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AddMath Spmnetic!™⚡️

AddMath Spmnetic!™⚡️

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This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

Ko'proq ko'rsatish

📈 Telegram kanali AddMath Spmnetic!™⚡️ analitikasi

AddMath Spmnetic!™⚡️ (@addmathspmnotes) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 34 203 obunachidan iborat bo'lib, Taʼlim toifasida 5 528-o'rinni va Hindiston mintaqasida 11 802-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 34 203 obunachiga ega bo‘ldi.

11 Iyul, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 507 ga, so‘nggi 24 soatda esa 46 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 14.33% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 6.72% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 4 902 marta ko‘riladi; birinchi sutkada odatda 2 299 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 7 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent addmath, untuk, 629/4, math, eqn kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

Yuqori yangilanish chastotasi (oxirgi ma’lumot 12 Iyul, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

34 203
Obunachilar
+4624 soatlar
+1837 kunlar
+50730 kunlar
Postlar arxiv
Addmath Bidang Kalkulus

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Mempermudahkan Ungkapan √20
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Solve the equation log10( 2x + 6 ) = 1 + log10 ( x – 5).
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Solve the equation 4 logx 5 + 2 logx 3 – log x 375 = 4 and give your answer correct to the four significant figures.
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4.
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Banyak latihan addmath ni ye... Tk nk pisang berbuah dua kali 😕😢

Assalamualaikum guys. Gudluck ye yang akan ambil 4 subjek killer dan subjek lain-lain bermula minggu hadapan ye. Yg lalu, biar lalu. Insya Allah manisnya akan menanti kita di hujung perjalanan nya...😊😊.

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