allcoding1_official

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Hindiston3 494 Texnologiyalar & Aralashmalar1 498...

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allcoding1_official (@allcoding1_official) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 85 085 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 498-o'rinni va Hindiston mintaqasida 3 494-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 85 085 obunachiga ega bo‘ldi.

02 Iyul, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 487 ga, so‘nggi 24 soatda esa -58 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

Tasdiqlash holati: Tasdiqlanmagan
Jalb etish (ER): Auditoriya o‘rtacha 3.08% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.80% ini tashkil etuvchi reaksiyalarni to‘playdi.
Post qamrovi: Har bir post o‘rtacha 2 619 marta ko‘riladi; birinchi sutkada odatda 684 ta ko‘rish yig‘iladi.
Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 1 ta reaksiya keladi.
Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, dev kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 03 Iyul, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

85 085

Obunachilar

-5824 soatlar

-3847 kunlar

-1 48730 kunlar

2 619

Post ko'rishlar

~ 68424 soatlar

~ 1 02948 soatlar

3.08%

Muloqot nisbati

~ 1

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🎯Thryve Digital Hiring Batch - 2020 / 21 / 22 CTC - 3.5LPA Apply Now:- https://match.myanatomy.in Telegram - @allcoding1_official

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#include <iostream> #include<bits/stdc++.h> using namespace std; int main() { int n1,n2,i,j,c; cin>>n1>>n2; int a[n1],b[n2]; set<int> s; for(i=0;i<n1;i++) { cin>>a[i]; s.insert(a[i]); } for(i=0;i<n2;i++) { cin>>b[i]; s.insert(b[i]); } vector<int> v(s.begin(),s.end()); c=s.size(); if(c%2==1) { c=c/2; cout<<v[c]; } else { n1=c/2; n2=n1-1; float q=(v[n1]+v[n2])/2.0; cout<<q; } return 0; } C++ Storeroom code Telegram - @allcoding1_official

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Python

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Two parallel code Python

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#include<stdio.h> int main() { int n,m; scanf("%d%d",&n,&m); int a[n],b[m]; int temp[m+n]; for(int i=0;i<n;i++) { scanf("%d",&a[i]); } for(int i=0;i<m;i++) { scanf("%d",&b[i]); } int x=0; for(int i=0;i<n;i++) { temp[x++]=a[i]; } for(int i=0;i<m;i++) { temp[x++]=b[i]; } for(int i=0;i<x;i++) { for(int j=i+1;j<x;j++) { if(temp[i]>temp[j]) { int t=temp[i]; temp[i]=temp[j]; temp[j]=t; } } } int count=0; for(int i=0;i<x;i++) { if(temp[i]==temp[i+1]) { for(int j=i+1;j<x-1;j++) { temp[j]=temp[j+1]; count=1; } x--; } } if(count==1) { x++; } if(x%2==0) { int mid=x/2; int mid1=x/2-1; int up=temp[mid]+temp[mid1]; float result=up/2.0; printf("%.2f",result); } else { printf("%d",temp[x/2]); } return 0; } C language Telegram:- @allcoding1_official

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Coding ANs https://instagram.com/allcoding1_official?igshid=YmMyMTA2M2Y= https://instagram.com/allcoding1_official?igshid=YmMyMTA2M2Y= Telegram:- @allcoding1_official

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