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class 11th physics notes

class 11th physics notes

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Ko'proq ko'rsatish
Class 9 10 notes sample papersTarmoq:Class 9 10 notes sample papersHindiston28 149Taʼlim14 076

📈 Telegram kanali class 11th physics notes analitikasi

class 11th physics notes (@class_11_physics_notes) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 14 110 obunachidan iborat bo'lib, Taʼlim toifasida 14 076-o'rinni va Hindiston mintaqasida 28 149-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 14 110 obunachiga ega bo‘ldi.

16 Sentabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -259 ga, so‘nggi 24 soatda esa -5 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 4.73% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.41% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 0 marta ko‘riladi; birinchi sutkada odatda 199 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent pdfs, 12th, physics, ravi10, ravkum0030 kabi asosiy mavzularga jamlangan.

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“Contact here at @PromoXtalk_bot for any business/ promotion related queries Contact here @MaterialXrequest_bot for requesting any Study materials”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 17 Sentabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

14 110
Obunachilar
-524 soatlar
-817 kun
-25930 kun
Postlar arxiv
class 11th physics notes
class 11th physics notes
14 110
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class 11th physics notes
class 11th physics notes
14 110
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class 11th physics notes
class 11th physics notes
14 110
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class 11th physics notes
class 11th physics notes
14 110
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class 11th physics notes
class 11th physics notes
14 110
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class 11th physics notes
class 11th physics notes
14 110
Which of the following remains constant in uniform circular motion?
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class 11th physics notes
class 11th physics notes
14 110
The time of flight of a projectile is given by:
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class 11th physics notes
class 11th physics notes
14 110
The resultant of two vectors A and B is perpendicular to vector A and its magnitude is equal to half the magnitude of vector B. The angle between A and B is:
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class 11th physics notes
class 11th physics notes
14 110
The centripetal acceleration of a particle moving in a circle of radius r with uniform speed v is:
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class 11th physics notes
class 11th physics notes
14 110
The horizontal range of a projectile is maximum when the angle of projection is:
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class 11th physics notes
class 11th physics notes
14 110
Which of the following is a scalar quantity?
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class 11th physics notes
class 11th physics notes
14 110
For a projectile, the angle between the velocity and the acceleration at the highest point is:
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class 11th physics notes
class 11th physics notes
14 110
A particle is moving in a circle with uniform speed. Its motion is:
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class 11th physics notes
class 11th physics notes
14 110
At the highest point of its trajectory, the velocity of a projectile is:
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class 11th physics notes
class 11th physics notes
14 110
The path of a projectile in the absence of air resistance is a:
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class 11th physics notes
class 11th physics notes
14 110
A train is travelling at a speed of 90 km/h. Brakes are applied so as to produce a uniform acceleration of -0.5 m/s^2. Find how far the train will go before it is brought to rest.
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class 11th physics notes
class 11th physics notes
14 110
The slope of a position-time graph gives:
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class 11th physics notes
class 11th physics notes
14 110
When can the distance covered by a body be equal to its displacement?
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class 11th physics notes
class 11th physics notes
14 110
A particle starts its motion from rest under the action of a constant force. If the distance covered in the first 10 seconds is S1 and that covered in the first 20 seconds is S2, then:
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class 11th physics notes
class 11th physics notes
14 110
A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward, followed again by 5 steps forward and 3 steps backward, and so on. Each step is 1 m long and requires 1 s. How long the drunkard takes to fall in a pit 13 m away from the start?
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