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AddMath Spmnetic!™⚡️

AddMath Spmnetic!™⚡️

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This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

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📈 Telegram kanali AddMath Spmnetic!™⚡️ analitikasi

AddMath Spmnetic!™⚡️ (@addmathspmnotes) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 38 070 obunachidan iborat bo'lib, Taʼlim toifasida 4 953-o'rinni va Hindiston mintaqasida 10 228-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 38 070 obunachiga ega bo‘ldi.

27 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 988 ga, so‘nggi 24 soatda esa 29 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 11.80% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 6.49% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 4 490 marta ko‘riladi; birinchi sutkada odatda 2 470 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 12 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent addmath, untuk, 629/4, math, eqn kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 28 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

38 070
Obunachilar
+2924 soatlar
+1787 kun
+98830 kun
Postlar arxiv
congrats to Aireez
congrats to Aireez

haha, a very nice question...
haha, a very nice question...

Answer
Answer

congrats to Nisha also...👍🏽👍🏽👍🏽
congrats to Nisha also...👍🏽👍🏽👍🏽

remember not all linear functions are arithemic sequences, but all arithemic sequences are linear functions..

congrats to amni madiha...

y=ax+b tu linear function Yang nj ikut pola je f(1) = 4 f(2) = 7 So 7-4=3 So .. f(3) = 7+3

guys, may I know your working for this question?

f(x) = 2x + 3, g(x) = x^2. Solve f(x) = g(x) for x.
Anonymous voting

f(x+2) = f(x) + 6, f(0) = 1. Find f(4).
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f(x+1) = f(x) + 5, f(0) = 2. What is f(3)?
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If f(x) = 2x - 1, what is f inverse of 3?
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If f(x) = ax+ b, if f(1) = 4 and f(2) = 7. Find f(3)
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lets make it a bit more harder 🙂

Given f(x) = 2x + 1 and f(a) = 13, find the value of a.
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Given f(x) = 2x - 5, find the value of x when f(x) = 9.
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photo content

Given f(x)=3x+2, find f(4).
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Mid year exam Seminar notes by TTC Education