uz
Feedback
allcoding1_official

allcoding1_official

Kanalga Telegram’da o‘tish

📈 Telegram kanali allcoding1_official analitikasi

allcoding1_official (@allcoding1_official) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 85 206 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 504-o'rinni va Hindiston mintaqasida 3 459-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 85 206 obunachiga ega bo‘ldi.

29 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 500 ga, so‘nggi 24 soatda esa -66 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 2.77% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.82% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 2 362 marta ko‘riladi; birinchi sutkada odatda 697 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, dev kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 30 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

85 206
Obunachilar
-6624 soatlar
-3997 kunlar
-1 50030 kunlar
Postlar arxiv
🎯Goldman Sachs Recruitment Drive 2023 | For 2024 Summer Analyst Program Job Role:- 2024 Summer Analyst Program Qualification:- Bachelors or Masters degree Branch:- Any Specialization Batch:- 2022, 2023 Salary:- INR 6 – 9* LPA Experience:-Freshers Location:- Pan India. Apply Now:- http://www.allcoding1.com Telegram:- @allcoding1_official

🎯Zoho Bulk Hiring 2023 | For UI/UX Designers Job role :- UI/UX Designers Degree:- BE, B Tech, BA, B COM, BBA, BSC, BCA, ME, M Tech, MCA, MA, M COM, MSC, Any Graduate Branch:- Any Branches Batch:- 2016, 2017, 2018,2019, 2020, 2021, 2022, 2023 Salary:- INR 6 LPA* Experience:- Fresher Location:- Chennai, Salem, Coimbatore, Tirunelveli, and Madurai Apply Now:- http://www.allcoding1.com Telegram:- @allcoding1_official

🎯 Tech Mahindra Off Campus Drive 2023 Hiring For Associate Software Engineer | 3.25 & 5.5 LPA Job Role:Associate Software Engineer Degree:B.E/B.Tech/MCA/M.Sc Batch:2022/2023 Salary:Rs 3.25 & 5.5 LPA Apply Now:- http://www.allcoding1.com Telegram:- @allcoding1_official

🎯DXC Technology is hiring for Associate Professional Finance Company:-  DXC Technology PositionAssociate:- Professional Finance Qualifications:- Bachelor’s degree Batch Any Batch Experience:- Freshers & Experienced Location:- Chennai, India Apply Now:- http://www.allcoding1.com Telegram:- @allcoding1_official

Today accenture exam Ans join this channels 👇 @allcoding1_official @accenture_examAns

🎯Amazon is hiring for Data Associate I ML Role Education qualifications:- Any  Graduate /Graduate/ Post Graduates Job Role : Data Associate I ML Location: work from home Apply Now:- http://www.allcoding1.com Telegram:- @allcoding1_official

Merge String code def MergeStrings(str1, str2):     if str1 is None and str2 is None:         return None     if str1 is None:         return str2     if str2 is None:         return str1         len1 = len(str1)     len2 = len(str2)     merged = [''] * (len1 + len2)         for i in range(min(len1, len2)):         if str1[i] <= str2[i]:             merged[i] = str1[i]             merged[-(i+1)] = str2[i]         else:             merged[i] = str2[i]             merged[-(i+1)] = str1[i]         if len1 > len2:         for i in range(len2, len1):             merged[i] = str1[i]     elif len2 > len1:         for i in range(len1, len2):             merged[i] = str2[i]         return ''.join(merged) Python join this channel 👇 @allcoding1_official @accenture_examAns

int LetteredNumberSum(char* str, int len) { &nbsp;&nbsp;&nbsp; if (str == nullptr) { &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbs
int LetteredNumberSum(char* str, int len) {     if (str == nullptr) {         return 0;     }     int sum = 0;     for (int i = 0; i < len; i++) {         char letter = str[i];         int ans = 0; //@allcoding1         switch (letter) {             case 'A':                 ans = 1;                 break;             case 'B':                 ans = 10;                 break;             case 'C':                 ans = 100;                 break;             case 'D':                 ans = 1000;                 break;             case 'E':                 ans = 10000;                 break;             case 'F':                 ans = 100000;                 break;             case 'G':                 ans = 1000000;                 break;             default:                 ans = 0;                 break;         }         sum += ans;     }     return sum; } C++

networking security and clouds
+3
networking security and clouds

Pseudo codes

Abstract reasoning

.

Critical Reasoning
+9
Critical Reasoning

Abstract Reasoning
+9
Abstract Reasoning

Psecudo codes Ans
+4
Psecudo codes Ans

🎯Amazon is hiring for Data Associate I ML Role Education qualifications:- Any  Graduate /Graduate/ Post Graduates Job Role : Data Associate I ML Location: work from home Apply Now:- http://www.allcoding1.com Telegram:- @allcoding1_official

Y88B
Y88B

Zcu
Zcu

360 WDBY
360 WDBY

2 join this channel 👇 @allcoding1_official @accenture_examAns
2 join this channel 👇 @allcoding1_official @accenture_examAns