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#include<bits/stdc++.h> using namespace std; #define mod 1000000007 #define ll long long int #define pb push_back int main() { ll t=1,i,n,j,q,k,x,y,z,l,yy,sum,m,e,f,p,r,g; ios::sync_with_stdio(0);cin.tie(0);cout.tie(0); cin>>t; while(t--) { cin>>n; ll a[n+1]; for(i=0;i<n;i++) cin>>a[i]; for(i=n-1;i>=0;i--) { if(a[i]%2==0&&a[i]%5==0) cout<<a[i]<<" "; } for(i=n-1;i>=0;i--) { if(a[i]%2==0&&a[i]%5!=0) cout<<a[i]<<" "; } for(i=0;i<n;i++) { if(a[i]%2==1) cout<<a[i]<<" "; } cout<<endl; } } Awesome sort Lowe's

Kantar Exam : Very Cool number Language : Python3 n , k = map(int,input().split()) c = 0 for i in range(1,n+1): s = 0 b = bin(i)[2:] while "101" in b: b = b[b.index("101")+1:] s+=1 if s>=k: c+=1 print (c) @placementupdatess

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#include <iostream> using namespace std; int frog(int h[],int n) { int dp[1000005]={}; dp[0]=0; dp[1]=abs(h[1]-h[0]); for(int i=2;i<n;i++) { dp[i]=min((dp[i-1]+abs(h[i]-h[i-1])),(dp[i-2]+abs(h[i]-h[i-2]))); } return dp[n-1]; } int main() { // your code goes here int n; cin>>n; int ar[n]; for(int i=0;i<n;i++) { cin>>ar[i]; } cout<<frog(ar,n)<<endl; return 0; } P19 Walmart Telegram:: @placementupdatess

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