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Firibgarlarga uchmang! Telemetrio bunday kanallarni topadi va belgilaydi 👉 Belgini ko‘rmoqchi bo‘lsangiz, obuna bo‘ling

allcoding1_official

allcoding1_official

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allcoding1_official (@allcoding1_official) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 78 453 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 628-o'rinni va Hindiston mintaqasida 3 774-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 78 453 obunachiga ega bo‘ldi.

05 Noyabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 577 ga, so‘nggi 24 soatda esa -59 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 2.00% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.65% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 573 marta ko‘riladi; birinchi sutkada odatda 507 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, dev kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 06 Noyabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

78 453
Obunachilar
-5924 soatlar
-3407 kun
-1 57730 kun
Postlar arxiv
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#include <bits/stdc++.h> using namespace std; vector<string> rows; char alphabet; string findPrecedingAlphabets() {     int r = -1, c = -1;     for (int i = 0; i < rows.size(); i++)     {         int idx = rows[i].find(alphabet);         if (idx != string::npos)         {             r = i;             c = idx;             break;         }     }     if (r == -1)         return "alphabet not found";     string a = "";     if (r > 0)         a += rows[r - 1][c];     if (c > 0)         a += rows[r][c - 1];     return a; } int main() {     int n;     cin >> n;     for (int i = 0; i < n; i++)     {         string row;         cin >> row;         rows.push_back(row);     }     cin >> alphabet;     cout << findPrecedingAlphabets() << endl;     return 0; } IBM Exam Ans Alphabets on Excel sheets code Python Telegram:- @allcoding1_official

Python 3 Telegram:- @allcoding1_official
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Python 3 Telegram:- @allcoding1_official

X++ IBM code
+1
X++ IBM code

Python Students or a school code
Python Students or a school code

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QAJ
QAJ

They can't hold their breath under water... TCS NQT 9AM EXAM ANS Telegram:- @allcoding1_official Discussion group:- @TCS_exam
They can't hold their breath under water... TCS NQT 9AM EXAM ANS Telegram:- @allcoding1_official Discussion group:- @TCS_examAns

Elon Musk TCS NQT 9AM EXAM ANS Telegram:- @allcoding1_official Discussion group:- @TCS_examAns
Elon Musk TCS NQT 9AM EXAM ANS Telegram:- @allcoding1_official Discussion group:- @TCS_examAns

D TCS NQT 9AM EXAM ANS Telegram:- @allcoding1_official Discussion group:- @TCS_examAns
D TCS NQT 9AM EXAM ANS Telegram:- @allcoding1_official Discussion group:- @TCS_examAns

China and Britain TCS NQT 9AM EXAM ANS Telegram:- @allcoding1_official Discussion group:- @TCS_examAns
China and Britain TCS NQT 9AM EXAM ANS Telegram:- @allcoding1_official Discussion group:- @TCS_examAns

1) B , 2) C
1) B , 2) C

QR
QR