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AddMath Spmnetic!™⚡️

AddMath Spmnetic!™⚡️

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This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

Ko'proq ko'rsatish

📈 Telegram kanali AddMath Spmnetic!™⚡️ analitikasi

AddMath Spmnetic!™⚡️ (@addmathspmnotes) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 38 041 obunachidan iborat bo'lib, Taʼlim toifasida 4 957-o'rinni va Hindiston mintaqasida 10 234-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 38 041 obunachiga ega bo‘ldi.

26 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 1 022 ga, so‘nggi 24 soatda esa 31 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 12.29% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 6.25% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 4 675 marta ko‘riladi; birinchi sutkada odatda 2 376 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 11 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent addmath, untuk, 629/4, math, eqn kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 27 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

38 041
Obunachilar
+3124 soatlar
+1707 kun
+1 02230 kun
Postlar arxiv
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lol 😂😂😂

use this as your lock screen
use this as your lock screen

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From @ElTapturo Also got the same answer as well.
From @ElTapturo Also got the same answer as well.

From ~priv Congrats!
+1
From ~priv Congrats!

I didn't know it was in our textbook, pls take note about this...

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This hint involves breaking the shaded region into multiple parts, but it's not the most efficient way.

For those who need a hint.
For those who need a hint.

Silap tanda dan silap kira je yang buat korang terlepas markah. Jadi semak balik working sebelum tulis jawapan final ye..

Kenapa C) 5 salah❌ Terus ambil nilai pemalar +5 je tanpa buat full working. Nilai minimum bukan bermakna nilai pemalar! Kenapa D) 7 salah ❌ Silap tanda! Jawapan dapat −7 tapi tulis +7. Jangan terlupa semak tanda positif dan negatif! 😭

Kenapa B) −5 salah ❌ Terlupa darab 3 × 4 = 12. Ramai yang guna 10 instead of 12 masa buat complete the square

Given f(x) = 3x² − 12x + 5, what is the minimum value of f(x)?
Anonymous voting

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Red Curve: y = 2x³ - x² - 14x Blue Curve: y = 4x - x² Find the area of the shaded region.
Red Curve: y = 2x³ - x² - 14x Blue Curve: y = 4x - x² Find the area of the shaded region.

All Pulau Pinang 09 and 10 students can join...