allcoding1_official

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Hindiston3 460 Texnologiyalar & Aralashmalar1 507...

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allcoding1_official (@allcoding1_official) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 85 295 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 507-o'rinni va Hindiston mintaqasida 3 460-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 85 295 obunachiga ega bo‘ldi.

28 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 494 ga, so‘nggi 24 soatda esa -77 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

Tasdiqlash holati: Tasdiqlanmagan
Jalb etish (ER): Auditoriya o‘rtacha 2.71% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.84% ini tashkil etuvchi reaksiyalarni to‘playdi.
Post qamrovi: Har bir post o‘rtacha 2 308 marta ko‘riladi; birinchi sutkada odatda 713 ta ko‘rish yig‘iladi.
Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 3 ta reaksiya keladi.
Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, dev kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 29 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

85 295

Obunachilar

-7724 soatlar

-3927 kunlar

-1 49430 kunlar

2 308

Post ko'rishlar

~ 71324 soatlar

~ 1 09648 soatlar

2.71%

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Ma'lumot yo'q

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85 295

🎯Deloitte Hiring for Analyst / Data Analysis Company Name Deloitte Position Analyst / Data Analysis Qualifications Any Graduate/ PG/ MBA Experience 0 – 4 (Years) Job Location Hyderabad, India Apply Now:- http://www.allcoding1.com Telegram:- @allcoding1_official

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#include <bits/stdc++.h> using namespace std; vector<string> rows; char alphabet; string findPrecedingAlphabets() { int r = -1, c = -1; for (int i = 0; i < rows.size(); i++) { int idx = rows[i].find(alphabet); if (idx != string::npos) { r = i; c = idx; break; } } if (r == -1) return "alphabet not found"; string a = ""; if (r > 0) a += rows[r - 1][c]; if (c > 0) a += rows[r][c - 1]; return a; } int main() { int n; cin >> n; for (int i = 0; i < n; i++) { string row; cin >> row; rows.push_back(row); } cin >> alphabet; cout << findPrecedingAlphabets() << endl; return 0; } IBM Exam Ans Alphabets on Excel sheets code Python Telegram:- @allcoding1_official

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