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IBPS RRB PO PRELIMS EXAM 2023 πŸ…πŸŽ― ΰ€€ΰ₯ˆΰ€―ΰ€Ύΰ€°ΰ₯€ ΰ€…ΰ€­ΰ₯€ ΰ€Έΰ₯‡ MOST EXPECTED COMPLETE PAPER 2023 WITH POLL ⏰ LIVE @@@ 5 PM ⏰ 🧿#NEW_SERIES
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1. The number of candidates who did not qualified Pre – exam from Punjab is how much more or less than number of candidates who did not qualified Pre –exam from West Bengal? (A)410 (B)411 (C)408 (D)402 (E)None of these 2. The number of candidates from Haryana who did not qualify the Pre – exam is what percent of total number of candidates who did not qualify the Pre – exam from all states? (A)28.42% (B)21.47% (C)28.67% (D)24.56% (E)None of these 3. If 25% candidate from Rajasthan who qualified Pre – exam has also qualified Mains exam and 31.25% candidate from West Bengal who qualified Pre –exam has also qualified Mains exam, then the sum of candidates who did not qualified Mains exam from Rajasthan and West Bengal both are what percent more or less than number of candidates from West Bengal who applied for the examination? (A)22% more (B)34% less (C)28% more (D)35% less (E)None of these 4. Find the ratio between number of candidates from Rajasthan who qualify the Pre – exam and number of candidates from West Bengal who did not qualify the Pre – exam. (A)41 : 43 (B)34 : 35 (C)32 : 39 (D)31 : 32 (E)None of these 5. Find the average number of candidates who qualify the Pre – exam from all five states. (A)1218 (B)1348 (C)1321 (D)1431 (E)None of these

#missing #series 1. πŸπŸ—, ? , πŸ’πŸ—, πŸπŸŽπŸ—, πŸπŸπŸ—, πŸ’πŸ‘πŸ— a.21 b.25 c.29 d.33 e.43 2. 𝟏𝟎𝟏, πŸ“πŸπŸ”πŸ, ? , πŸ–πŸ•πŸŽπŸ, πŸ–πŸ—πŸπŸ”, πŸ–πŸ—πŸ“πŸ— a.7341 b.7141 c.6741 d.7541 e.7841 3. πŸ”πŸπŸπŸŽ, πŸ‘πŸŽπŸ”πŸŽ, 𝟏𝟎𝟐𝟎, ? , πŸ“πŸ, πŸ–. πŸ“ a.204 b.408 c.510 d.255 e.170 4. πŸπŸ—, πŸ’πŸ“, ? , πŸπŸ“πŸ‘, πŸ“πŸŽπŸ—, πŸ—πŸŽπŸ— a.109 b.99 c.119 d.89 e.129 5. ? , πŸπŸ–, πŸ‘πŸ”, πŸ—πŸŽ, πŸπŸ•πŸŽ, πŸ—πŸ’πŸ“ a.15 b.9 c.12 d.24 e.6 6. πŸ‘πŸ‘, πŸ”πŸ‘, ? , πŸπŸ”πŸ, πŸπŸ‘πŸ‘, πŸ‘πŸπŸ‘ a.105 b.109 c.113 d.101 e.97 7. πŸ’πŸ–, πŸ’πŸ—, πŸ“πŸ’, πŸ•πŸ—, ? , πŸ–πŸπŸ— a.104 b.204 c.304 d.154 e.184 8. πŸ”πŸ—, πŸπŸ–πŸŽ, πŸ’πŸŽπŸ, ? , πŸπŸπŸ•πŸ—, πŸπŸ•πŸ‘πŸ’ a.935 b.835 c.635 d.535 e.735 9. πŸπŸ”, πŸ‘πŸ’, ? , πŸ’πŸ”, πŸ“πŸ”, πŸ”πŸ• a.37 b.45 c.43 d.41 e.39 10.πŸπŸŽπŸ“, πŸπŸ”πŸ, πŸπŸ•πŸ‘, ? , πŸπŸ—πŸ“πŸ‘, πŸ–πŸ”πŸ•πŸ‘ a.519 b.549 c.609 d.649 e.709

#wrong #series 1. πŸ—πŸ–πŸ—, πŸπŸŽπŸŽπŸ–, πŸ—πŸ•πŸŽ, πŸπŸŽπŸ–πŸŽ, πŸ”πŸπŸ–, πŸπŸ—πŸŽπŸ– a.989 b.1008 c.970 d.2908 e.1080 2. πŸπŸ’, 𝟏𝟐, πŸπŸ’, πŸπŸ–, πŸ‘πŸ”, πŸ—πŸŽ a.14 b.90 c.18 d.36 e.24 3. πŸ“πŸ•, πŸ•πŸ”, 𝟏𝟏𝟐, πŸπŸ–πŸ”, πŸ‘πŸπŸ‘, πŸ“πŸπŸ a.57 b.112 c.512 d.313 e.186 4. πŸπŸŽπŸ—, πŸπŸ‘πŸ, πŸ‘πŸ“πŸ—, πŸ—πŸ–πŸ’, πŸπŸπŸŽπŸ—, πŸ’πŸπŸ‘πŸ’ a.109 b.984 c.2209 d.132 e.4234 5. πŸ—, 𝟏𝟎, πŸπŸ–, πŸ’πŸ‘, πŸπŸŽπŸ—, πŸπŸ‘πŸ’ a.10 b.234 c.43 d.109 e.18 6. πŸ”, πŸ–, πŸπŸ—, πŸ”πŸ‘, πŸπŸ’πŸ—, πŸπŸπŸ“πŸ a.8 b.19 c.1251 d.249 e.63 7. πŸ—πŸ’, πŸ—πŸ’πŸ“πŸ’, πŸπŸπŸ‘πŸπŸ”, πŸπŸπŸ•πŸ—πŸ’, πŸπŸπŸ—πŸ’πŸŽ, πŸπŸπŸŽπŸπŸ– a.11326 b.9454 c.12028 d.11940 e.94 8. πŸ–πŸ, πŸπŸπŸ—, πŸπŸ—πŸ—, πŸ‘πŸπŸŽ, πŸ’πŸ–πŸ—, πŸ•πŸπŸ a.199 b.711 c.489 d.81 e.320 9. πŸ‘πŸ, πŸπŸ”, πŸ’πŸ–, πŸπŸ’, πŸ”πŸŽ, 𝟏𝟎 a.48 b.24 c.10 d.60 e.32 10.πŸ—πŸ, πŸπŸŽπŸ—, πŸπŸ—πŸŽ, πŸ’πŸ’πŸ”, πŸπŸŽπŸ•πŸ, πŸπŸ‘πŸ”πŸ• a.446 b.2367 c.91 d.109 e.190

10.I.π’™πŸ βˆ’ πŸ‘. πŸ’π’™ + 𝟐. πŸ– = 𝟎 II.πŸπŸπ’šπŸ = πŸ‘πŸ‘πŸ•πŸ“ βˆ’ πŸ‘π’šπŸ

9. I.π’™πŸ + πŸ’πŸ”π’™ + πŸ“πŸπŸ– = 𝟎 II.π’šπŸ βˆ’ π’š βˆ’ πŸ’πŸπŸŽ = 𝟎

8. I.π’™πŸ + πŸ–βˆšπŸ‘π’™ + πŸ’πŸ“ = 𝟎 II.π’šπŸ + πŸβˆšπŸ‘π’š βˆ’ πŸ’πŸ“ = 𝟎

7. I.π’™πŸ + πŸ‘πŸπ’™ + πŸπŸ’πŸŽ = 𝟎 II.π’šπŸ βˆ’ πŸ’πŸπ’š + πŸπŸ–πŸŽ = 𝟎

6. I.πŸ–π’™πŸ + πŸπŸŽπ’™ + 𝟏𝟐 = 𝟎 II.πŸ’π’šπŸ + πŸπŸ•π’š + πŸπŸ– = 𝟎

5. I.π’™πŸ βˆ’ πŸπŸπ’™ + πŸ–πŸ“ = 𝟎 II.π’š 𝟐 + πŸ‘. πŸ”π’š + 𝟏. πŸ– = 𝟎

4. I.π’™πŸ βˆ’ πŸ‘πŸ•π’™ + πŸ‘πŸ‘πŸ” = 𝟎 II.π’šπŸ βˆ’ πŸπŸŽπ’š + πŸ”πŸ’ = 𝟎

3. I.π’™πŸ = πŸπŸπŸπŸ” II.π’š = βˆšπŸπŸ’πŸŽπŸ

2. I.π’™πŸ + πŸπŸπ’™ βˆ’ πŸπŸ“πŸ = 𝟎 II.π’šπŸ βˆ’ πŸπŸ•π’š + πŸπŸ“πŸ = 𝟎

1. I.π’™πŸ βˆ’ πŸ‘πŸ—π’™ + πŸ‘πŸ•πŸ– = 𝟎 II.π’šπŸ βˆ’ πŸπŸ’π’š + πŸπŸŽπŸ– = 𝟎

The ratio of ages of two cousins Bobby and Sunny after 5 years is 5:6. After 11 years, the age of Bobby will be 87.5% of that of Sunny’s age. Find the sum of their present age ? a.23 b.43 c.33 d.53 e.13

Average of β€œn” numbers is 40. When two numbers 83 and 67 are removed, then the average becomes 35. What is the value of β€œn” ? a.20 b.18 c.16 d.15 e.14