Python learning
Kanalga Telegram’da o‘tish
📈 Telegram kanali Python learning analitikasi
Python learning (@python3learning) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 890 obunachidan iborat bo'lib, Taʼlim toifasida 8 592-o'rinni va Hindiston mintaqasida 18 283-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 22 890 obunachiga ega bo‘ldi.
25 Avgust, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -259 ga, so‘nggi 24 soatda esa -11 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 6.20% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining N/A% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 0 marta ko‘riladi; birinchi sutkada odatda 0 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
📝 Tavsif va kontent siyosati
Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“Learn python🔥”
Yuqori yangilanish chastotasi (oxirgi ma’lumot 26 Avgust, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
22 890
Obunachilar
-1124 soatlar
-667 kunlar
-25930 kunlar
Ma'lumot yuklanmoqda...
O'xshash kanallar
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Ma'lumot yo'q
Muammo bormi? Iltimos, sahifani yangilang yoki bizning qo'llab-quvvatlash boshqaruvchimizga murojaat qiling>.
Kirish va chiqish esdaliklari
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Obunachilarni jalb qilish
Avgust '26
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+5
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+41
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+555
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+185
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May '21
+866
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| Sana | Obunachilarni jalb qilish | Esdaliklar | Kanallar | |
| 26 Avgust | +1 | |||
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| 02 Avgust | +2 | |||
| 01 Avgust | 0 |
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I've been writing Python for years, and this release surprised me.
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Most developers haven't noticed these changes yet.
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| 19 | ***
✅ *Python Logic Building Interview Question* 🧠🐍
You have a list of numbers: nums = [3, 5, 7, 9, 12, 17, 20, 21]
*Question:*
Find and print all numbers in the list that are prime.
*Expected Output:* [3, 5, 7, 17]
*Python Code:* def is_prime(n):
if n < 2:
return False
for i in range(2, int(n**0.5) + 1):
if n % i == 0:
return False
return True
prime_nums = [n for n in nums if is_prime(n)]
print(prime_nums)
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– Checks each number with is_prime() logic
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– Prints list of all prime numbers
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| 20 | ✅ *Python Scenario-Based Interview Question* 🧠🐍
You have a list: numbers = [1, 2, 3, 2, 4, 1, 5, 2]
*Question:*
Find the number that appears most frequently in the list.
*Expected Output:* 2
*Python Code:* from collections import Counter
most_common_num = Counter(numbers).most_common(1)[0][0]
print(most_common_num)
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– most_common(1) returns the most frequent item
– Access [0][0] to get just the number
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***
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