs [ɴɪʜᴀʀ]❤️ team

📚 Top 100 Miscellaneous Quant Questions for Banking Exams

📗Top 100 Arithmetic Questions for Banking Exams

Memory based Quant Question (IBPS CLERK 12th / 18th / 19th December❄ 2021) 1).In a rectangle, the ratio of length and breadth is 3 : 2 and its perimeter is 240 cm, then what the area of the rectangle? 🔹️ Solution 2) A train crosses a pole in 36 seconds and a platform in 52 seconds. If the speed of the train is 54 km/hr, then what is the length of the platform? Solution 3) An article is sold for Rs. 480 at 20% loss. If this article was sold at 12.5%profit, what would have been its sellingprice? Solution 4) N worker can complete a piece of work in 50 days. When 5 more workers joined, then the work got completed in 40 days, then what is the value of N? Solution 5) A and B started a business in partnership by investing the capital of Rs. 35000 and Rs. 40000 respectively. After six months, C also joined them with some capital. If at the end of the year, the profit share of C is Rs. 8000 out of the total profit of Rs. 23000, then find the amount invested by C? Solution 6) Two years ago, Jane’s age was equal to four times the Duo’s age. Five years hence, Jane’s age will be equal to three times the Duo’s age. Find the present age of Jane. Solution 7) Neha and Chaman cover a distance of D km at the speed of 10km/h and 8 km/h respectively. If Chaman takes 30 minutes more than Neha to cover that distance, find the value of 2D. Solution 8) An amount of Rs. 1520 is divided among A, B and C, such that A gets 1/5 of what B gets and B gets 3/4of what C gets. Find the share of C. Solution 9) Perimeter of a rectangle is 72 cm and it is equal to the circumference of a semi-circle, whose radius is equal to the length of the rectangle.What is the breadth of the rectangle? Solution 10) The perimeter of a square is 52 cm less than the circumference of a circle whose radius is 1 cm more than the side of the square, then what is the area of the circle? Solution 11) A man gives 40% of his salary to his daughter. He gives two third of the remaining salary to his son. If he gives the remaining salary to his wife, which is Rs. 10000, then what is the total amount he gave to his son and daughter? Solution 12) Ratio of present ages of father and son is 7:3. After 4 years the age of father will be 2.5 times of the present age of son. Find the sum of ages of father and son after 2 years. Solution 13) Simple interest on Rs. 8750 at the rate of 20% per annum for 3 years is 2.5 times of the simple interest on Rs. x at the rate of 10% per annum for 2 years, then what is the value of x? Solution 14 ) The speed of a train, which crosses a pole in 15 seconds, is 90 km/hr. What will be the length of a platform which the train will cross in 30 seconds with the same speed? Solution 15) A can do a piece of work in 10 hours and B can do the same work in 15 hours. A and B started the work together and after 3 hours B left the work. After 1 hour A also left the work, then in how many hours will B alone complete the remaining work? Solution #ibpsclerkquant2021 #memorybased

Lcm (30) A=30/10= 3 B = 30/15= 2 5×3+ 3×1 + 2t = 30 18+2t= 30 t=6hour

90×5/18 = 25m/s 25 = lt/15 Lt = 375 25 = 375+lp / 30 750-375 = lp 375m

8750 ×20×3/100 = 5/2 ( X× 10 ×2)/ 100 X= 10,500

F =7x S =3x 7x+4 = 5/2(3x) 14x+8 = 15x x=8 F+S = 10x+4=84

Let the salary of the man = 100x, then A/Q 60x – 60x 2/3 = 10000 ⇒ 20x = 10000 Hence, the answer = 100x – 20x = 80x = 4 × 20x = Rs. 40,000.

Side = a Also r =a+1 4a + 52 = 44/7 r 28a+364 = 44a+44 16a = 320 a=20 r=21 Area of circle = 22/7 × 21 ×21 = 22×3×21=1386

L=R 2(R+ B)= pi R + 2R 2R + B = piR + 2R B= 11R/7 R=7B/11 2(R+B)=72 R+ B=36 7B+11B= 36×11 B=22

Let 2 years ago D age be x So J age, 2 years ago = 4x A/Q 4x + 7 = 3(x + 7) 4x – 3x = 21 – 7 x = 14 Present age of J= 4x + 2 = 14 × 4 + 2 = 58 years

Neha : chaman S 10 : 8 S 5 : 4 T 4 : 5 1----30min or 1/2hr Distance = 4×1/2 ×10= 20km 2D = 40km

Let C be x. Then, amount received by B = 3/4x A = 1/5 × 3/4x = 3/20x Now, x +3/4x + 3/20x = 1520 x = 800

35000 × 12 : 40000 × 12 : X × 6 = 70000 : 80000 : X So X/(70000 + 80000 + X)= 8/23 23X = 8X + 150000 × 8 15X = 150000 × 8 X = 80000

N × 50 = (N + 5) × 40 ⇒ 5N = 4N + 20 ⇒ N = 20

80% =480 112.5% = ?? Ans = 675

St = 54×5/18= 15m/s St = lt/36 Lt = 540 St = lt+lp/52 Lp = 52×15-540= 240

Perimeter = 2(3x + 2x) 240 = 10x x = 24 area = 6x24×24 3456cm2