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import re def is_prime(num):     if num <= 1:         return False     if num == 2:         return True     if num % 2 == 0:         return False     for i in range(3, int(num**0.5) + 1, 2):         if num % i == 0:             return False     return True def fun(input_str):     numbers = re.findall(r'\d+', input_str)     total_sum = 0     for num_str in numbers:         num = int(num_str)         if is_prime(num) or num % 2 == 0:             total_sum += num         return total_sum print fun(raw_input())

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def count_valid_strings(N):
    MOD = 10**9 + 7
    
    T, A, N, R, U, S = range(6)
    
    dp = [[0] * 6 for _ in range(N + 1)]
    
    dp[1][T] = 1
    dp[1][N] = 1
    dp[1][S] = 1
    
    for i in range(1, N):
        dp[i + 1][A] = (dp[i][T]) % MOD
        dp[i + 1][N] = (dp[i][A]) % MOD
        dp[i + 1][R] = (dp[i][A] + dp[i][N]) % MOD
        dp[i + 1][U] = (dp[i][R]) % MOD
        dp[i + 1][S] = (dp[i][U]) % MOD
        dp[i + 1][T] = (dp[i][S]) % MOD
        dp[i + 1][A] = (dp[i + 1][A] + dp[i][S]) % MOD
        dp[i + 1][N] = (dp[i + 1][N] + dp[i][S]) % MOD
        dp[i + 1][R] = (dp[i + 1][R] + dp[i][S]) % MOD
        dp[i + 1][U] = (dp[i + 1][U] + dp[i][S]) % MOD
    
    result = sum(dp[N][c] for c in [T, A, N, R, U, S]) % MOD
    return result

Thoughtwork ✅

def count_arrays(N, K, X):     MOD = 1000000007         if N == 1:         return 1 if X == 1 else 0     a = [0] * (N + 1)     b = [0] * (N + 1)         a[1] = 1     b[1] = 0         for i in range(2, N + 1):         a[i] = (a[i - 1] * (K - 2) + b[i - 1] * (K - 1)) % MOD         b[i] = a[i - 1] % MOD         return b[N] N = int(input()) K = int(input()) X = int(input()) print(count_arrays(N, K, X)) Number Of Array code Thoughtwork exam Python3 ✅

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