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allcoding1_official

allcoding1_official

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allcoding1_official (@allcoding1_official) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 84 536 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 499-o'rinni va Hindiston mintaqasida 3 531-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 84 536 obunachiga ega bo‘ldi.

11 Iyul, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 593 ga, so‘nggi 24 soatda esa -70 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 2.09% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.84% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 769 marta ko‘riladi; birinchi sutkada odatda 712 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 1 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, dev kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 12 Iyul, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

84 536
Obunachilar
-7024 soatlar
-4307 kunlar
-1 59330 kunlar
Postlar arxiv
Repost from allcoding1
EDOC TATA steel exam Ans Telegram - @allcoding_1 🔔Unmute this channel to never miss any updates
EDOC TATA steel exam Ans Telegram - @allcoding_1 🔔Unmute this channel to never miss any updates

Repost from allcoding1
Abcdef TATA steel exam Ans Telegram - @allcoding_1 🔔Unmute this channel to never miss any updates
Abcdef TATA steel exam Ans Telegram - @allcoding_1 🔔Unmute this channel to never miss any updates

INFOSYS, TATA STEEL EXAM ANSWERS (23/4/22) INFOSYS:- http://www.joboffersadda.com/2022/01/infosys-exam-answer.html TATA STEEL:- http://www.joboffersadda.com/2022/04/tata-steel-exam-ans.html Telegram - @allcoding1 🔔Unmute this channel to never miss any updates

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INFOSYS, TATA STEEL & ADOBE EXAM ANS Telegram - @allcoding1 🔔Unmute this channel to never miss any updates

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Gago Code python
+1
Gago Code python

a=[int(x) for x in input().split()] n=int(input()) l=[] for i in range(len(a)-1): c=0 print(a[i],a[i+1]) for j in range(2, mi
a=[int(x) for x in input().split()] n=int(input()) l=[] for i in range(len(a)-1): c=0 print(a[i],a[i+1]) for j in range(2, min(a[i], a[i+1])+1): if a[i]%j==a[i+1]%j==0: c=1 if c==0 and a[i]>a[i+1]: l.append(i) print(l[0]) Zombies Code

Accenture premium modules 1:30 Ans @allcoding_1

Accenture premium modules 1:30slot 1)system testing 2)outer join 3)while 4)sprints Telegram - @allcoding1 🔔Unmute this channel to never miss any updates

Accenture premium modules 1:30slot 1)system testing 2)outer join

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Accenture primary Modules 10am slot answers 1) private cloud 2nd protect 3)thr management configured 4)pptp 5) 6)security log 7)ipconfig 8)-r 9)hostname 10)ipconfig 11)firewall 12)security 13)authentication 14)s3 life cycle 15)on demand 16)azure logic apps 17)azure application. 18)single valued. 19)true Telegram - @allcoding1 🔔Unmute this channel to never miss any updates

Accenture primary Modules 10am slot answers 1) private cloud 2nd protect 3)thr management configured 4)pptp 5) 6)security log 7)ipconfig 8)-r 9)hostname 10)ipconfig 11)firewall 12)security 13)authentication 14)s3 life cycle 15)on demand 16)azure logic apps Telegram - @allcoding1 🔔Unmute this channel to never miss any updates