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def minOps(A, B): m = len(A) n = len(B) # This part checks whether conversion is possible or not if n != m: return -1 count = [0] * 256 for i in range(n): # count characters in A count[ord(B[i])] += 1 for i in range(n): # subtract count for every char in B count[ord(A[i])] -= 1 for i in range(256): # Check if all counts become 0 if count[i]: return -1 # This part calculates the number of operations required res = 0 i = n-1 j = n-1 while i >= 0: # if there is a mismatch, then keep incrementing # result 'res' until B[j] is not found in A[0..i] while i>= 0 and A[i] != B[j]: i -= 1 res += 1 # if A[i] and B[j] match if i >= 0: i -= 1 j -= 1 return res # Driver program A = "EACBD" B = "EABCD" print ("Minimum number of operations required is " + str(minOps(A,B))) Python Minimum number of operations required Code ✅ http://t.me/Coding_solution_0 http://t.me/Coding_solution_0 http://t.me/Coding_solution_0

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