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AddMath Spmnetic!™⚡️

AddMath Spmnetic!™⚡️

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This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

Ko'proq ko'rsatish

📈 Telegram kanali AddMath Spmnetic!™⚡️ analitikasi

AddMath Spmnetic!™⚡️ (@addmathspmnotes) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 34 116 obunachidan iborat bo'lib, Taʼlim toifasida 5 533-o'rinni va Hindiston mintaqasida 11 806-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 34 116 obunachiga ega bo‘ldi.

09 Iyul, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 413 ga, so‘nggi 24 soatda esa 27 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 13.44% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 6.74% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 4 586 marta ko‘riladi; birinchi sutkada odatda 2 299 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 7 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent addmath, untuk, 629/4, math, eqn kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

Yuqori yangilanish chastotasi (oxirgi ma’lumot 10 Iyul, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

34 116
Obunachilar
+2724 soatlar
+1607 kunlar
+41330 kunlar
Postlar arxiv
Sudah sedia guys untuk hari ni 🙂🙂. Dh cukup peluru semua. so, gudluck ye. Maaf ye kalau admin tersilap ke, marah kamu. 🥺. Admin doakan semua mendapatkan jawab dgn jayanya sekali gus mendapat results cemerlang dlm subjek addmath dan subjek2 lain😊❤️🥺... Ok, all the best 🌹 beb

BINOMIAL EXPANSIONS.pdf1.64 MB

NOTA COORDINATE GEOMETRY.pdf10.98 MB

Linear Law Bahan Pelajar.pdf2.94 MB

NOTA COORDINATE GEOMETRY.pdf10.98 MB

Linear Law Bahan Pelajar.pdf2.94 MB

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MUTU JAWAPAN SPM 2020 (1).pdf3.13 MB

Probability Distribution Answers 1) a) 53.748 & 16.694 b) 5.78% 2) a) S={(H, H), (H, T), (T, H) (T, T) } b) X=0,1,2 3)a) h=-0.8 b) 62 4)a)i) p=0.6 II) 0.3154 5) b) I) v=958.16cm³ II) 0.6284 6) a) I) 0.1587 II) p(1800-2870/900<z<3000-2870/900) b) -0.674

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Tips Untuk Score Addmaths 👇 https://vt.tiktok.com/ZSdL9qgBw/ Jangan Lupa save & share ✅

ALL THE BEST FOR ADD MATHS EXAMS SUBSS🥰❤️ 1. Believe in yourself! That's the most important part kay💪🏻 Be confident when answering questions. 2. Don't leave any questions blank. ( Even if you're not sure, try, you'll remember something) 3. Write down all your working systematically (as papers are scanned) 4. And also sleep early (get some good rest kayy so that y'all feel fresh tomorrow) FINALLY, LET'S GIVE OUR BEST BATCH 04!! WE'VE GOT THIS✨❤️

That's all for probability distribution topic! 🍁

Q6 (a) (i) Find the standard deviation. Cari sisihan piawai (ii) If 30 customers are chosen at random, find the number of cus
Q6 (a) (i) Find the standard deviation. Cari sisihan piawai (ii) If 30 customers are chosen at random, find the number of customers who have a credit card balance between RM1 800 and RM3 000, Jika 30 orang pelanggan dipilih secara rawak, cari bilangan pelanggan yang mempunyai baki hutang kad kredit di antara RM1 800 dan RM3 000. (b) It is found that 25% of the customers have a credit card balance less than RM y. Find the value of y. Didapati bahawa 25% pelanggan mempunyai jumlah baki hutang kad kredit kurang daripada RMy Cari nilai y

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