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Firibgarlarga uchmang! Telemetrio bunday kanallarni topadi va belgilaydi πŸ‘‰ Belgini koβ€˜rmoqchi boβ€˜lsangiz, obuna boβ€˜ling

Code With Virus

Code With Virus

Kanalga Telegram’da oβ€˜tish

Coding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ‘ˆ Accenture @Accenturavirustech πŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆ

Ko'proq ko'rsatish

πŸ“ˆ Telegram kanali Code With Virus analitikasi

Code With Virus (@codewithvirus) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 10 559 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 10 501-o'rinni va Hindiston mintaqasida 43 593-o'rinni egallagan.

πŸ“Š Auditoriya koβ€˜rsatkichlari va dinamika

Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ sanasidan buyon loyiha tez oβ€˜sib, 10 559 obunachiga ega boβ€˜ldi.

04 Dekabr, 2025 dagi oxirgi ma’lumotlarga koβ€˜ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -87 ga, soβ€˜nggi 24 soatda esa 0 ga oβ€˜zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya oβ€˜rtacha 0% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining N/A% ini tashkil etuvchi reaksiyalarni toβ€˜playdi.
  • Post qamrovi: Har bir post oβ€˜rtacha 0 marta koβ€˜riladi; birinchi sutkada odatda 0 ta koβ€˜rish yigβ€˜iladi.
  • Reaksiyalar va oβ€˜zaro ta’sir: Auditoriya faol: har bir postga oβ€˜rtacha 0 ta reaksiya keladi.

πŸ“ Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
β€œCoding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ‘ˆ Accenture @Accenturavirustech πŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆβ€

Yuqori yangilanish chastotasi (oxirgi ma’lumot 05 Dekabr, 2025 da olingan) sababli kanal doimo dolzarb va katta qamrovli boβ€˜lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini koβ€˜rsatadi.

10 559
Obunachilar
Ma'lumot yo'q24 soatlar
-227 kun
-8730 kun
Postlar arxiv
myCode(str) code in java @codewithvirus. πŸ‘ˆ @codewithvirus. πŸ‘ˆ @codewithvirus. πŸ‘ˆ @codewithvirus. πŸ‘ˆ
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myCode(str) code in java @codewithvirus. πŸ‘ˆ @codewithvirus. πŸ‘ˆ @codewithvirus. πŸ‘ˆ @codewithvirus. πŸ‘ˆ

MyCode(str) code in java
+2
MyCode(str) code in java

// jusPay 3rd code int solve(vector& maze) { int n=maze.size(); int maxSum=-1; for(int i=0; i visited; while(node < n && node >= 0 && i!=maze[node] && visited.count(node)==0) { visited.insert(node); sum+=node; node=maze[node]; } if(node>=0 && node < n && i == maze[node]) { maxSum=max(maxSum,sum); } } return maxSum; }

// jusPay 2nd code int solution(vector arr) { int ans = INT_MIN; int result = -1; vector weight(arr.size(), 0); for (int i = 0; i < arr.size(); i++) { int source = i; int dest = arr[i]; if (dest != -1) { weight[dest] += source; if (ans <= weight[dest]) { ans = max(ans, weight[dest]); result = dest; } } } if (ans != INT_MIN) return result; return -1; }

// jusPay 2nd code int solve(vector& maze,int n) { int maxSum=-1; for(int i=0; i visited; while(node < n && node >= 0 && i!=maze[node] && visited.count(node)==0) { visited.insert(node); sum+=node; node=maze[node]; } if(node>=0 && node < n && i == maze[node]) { maxSum=max(maxSum,sum); } } return maxSum; }

// jusPay 1st code public static int Solution(int[] arr, int C1, int C2) { int[] dist = new int[arr.length]; int max = Integer.MAX_VALUE; Arrays.fill(dist, Integer.MAX_VALUE); Queue q = new ArrayDeque<>(); int dis = -1; q.offer(c1); q.offer(max); boolean[] visited = new boolean[arr.length]; while (q.size() > 1) { int vtx = q.poll(); if (vtx == max) { q.offer(vtx); dis++; continue; } visited[vtx] = true; dist[vtx] = Math.min(dis + 1, dist[vtx]); int neigh = arr[vtx]; if (visited[neigh] == false) { q.offer(neigh); } } Arrays.fill(visited, false); q.poll(); q.offer(C2); q.offer(max); int ans = -1; while (q.size() > 1) { int vtx = q.poll(); if (vtx == max) { q.offer(vtx); dis++; continue; } if (visited[vtx] == false && dist[vtx] != max) { ans = vtx; break; } visited[vtx] = true; int neigh = arr[vtx]; if (visited[neigh] == false) { q.offer(neigh); } } return ans; }

You have on campus Juspay exam ?? Tell me which college form you are mm