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HYDERABAD BANGLORE REAL-ESTATE ||STOCKS || INVESTMENTS || PLOTS || RENTS

HYDERABAD BANGLORE REAL-ESTATE ||STOCKS || INVESTMENTS || PLOTS || RENTS

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🔰Byjus hiring all Batches 🔰 10 laks😱 👉Name of Post :Business Development 👉Qualification : BE/B.Tech 👉Batch : Any Batch 👉Salary : 10 laks 🔴Apply Link : https://byjus.com/apply/

ranks=[0,0,0,0,0] names=['Malaysia','Australia','Germany','Dubai','France'] flag=0 for i in range(0,5): if flag==1: break for j in range(0,5): r=input() if r.isnumeric(): r=int(r) if r>0 and r<=5: if r==1: ranks[j]+=1 else: flag=1 break else: flag=1 break if flag==1: print("INVALID INPUT") else: comb=list(zip(ranks,names)) comb.sort(key = lambda x:x[0]) top = comb[0][0] for i in range(0,5): if top==comb[i][0]: print(comb[i][1])

import sys items = {1:50, 2:100, 3:40,4:200,5:300} user_items =[int(x) for x in input().split() ] quantity = [int(x) for x in input().split()] membership = input() tp = 0.0 k=0 for i in user_items: if i in items: tp += items[i] * quantity[k] k = k+1 else: print("INVALID INPUT") sys.exit(0) if((membership == 'y' or membership == "Y") and tp > 1000): tp = tp - ((15*tp)/100) elif(membership == 'y' or membership == "Y"): tp = tp - ((5*tp)/100) elif(tp > 1000): tp = tp - ((10*tp)/100) print(tp,"INR",sep="")

Bunch of keys x=[] while True: x.append(input()) if x[-1]=='q': break x.remove('q') p=x.count('-') print("BLANK KEYS:"+str(p)) print("TOTAL KEYS:"+str(len(x))) print("NUMBER OF LOCKS:"+str(len(x)-p))

l = [0,50,100,40,200,300] item = list(map(int,input().split())) quan = list(map(int,input().split())) c = input() cost = 0 for i in range(len(item)): cost = cost + quan[i]*l[item[i]] if cost>100 and c== 'y': cost = cost-cost*15/100 if cost>1000 and c!='y': cost = cost-cost*0.1 if max(item)>5: print('INVALID INPUT') else: print(f'{cost}INR')

#include<bits/stdc++.h> using namespace std; int main(){ double price[] = {80.0, 130.0, 100.0, 80.0, 90.0,110.0,120.0, 140.0, 70.0,80.0, 130.0, 160.0, 70.0,60.0,40.0,50.0,30.0,40.0,160.0,150.0}; double total = 0; int ch, q; char chc; do{ cin>>ch>>q; cout<<"more items? (y/n) \n"; cin>>chc; if(ch > -1 && ch < 20) total += price[ch-1] * q; else { cout<<"INVALID INPUT"; return 0; } } while(chc == 'y'); int t = total; if(t != total) cout<<"Total Amount "<<total<<" INR"; else cout<<"Total Amount "<<total<<".0 INR"; return 0; }

💥 Verbal ability:- 1. The most important thing.. Ans: A B

💥 Numerical Ability:- 1.Train travelling at 79km/hr.... Ans - 7.4 2. If (x+10)%.. Ans: 16 3. Value of.. Ans: 18/35 4. A shopkeeoer... Ans: 11(1/9) 5. A certain loan.. Ans: 1320 6.if a is 20%... Ans: 25c:18b 7. Let x be upper limit.. Ans: 10.5 8. The speed of boat.. Ans: 24 9. What is the mean mark.. Ans: 16(2/3) 10. (2.4)^2... Ans: 0.3&0.5 11. Number of pencils.. Ans- 15 12. A&b can complete.. Ans: 15 13. A certain sum amt.. Ans: 12960 14.Difference between age Ans: 36 15. In a compatetive exam.. Ans: 26 16. √1+√3/2... Ans: 9 17. The sum if height... Ans: 10568 18. Sarita wants to gift.. Ans: 15

💥Numerical Ability:- 1. The marks of 10 student.. Ans: 9.0 2. 10% of voters.. Ans: 20000 3. If (x+10)%... Ans: 16 4. The standard deviation.. Ans: 16&18 (join helping_hand4u for more) 5. Amita earns.. Ans: loss 3.5% 6. In finding hcf.. Ans: 68 7. If the mean 29 obser.. Ans: 63 8. What is the mean of.. Ans: 14.5 9. Two sarees.. Ans: 150 10. The time taken by boat.. Ans: 6.4 11. In 2018, madhu... Ans: 19.8 12. 3(4/7)/... Ans: 15/16 13. Table answer.. Ans: 37.5 14. The ratio of two number.. Ans: 6:5 15. If 5x3y... Ans: 27 (Join helping_hand4u) 16. What is the sum(in rs).. Ans: 25020 17. A certain sum.. Ans:15972 18. A metallic speher.. Ans: 185 19. Two soln a and b.. Ans: 45 Join helping_hand4u for more 20. The loan of inr.. Ans: 10140 21. Pipe a and b.. Ans: 32

//python code t1=0 flag=0 t2=1 t3=0 fib=[] odd_cnt=0 even_cnt=0 n=input() if n.isdigit(): n=int(n) if n<=5 or n>20: flag=1 else: for i in range(0,n): t1=t2 t2=t3 t3=t1+t2 fib.append(t3) if t3%2==0: even_cnt+=1 else: odd_cnt+=1 if flag==1: print("INVALID INPUT") else: for i in range(0,n): if i!=(n-1): print(fib[i],end=" ") else: print(fib[i]) print(even_cnt) print(odd_cnt)

//python code t1=0 flag=0 t2=1 t3=0 fib=[] odd_cnt=0 even_cnt=0 n=input() if n.isdigit(): n=int(n) if n<=5 or n>20: flag=1 else: for i in range(0,n): t1=t2 t2=t3 t3=t1+t2 fib.append(t3) if t3%2==0: even_cnt+=1 else: odd_cnt+=1 if flag==1: print("INVALID INPUT") else: for i in range(0,n): if i!=(n-1): print(fib[i],end=" ") else: print(fib[i]) print(even_cnt) print(odd_cnt)

Quants 1. If 3√4913/4096..value of a A. 1 2. In a competitive exam A. 26 3. Csa of cone... A. 11440 4.Two cars a and b meet.. A. 60 kmph Join @ tcsnqtexam 5. The value 7.6*3.8*15.28.. A. 13 and 14 6. Salary in rupees of 10 emp A. 11.983 7. Bike.. A. 7 Join @ tcsnqtexam 8. If the perimeter of rectangle... A. 420 9. Number divisible by 7 A. 2 10. A sum was lent at A. 3000 Join @ tcsnqtexam 11. A can do a piece.. A. 30 6/7 12. Mean of 29 observations A. 63 13. Pie Chart A. 1500 14. if √2 = 1.1414.... A. 1.284 15. A sells an article A. 690 Join @ tcsnqtexam 16. What percentage of total A. 52.7 17. A, B and C enter A. 300000 18. 10% of the voters A. 25000 Join @ tcsnqtexam 19. If a deaer A. 1.5 20. A and B undertake A. 360 Join @placementupdatess

💥 Numerical Ability:- 1.Standard deviation... Ans: 11.983 2. Mean of the.. Ans: 63 3. If 3√4913/4096... Ans: 1 4. If the perimeter of rectangle... Ans: 420 5. Csa of cone... Ans: 11440 6. The mean of data.. Ans: 5 7. Bike.. Ans: 7 8.Two cars a and b meet.. Ans: 60 kmph 9. A sales representative.. Ans: 50000 10.Valye of 7.6*...... Ans: 13 and 14 11. If the number is divided by 7.. Ans: 4 12. If √2=1.414.. Ans: 1.2843 13. In a compatitive exam.. Ans: 26 14. Pie chart Ans: 1500

Update by iON, Students can try resuming back the test and continue the test. If still the issue persists, no need to panic they will receive the communication accordingly by EOD from iON. Thank you.

Try Not To Do anytype of Malpractice In TCS nqt... Even if u do ,do with great care and without being caught Because TCS may ban your Account and You cannot write NQT after 3 months again...😐

Click on the above link-->Login to the account-->Click here to view updates on your NQT details (Right side of home pages)-->Click on login details tab-->You will able to see slot details https://learning.tcsionhub.in/iDH/India/home

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