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Firibgarlarga uchmang! Telemetrio bunday kanallarni topadi va belgilaydi 👉 Belgini ko‘rmoqchi bo‘lsangiz, obuna bo‘ling

allcoding1_official

allcoding1_official

Kanalga Telegram’da o‘tish

📈 Telegram kanali allcoding1_official analitikasi

allcoding1_official (@allcoding1_official) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 78 703 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 622-o'rinni va Hindiston mintaqasida 3 757-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 78 703 obunachiga ega bo‘ldi.

30 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 600 ga, so‘nggi 24 soatda esa -27 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 1.38% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.62% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 091 marta ko‘riladi; birinchi sutkada odatda 486 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, dev kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 31 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

78 703
Obunachilar
-2724 soatlar
-3217 kun
-1 60030 kun
Postlar arxiv
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def PowerLimit(a, b): current_resource, max_seconds = 1, 0 while a > 0 and b > 0: if a > b: current_resource, a, b = 1, a - 2
def PowerLimit(a, b):   current_resource, max_seconds = 1, 0   while a > 0 and b > 0:     if a > b:       current_resource, a, b = 1, a - 2, b + 1     else:       current_resource, b, a = 2, b - 2, a + 1     max_seconds += 1   max_seconds += a // 2 if current_resource == 1 else b // 2   return max_seconds power limit ✅