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allcoding1_official

allcoding1_official

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allcoding1_official (@allcoding1_official) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 84 611 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 497-o'rinni va Hindiston mintaqasida 3 527-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 84 611 obunachiga ega bo‘ldi.

10 Iyul, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 556 ga, so‘nggi 24 soatda esa -30 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 2.01% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.85% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 701 marta ko‘riladi; birinchi sutkada odatda 723 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 1 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, dev kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 11 Iyul, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

84 611
Obunachilar
-3024 soatlar
-4257 kunlar
-1 55630 kunlar
Postlar arxiv
12. 4800 13. 20% @allcoding1

11- only I

TCS digital apitude 1)5 2)11:40 am 3)3:2 4-3:1 5-46,400 6-18 7. $150mn 8. 4,477 9- Only II 10-0.54 telegram:-@allcoding1

TCS digital apitude 1)5 2)11:40 am 3)3:2 4-3:1 5-46,400 6-18 7. $150mn 8. 4,477 9- Only II telegram:-@allcoding1

TCS digital apitude 1)5 2)11:40 am 3)3:2 4-3:1 5-46,400 6-18 7. $150mn 8. 4,477 telegram:-@allcoding1

TCS digital apitude 1)5 2)11:40 am 3)3:2 4-3:1 5-46,400 6-18 telegram:-@allcoding1

TCS digital apitude 1)5 2)11:40 am 3)3:2 4-3:1 5-46,400 telegram:-@allcoding1

5-46,400

TCS digital apitude 1)5 2)11:40 am 3)3:2 4-3:1 telegram:-@allcoding1

TCS digital apitude 1)5 2)11:40 am 3)3:2 telegram:-@allcoding1

Tcs digital answers 1- a4 b3 C2 d1 2- it was my belief 3- SR 4- Notified Potential 5- my hands are full every inch 6-capriciously 7-unobtrusive 8-edbac 9-epitaph 10- they were penerially 11- premise 12- mistification 13)it distracts Telegram:-@allcoding1

Tcs digital answers 1- a4 b3 C2 d1 2- it was my belief 3- SR 4- Notified Potential 5- my hands are full every inch 6-capriciously 7-unobtrusive 8-edbac 9-epitaph 10- they were penerially Telegram:-@allcoding1

TCS BPS Fresher Hiring Location: Across India Qualification: BSc/ BCA/ BCom/ BBA/ BBM/ BMS/ BCS/ BA/ BAF/ BBI/ BPharm/ MPharm Batch: 2020/ 2021/ 2022 Salary: Min 3.5 LPA Apply Now:- https://www.tcs.com/careers/tcs-bps-hiring Telegram:-@allcoding1

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Python (Revature) Telegram:-@allcoding1
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Python (Revature) Telegram:-@allcoding1

import math n=int(input()) a=list(map(int,input().split())) m=[x for x in a if x%2!=0] k=[math.pow(x,3) for x in m] print(*k) Find the cubes of odd numbers of an array Stream : Python 3 Telegram:-@allcoding1

#include<iostream> using namespace std; int main() { char ch; cin >> ch; if(ch >= 65 && ch <= 90) cout << “Upper”; examcell else if(ch >= 97 && ch <= 122) cout << “Lower”; else if(ch >= 48 && ch <= 57) cout << “Number”; else cout << “Symbol”; return 0; } Check if given input is uppercase or lowercase or digit ✅ Stream : C++ Telegram:-@allcoding1

Reventure exam 10AM Array Operations : Ascending Order Python Telegram :-@allcoding1
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Reventure exam 10AM Array Operations : Ascending Order Python Telegram :-@allcoding1

Python (Revature) ✅ Telegram:-@allcoding1
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Python (Revature) ✅ Telegram:-@allcoding1

Revature (Python 3)✅ Telegram:-@allcoding1
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Revature (Python 3)✅ Telegram:-@allcoding1