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Python Interviews

Python Interviews

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Join this channel to learn python for web development, data science, artificial intelligence and machine learning with quizzes, projects and amazing resources for free For collaborations: @coderfun

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Python Interviews (@pythoninterviews) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 28 760 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 4 783-o'rinni va Hindiston mintaqasida 15 157-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 28 760 obunachiga ega bo‘ldi.

08 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 59 ga, so‘nggi 24 soatda esa -11 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 0.57% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.81% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 163 marta ko‘riladi; birinchi sutkada odatda 234 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 1 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent |--, link:-, learning, sql, analytic kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
Join this channel to learn python for web development, data science, artificial intelligence and machine learning with quizzes, projects and amazing resources for free For collaborations: @coderfun

Yuqori yangilanish chastotasi (oxirgi ma’lumot 09 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

28 760
Obunachilar
-1124 soatlar
+217 kunlar
+5930 kunlar
Postlar arxiv
12. Write a program to check whether the string ends with "universe" or not . a= "Hey , Good Morning" print(a.endswith("universe")) Shell : False

11. Write a program to find string length. a = "The Universe" print(len(a)) Shell : 12

10. string slicing Ex.(1.) a= "Complete Freedom" print(a [0:15]) Shell : Complete Freedo Ex.(2.) a="The universe" print(a[1: ]) Shell : he universe # [1: ] treats as [2:12] Ex.(3.) a="The universe" print(a[ :12]) Shell : The universe # [ :12 ] treats as [0 : 12] Ex(4.) a="The universe" print(a[ :-1]) # Reason : We can start counting from last (-1,-2.......) , instead of srating from start (0,1,2,3....). [ In string]

9. If we use ', ' instead of '+' a = "Free" b = "dom" print(a,b) She'll : Free dom

8. Sum of two strings a="Free" b="dom" print(a+b) Shell : Freedom

7. Square of a number a= int(input("Enter the number :")) b= a*a print( "square of given number is :", b )

6. Average of two numbers a = int(input("Enter first number :")) b = int(input("Enter the second number : ")) c= (a+b)/2 print("Average of given numbers : ", c)

5. Use the comparision operator to check a is greater than b or not. a = int (input("Enter first number :")) b=int(input("Enter second number :")) print("a is greater than b ,it is true or false : ", (a>b) )

4. Check the type of the variable assigned using input() function a= input ("Enter something :") print(type(a))

3. Write a program to find remainder when a number is divided by 2 a = input ("Enter the number :") a = int((a)) Remainder = a%2 print("Remainder is ",Remainder)

2. write a program to add two numbers. a=input("Enter first number :") a=(int(a)) b=input("Enter second number:") b=(int(b)) print("Sum ", a+b)

1. write a python program to print the Hello universe! print("Hello universe!")