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Codehub (@pythonadvisorai) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 32 524 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 4 014-o'rinni va Malayziya mintaqasida 1 025-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 32 524 obunachiga ega bo‘ldi.
25 Avgust, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -446 ga, so‘nggi 24 soatda esa -9 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 3.42% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining N/A% ini tashkil etuvchi reaksiyalarni to‘playdi.
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📝 Tavsif va kontent siyosati
Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“Free Programming resources.”
Yuqori yangilanish chastotasi (oxirgi ma’lumot 26 Avgust, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
nums = [3, 5, 7, 9, 12, 17, 20, 21]*Question:* Find and print all numbers in the list that are prime. *Expected Output:*
[3, 5, 7, 17]*Python Code:*
def is_prime(n):
if n < 2:
return False
for i in range(2, int(n**0.5) + 1):
if n % i == 0:
return False
return True
prime_nums = [n for n in nums if is_prime(n)]
print(prime_nums)
*Explanation:*
– Checks each number with is_prime() logic
– Uses list comprehension for concise filtering
– Prints list of all prime numbers
💬 *Tap ❤️ for more logic-building questions!*numbers = [1, 2, 3, 2, 4, 1, 5, 2]*Question:* Find the number that appears most frequently in the list. *Expected Output:*
2*Python Code:*
from collections import Counter
most_common_num = Counter(numbers).most_common(1)[0][0]
print(most_common_num)
*Explanation:*
– Counter() counts occurrences of each element
– most_common(1) returns the most frequent item
– Access [0][0] to get just the number
💬 *Tap ❤️ for more bite-sized Python tips!*
***
Would you like the next one to be slightly more advanced (e.g., involving strings or list comprehensions)? while`) & Conditionals (`if, `else`)
• Functions & Modules
✅ *Tip 2: Practice Small Programs*
Build mini-projects to reinforce concepts:
• Calculator
• To-do app
• Dice roller
• Guess-the-number game
✅ *Tip 3: Understand Data Structures*
• Lists, Tuples, Sets, Dictionaries
• How to manipulate, search, and iterate
✅ *Tip 4: Learn File Handling & Libraries*
• Read/write files (`open`, `with`)
• Explore libraries: math, random, datetime, os
✅ *Tip 5: Work with Data*
• Learn pandas for data analysis
• Use matplotlib & seaborn for visualization
✅ *Tip 6: Object-Oriented Programming (OOP)*
• Classes, Objects, Inheritance, Encapsulation
✅ *Tip 7: Practice Coding Challenges*
• Platforms: LeetCode, HackerRank, Codewars
• Focus on loops, strings, arrays, and logic
✅ *Tip 8: Build Real Projects*
• Portfolio website backend
• Chatbot with NLTK or Rasa
• Simple game with pygame
• Data analysis dashboards
✅ *Tip 9: Learn Web & APIs*
• Flask / Django basics
• Requesting & handling APIs (`requests`)
✅ *Tip 10: Consistency is Key*
Practice Python daily. Review your old code and improve logic, readability, and efficiency.
💬 *Tap ❤️ if this helped you!*import numpy as np
def remove_outliers(data):
q1 = np.percentile(data, 25)
q3 = np.percentile(data, 75)
iqr = q3 - q1
lower = q1 - 1.5 * iqr
upper = q3 + 1.5 * iqr
return [x for x in data if lower <= x <= upper]
2️⃣ Convert a nested list to a flat list.
nested = [[1, 2], [3, 4],]
flat = [item for sublist in nested for item in sublist]
3️⃣ Read a CSV file and count rows with nulls.
import pandas as pd
df = pd.read_csv('data.csv')
null_rows = df.isnull().any(axis=1).sum()
print("Rows with nulls:", null_rows)
4️⃣ How do you handle missing data in pandas?
⦁ Drop missing rows: df.dropna()
⦁ Fill missing values: df.fillna(value)
⦁ Check missing data: df.isnull().sum()
5️⃣ Explain the difference between loc[] and iloc[].
⦁ loc[]: Label-based indexing (e.g., row/column names)
Example: df.loc[0, 'Name']
⦁ iloc[]: Position-based indexing (e.g., row/column numbers)
Example: df.iloc
💬 Tap ❤️ for more!import numpy as np
def remove_outliers(data):
q1 = np.percentile(data, 25)
q3 = np.percentile(data, 75)
iqr = q3 - q1
lower = q1 - 1.5 * iqr
upper = q3 + 1.5 * iqr
return [x for x in data if lower <= x <= upper]
2️⃣ Convert a nested list to a flat list.
nested = [[1, 2], [3, 4],]
flat = [item for sublist in nested for item in sublist]
3️⃣ Read a CSV file and count rows with nulls.
import pandas as pd
df = pd.read_csv('data.csv')
null_rows = df.isnull().any(axis=1).sum()
print("Rows with nulls:", null_rows)
4️⃣ How do you handle missing data in pandas?
⦁ Drop missing rows: df.dropna()
⦁ Fill missing values: df.fillna(value)
⦁ Check missing data: df.isnull().sum()
5️⃣ Explain the difference between loc[] and iloc[].
⦁ loc[]: Label-based indexing (e.g., row/column names)
Example: df.loc[0, 'Name']
⦁ iloc[]: Position-based indexing (e.g., row/column numbers)
Example: df.iloc
💬 Tap ❤️ for more!