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GeeksForGeeks - POTD | GFG POTD Answer

GeeksForGeeks - POTD | GFG POTD Answer

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class Solution{ public: int maxSweetness(vector& arr, int N, int K) { int sum = 0; for(int i=0;i>1; int ct = K+1; int sm = 0; int i=0; while(i=mid) { ct--; sm=0; } i++; } if(ct<=0) { l = mid+1; ans = max(ans,mid); } else{ h = mid-1; } } return ans; } };

1st May : C++ Solution ☝🏼

class Solution{ public: set track; //do dfs and create the preorder string from the root void dfs(Node *root, string &s) { if (!root) return; s += to_string(root->data) + ","; for (int i = 0; i < root->children.size(); i++) { if (root->children[i] != NULL) { dfs(root->children[i], s); } } } void helper(Node *root, set &ans) { if (!root) return; //do bfs queue q; q.push(root); while (!q.empty()) { int size = q.size(); //for every node create dfs string and check whether already covered while (size--) { Node* node = q.front(); string preorder = ""; dfs(node, preorder); //if subtree is there previously add to ans if (track.find(preorder) != track.end()) { ans.insert(preorder); } else { //if subtee is not there then insert to track set track.insert(preorder); } q.pop(); for (int i = 0; i < node->children.size(); i++) { if (node->children[i] != NULL) { q.push(node->children[i]); } } } } } int duplicateSubtreeNaryTree(Node *root) { set ans; helper(root, ans); //ans is size of ans set return ans.size(); } };

Redeemed My 1st GFG Reward !!🎁❤️ Keep Solving Daily Challenge‼️ Keep Following GFG POTD ❤️
Redeemed My 1st GFG Reward !!🎁❤️ Keep Solving Daily Challenge‼️ Keep Following GFG POTD ❤️

30th April : C++ Solution ☝🏼

class Solution{ public: int powerfullInteger(int n,vector> &in,int k){ int mx=0; for(int i=0;iv(mx+2,0); for(int i=0;i=k)ans=i; } return ans; } };

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29th April : C++ Solution ☝🏼

class Solution{ public: long long findNumber(long long N){ long long ans = 0; while(N > 0) { int rank = N%5; N /= 5; if(rank == 0) { rank = 5; N--; } ans = ans*10 + (2*rank - 1); } return reverse(ans); } long long reverse(long long n) { long long ans = 0; while(n > 0) { ans = ans*10 + n%10; n /= 10; } return ans; } };

28th April : C++ Solution ☝🏼

class Solution{ public: vector> chefAndWells(int n,int m,vector> &c){ vector> ans(n,vector (m,0)); vector> vis(n,vector (m,0)); queue> q; for(int i=0;i temp=q.front(); q.pop(); for(int k=0;k<4;k++){ int nr = temp.first+dr[k]; int nc = temp.second+dc[k]; if(nr>=0 && nc>=0 && nr

27th April : C++ Solution ☝🏼

class Solution{ public: vector easyTask(int n,string s,int q,vector> &queries){ vector ans; for(const auto & query : queries){ if(query[0] == "1"){ int ind = stoi(query[1]); s[ind] = query[2][0]; } else if(query[0] == "2"){ int arr[26] = {0}; int left = stoi(query[1]); int right = stoi(query[2]); int k = stoi(query[3]); for(int i=left; i<=right; i++){ arr[s[i]-'a'] += 1; } for(int i=25; i>=0; i--){ k -= arr[i]; if(k <= 0){ ans.push_back('a'+i); break; } } } } return ans; } };

26th April : C++ Solution ☝🏼

class Solution{ public: bool is_possible_to_get_seats(int n, int m, vector& seats){ int i=0,j=1,prev=-1; if(n == 0) return true; if(n > m) return false; int k = n; while(k > 0 and j < m){ if(prev != 1 and seats[i] == 0 and seats[j] == 0) { k--;prev = seats[j];seats[i] = 1;i=i+2;j=j+2; } else { prev = seats[i];i++,j++; } } if(k != 0 and seats[m-2] == 0 and seats[m-1] == 0){ k--; seats[m-1]=1; } if(k != 0) return false; return true; } };

25th April : C++ Solution ☝🏼

class Solution{ public: int mod; vector mp; Solution(){ mod=1e9+7; mp.resize(31); vectorprime={2,3,5,7,11,13,17,19,23,29}; for(int i=2; i<=30; ++i){ if(0 == i%4 0 == i%9 25 == i) continue; int mask=0; for(int j=0; j<10; ++j){ if(0 ==i%prime[j]) mask |= 1<>=1; } return ans; } int goodSubsets(vector &arr, int n){ int one=0; vector dp(1024), cnt(31); dp[0] =1; for(int i: arr){ if(i == 1) one++; else if(mp[i]!=0) cnt[i]++; } for(int i=0; i<31; ++i){ if(cnt[i] == 0) continue; for(int j=0; j<1024; ++j){ if(0 != (j &mp[i]) ) continue; dp[j | mp[i]] = (int) ((dp[j | mp[i]] + dp[j] * (long)cnt[i]) % mod); } } long ans=0; for(int i:dp) ans = (ans+i) % mod; ans--; if(one!=0) ans=ans*pow(one)%mod; return (int)ans; } };

24th April : C++ Solution ☝🏼

class Solution { public: vector<int> nearestSmallerTower(vector<int> a) { int i, n=a.size(); stack<int> st; vector<int> ans(n, -1); for(i=n-1;i>=0;i--) { while(st.size() && a[st.top()]>=a[i]) st.pop(); ans[i]=(st.size())?st.top():-1; st.push(i); } while(st.size()) st.pop(); for(i=0;i<n;i++) { while(st.size() && a[st.top()]>=a[i]) st.pop(); if(st.size()) { if(ans[i]==-1) ans[i]=st.top(); else { int index=st.top(); if((i-index)<(ans[i]-i)) ans[i]=index; else if((i-index)==(ans[i]-i)) { if(a[index]<=a[ans[i]]) ans[i]=index; } } } st.push(i); } return ans; } };

23rd April : C++ Solution ☝🏼