Endi mavjud! Telegram Tadqiqoti 2025 — yilning asosiy insaytlari 
Mathematics Optional
Kanalga Telegram’da o‘tish
Ko'proq ko'rsatish
📈 Telegram kanali Mathematics Optional analitikasi
Mathematics Optional (@mathematics_optional_notes) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 10 344 obunachidan iborat bo'lib, Taʼlim toifasida 19 231-o'rinni va Hindiston mintaqasida 38 757-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 10 344 obunachiga ega bo‘ldi.
30 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -122 ga, so‘nggi 24 soatda esa -9 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 2.96% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining N/A% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 0 marta ko‘riladi; birinchi sutkada odatda 0 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent upsc, mathematics, kataria, mathematic, ज्वाइन kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Kanal uchun tavsif kiritilmagan.
Yuqori yangilanish chastotasi (oxirgi ma’lumot 01 Iyul, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
10 344
Obunachilar
-924 soatlar
-457 kunlar
-12230 kunlar
Postlar arxiv
10 346
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Free Videos for All
https://www.youtube.com/channel/UClQ37UtKiY5AZ4PuYBslGsg?sub_confirmation=1
Subscribe and Share with your friends
10 346
Repost from N/a
CSAT 60 Days guidance programme with IIM Calcutta alumni @ 1 Rs. ( Only 100 seats)
To get a free sample copy of material and plan download the app ↴↴
☞ Download link for android ➛ http://on-app.in/app/home?orgCode=bqqrx
☞ For ios ➛ open my institute app and then use org code BQQRX.
