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allcoding1_official

allcoding1_official

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allcoding1_official (@allcoding1_official) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 79 009 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 613-o'rinni va Hindiston mintaqasida 3 828-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 79 009 obunachiga ega bo‘ldi.

25 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 654 ga, so‘nggi 24 soatda esa -52 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 1.79% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.62% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 414 marta ko‘riladi; birinchi sutkada odatda 489 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, dev kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 26 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

79 009
Obunachilar
-5224 soatlar
-3677 kun
-1 65430 kun
Postlar arxiv
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import java.util.Scanner; public class Main {     public static void main(String[] args) {         Scanner scanner = new Scanner(System.in);                 int n = scanner.nextInt();         int[] left = new int[n];         int[] right = new int[n];                 for (int i = 0; i < n; i++) {             left[i] = scanner.nextInt();             right[i] = scanner.nextInt();         }                 int sumLeft = 0;         int sumRight = 0;                 for (int i = 0; i < n; i++) {             sumLeft += left[i];             sumRight += right[i];         }                 if (sumLeft % 2 == 0 && sumRight % 2 == 0) {             System.out.println(0);             return;         }                 boolean possible = false;         for (int i = 0; i < n; i++) {             int newSumLeft = sumLeft - left[i] + right[i];             int newSumRight = sumRight - right[i] + left[i];             if (newSumLeft % 2 == 0 && newSumRight % 2 == 0) {                 possible = true;                 break;             }         }                 if (possible) {             System.out.println(1);         } else {             System.out.println(-1);         }     } }

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Count children Thoughtwork exam Python3 Telegram:-
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Prime partition
Prime partition

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