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allcoding1_official (@allcoding1_official) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 85 554 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 505-o'rinni va Hindiston mintaqasida 3 485-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 85 554 obunachiga ega bo‘ldi.

23 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 402 ga, so‘nggi 24 soatda esa -39 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 2.78% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.68% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 2 382 marta ko‘riladi; birinchi sutkada odatda 585 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, dev kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 24 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

85 554
Obunachilar
-3924 soatlar
-2757 kunlar
-1 40230 kunlar
Postlar arxiv
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Ok

Beautiful set of nodes Infosys
Beautiful set of nodes Infosys

Cinema code infosys Telegram:-
Cinema code infosys Telegram:-

def max_benefit(n,A, K):     n = len(A)     dp = [0] * (n + 1)     prefix_sum = [0] * (n + 1)         for i in range(1, n + 1):         prefix_sum[i] = prefix_sum[i - 1] + A[i - 1]         for i in range(1, n + 1):         min_val = float('inf')         max_val = float('-inf')                 for j in range(1, K + 1):             if i - j >= 0:                 min_val = min(min_val, prefix_sum[i] - prefix_sum[i - j])                 max_val = max(max_val, prefix_sum[i] - prefix_sum[i - j])                 dp[i] = max(dp[i], dp[i - j] + max(max_val, -min_val))         return dp[n] % MOD Alternate Segment Infosys Telegram:- @allcoding1_official

#include using namespace std; int gcd(int a, int b) {     while (b != 0) {      &nbsp
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#include <bits/stdc++.h> using namespace std; int gcd(int a, int b) {     while (b != 0) {         int temp = b;         b = a % b;         a = temp;     }     return a; } vector<int> gcdArrays(vector<int>& arr) {     int n = arr.size();     int max_gcd = 0;     int max_length = 0;     for (int i = 0; i < n - 1; ++i) {         int current_gcd = arr[i];         for (int j = i + 1; j < n; ++j) {             current_gcd = gcd(current_gcd, arr[j]);             if (current_gcd > max_gcd) {                 max_gcd = current_gcd;                 max_length = j - i + 1;             } else if (current_gcd == max_gcd && (j - i + 1) > max_length) {                 max_length = j - i + 1;             }         }     }     return {max_gcd, max_length}; } DE Shaw Telegram:- @allcoding1_official

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Hacker Coin IBM
Hacker Coin IBM

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