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Reverse the given number N and print the hexadecimal equivalent of the reversed number. Assume the value of N between 1 and 9999 C++ language

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Pattern printing Python

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Guys just copy and paste on your compler Use control a and control v This is for Java. Don't type 🔴

import java.util.Scanner; public class Solution { public static void main(String[] args) { // TODO Auto-generated method stub Scanner sc = new Scanner(System.in); int n = 4 ; Bank d[] = new Bank[n]; for (int i = 0; i < d.length; i++) { int bankid = sc.nextInt(); sc.nextLine(); String bankNmae = sc.nextLine(); int numberofCustumer = sc.nextInt(); sc.nextLine(); String city = sc.nextLine(); d[i] = new Bank(bankid, bankNmae, numberofCustumer, city); } String newname = sc.nextLine(); double m1 = findavgnumberofcustumerbycity(d); // calling method1 if (m1 != 0) { System.out.println(m1); } else { System.out.println("Bank not found"); } Bank m2 = getsecondlowestnumberofcustumerbank(d, newname); // calling method 2 if (m2 != null) { System.out.println("id-" + m2.getBankid()); System.out.println("name-" + m2.getBankNmae()); System.out.println("salary-" + m2.getNumberofCustumer()); System.out.println("age-" + m2.getCity()); } else { System.out.println("Bank not found"); } } public static double findavgnumberofcustumerbycity(Bank[] ar) { double sum = 0, avg = 0; for (int i = 0; i < ar.length; i++) { sum += ar[i].getNumberofCustumer(); } avg = (sum / (ar.length)); return avg; } public static Bank getsecondlowestnumberofcustumerbank(Bank[] d, String name) { Bank l3 = null; for (int i = 0; i < d.length; i++) { // System.out.println(d[i].getName()); // System.out.println(name); if (d[i].getBankNmae().equalsIgnoreCase(name)) { l3 = d[i]; // assigning object value to l3 break; } } return l3; } } class Bank { private int bankid; private String bankNmae; private int numberofCustumer; private String city; public Bank(int bankid, String bankNmae, int numberofCustumer, String city) { super(); this.bankid = bankid; this.bankNmae = bankNmae; this.numberofCustumer = numberofCustumer; this.city = city; } public int getBankid() { return bankid; } public void setBankid(int bankid) { this.bankid = bankid; } public String getBankNmae() { return bankNmae; } public void setBankNmae(String bankNmae) { this.bankNmae = bankNmae; } public int getNumberofCustumer() { return numberofCustumer; } public void setNumberofCustumer(int numberofCustumer) { this.numberofCustumer = numberofCustumer; } public String getCity() { return city; } public void setCity(String city) { this.city = city; } }

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Guys if you're at least 3 test case passed then submit and exit don't wait for passing all test case Otherwise you if you are not submitting code then you can't get further Mail

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Remove duplicates Python 3