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Firibgarlarga uchmang! Telemetrio bunday kanallarni topadi va belgilaydi πŸ‘‰ Belgini koβ€˜rmoqchi boβ€˜lsangiz, obuna boβ€˜ling

Code With Virus

Code With Virus

Kanalga Telegram’da oβ€˜tish

Coding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ‘ˆ Accenture @Accenturavirustech πŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆ

Ko'proq ko'rsatish

πŸ“ˆ Telegram kanali Code With Virus analitikasi

Code With Virus (@codewithvirus) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 10 559 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 10 501-o'rinni va Hindiston mintaqasida 43 593-o'rinni egallagan.

πŸ“Š Auditoriya koβ€˜rsatkichlari va dinamika

Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ sanasidan buyon loyiha tez oβ€˜sib, 10 559 obunachiga ega boβ€˜ldi.

04 Dekabr, 2025 dagi oxirgi ma’lumotlarga koβ€˜ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -87 ga, soβ€˜nggi 24 soatda esa 0 ga oβ€˜zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya oβ€˜rtacha 0% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining N/A% ini tashkil etuvchi reaksiyalarni toβ€˜playdi.
  • Post qamrovi: Har bir post oβ€˜rtacha 0 marta koβ€˜riladi; birinchi sutkada odatda 0 ta koβ€˜rish yigβ€˜iladi.
  • Reaksiyalar va oβ€˜zaro ta’sir: Auditoriya faol: har bir postga oβ€˜rtacha 0 ta reaksiya keladi.

πŸ“ Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
β€œCoding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ‘ˆ Accenture @Accenturavirustech πŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆβ€

Yuqori yangilanish chastotasi (oxirgi ma’lumot 05 Dekabr, 2025 da olingan) sababli kanal doimo dolzarb va katta qamrovli boβ€˜lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini koβ€˜rsatadi.

10 559
Obunachilar
Ma'lumot yo'q24 soatlar
-227 kun
-8730 kun
Postlar arxiv
awk 'BEGIN{FS=",", count=0;} { if($3>=60) count++; {print $2,"#",$3;} } END { if(count!=0){print count; } else { print "No re
awk 'BEGIN{FS=",", count=0;} { if($3>=60) count++; {print $2,"#",$3;} } END { if(count!=0){print count; } else { print "No records found"; }}'

awk 'BEGIN{FS="|", count=0;} { if($3>20) {count+=$3;} } END { if(count!=0){print "Total count: " count; } else { print "No re
awk 'BEGIN{FS="|", count=0;} { if($3>20) {count+=$3;} } END { if(count!=0){print "Total count: " count; } else { print "No record found with matching criteria."; }}'

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You have PRA tomorrow ?? πŸ€”

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Upcoming Mega Recruitment Drive in TCS for the following positions: Drop your resume below and our team will connect with the suitable candidates Registration Link: https://bit.ly/tcs-mega Kindly share this with your friends and colleagues.

Anyone is there to who send me full question and proper ??? πŸ€”With input output ??

Divisibility by product code in c++ language
Divisibility by product code in c++ language

Playing with arrays Java language
Playing with arrays Java language

Average of triplets in an array of integers Java language
Average of triplets in an array of integers Java language

C++ language
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C++ language

Anyone is there to who send me full question and proper ??? πŸ€”With input output ??

You have Mindtree exam ?? Then drop your coding question in our Main group πŸ”₯πŸ”₯ @avirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @avirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @avirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @avirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @avirustech πŸ”₯πŸ”₯ πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄

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Guys do you want solution ??
Guys do you want solution ??

Substring search C++ language @codewithvirus
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Substring search C++ language @codewithvirus

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C++ language ways to sum @codewithvirus
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C++ language ways to sum @codewithvirus

#include using namespace std; int NumberOfways(int N, int K) { vector dp(N + 1, 0); // Update dp[0] to 1 dp[0] = 1; // Iterat
#include <bits/stdc++.h> using namespace std; int NumberOfways(int N, int K) { vector<int> dp(N + 1, 0); // Update dp[0] to 1 dp[0] = 1; // Iterate over the range [1, K + 1] for (int row = 1; row < K + 1; row++) { // Iterate over the range [1, N + 1] for (int col = 1; col < N + 1; col++) { // If col is greater // than or equal to row if (col >= row) // Update current // dp[col] state dp[col] = dp[col] + dp[col - row]; } } // Return the total number of ways return(dp[N]); } // Driver Code int main() { int N ; int K; cin>>N>>K; cout << (NumberOfways(N, K)); }