allcoding1_official

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Hindiston3 527 Texnologiyalar & Aralashmalar1 497...

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allcoding1_official (@allcoding1_official) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 84 584 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 497-o'rinni va Hindiston mintaqasida 3 527-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 84 584 obunachiga ega bo‘ldi.

10 Iyul, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 556 ga, so‘nggi 24 soatda esa -30 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

Tasdiqlash holati: Tasdiqlanmagan
Jalb etish (ER): Auditoriya o‘rtacha 2.01% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.85% ini tashkil etuvchi reaksiyalarni to‘playdi.
Post qamrovi: Har bir post o‘rtacha 1 701 marta ko‘riladi; birinchi sutkada odatda 723 ta ko‘rish yig‘iladi.
Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 1 ta reaksiya keladi.
Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, dev kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 11 Iyul, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

84 584

Obunachilar

-3024 soatlar

-4257 kunlar

-1 55630 kunlar

1 701

Post ko'rishlar

~ 72324 soatlar

~ 1 07348 soatlar

2.01%

Muloqot nisbati

~ 1

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INFOSYS EXAM ANSWERS 24/4/22 https://www.joboffersadda.com/2022/04/infosys-exam-ans.html https://www.joboffersadda.com/2022/04/infosys-exam-ans.html https://www.joboffersadda.com/2022/04/infosys-exam-ans.html Telegram:-@allcoding1

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Repost from allcoding1_official

// Java program to find the XOR of // all elements in the array class GFG { // Function to find the XOR of // all elements in the array static int xorOfArray(int arr[], int n) { // Resultant variable int xor_arr = 0; // Iterating through every element in // the array for (int i = 0; i < n; i++) { // Find XOR with the result xor_arr = xor_arr ^ arr[i]; } // Return the XOR return xor_arr; } // Driver Code public static void main (String[] args) { int arr[] = { 3, 9, 12, 13, 15 }; int n = arr.length; // allcoding1 System.out.println(xorOfArray(arr, n)); } } Prifix XOR code in Java Telegram - @allcoding1

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Repost from allcoding1_official

#include <map> #include <set> #include <list> #include <cmath> #include <ctime> #include <deque> #include <queue> #include <stack> #include <string> #include <bitset> #include <cstdio> #include <limits> #include <vector> #include <climits> #include <cstring> #include <cstdlib> #include <fstream> #include <numeric> #include <sstream> #include <iostream> #include <algorithm> #include <unordered_map> using namespace std; char B[105]; int main(){ int n; int ans=0; scanf("%d", &n); scanf("%s", B); for(int i=2; B[i]; i++){ if(B[i-2] == '0' && B[i-1] == '1' && B[i] == '0') B[i] = '1', ans++; } printf("%d", ans); return 0; } Beautiful Binary String HackerRank Solution in C++ Telegram - https://t.me/allcoding1

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