PythonCoder Official
Kanalga Telegram’da o‘tish
• 𝗕𝗲𝘀𝘁 𝗽𝗹𝗮𝗰𝗲 𝗳𝗼𝗿 𝗣𝘆𝘁𝗵𝗼𝗻 𝗖𝗼𝗱𝗲𝗿𝘀 😀 • 𝗙𝗿𝗲𝗲 𝗣𝗿𝗼𝗴𝗿𝗮𝗺𝗺𝗶𝗻𝗴 𝗖𝗼𝘂𝗿𝘀𝗲𝘀 & 𝗧𝘂𝘁𝗼𝗿𝗶𝗮𝗹𝘀📒 • 𝗗𝗮𝘁𝗮 𝗦𝗰𝗶𝗲𝗻𝗰𝗲📊 | 𝗠𝗮𝗰𝗵𝗶𝗻𝗲 𝗟𝗲𝗮𝗿𝗻𝗶𝗻𝗴 | 𝗔𝗜 🤖 • 𝗗𝗮𝗶𝗹𝘆 𝗗𝗼𝘇𝗲 𝗼𝗳 𝗣𝗿𝗼𝗷𝗲𝗰𝘁𝘀 🧠
Ko'proq ko'rsatish📈 Telegram kanali PythonCoder Official analitikasi
PythonCoder Official (@pythoncoder92) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 74 610 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 690-o'rinni va Hindiston mintaqasida 4 272-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 74 610 obunachiga ega bo‘ldi.
25 Avgust, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 442 ga, so‘nggi 24 soatda esa -42 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 7.45% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.45% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 5 562 marta ko‘riladi; birinchi sutkada odatda 1 079 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 16 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent programming, certification, stack, s_curve, t.left(90 kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“• 𝗕𝗲𝘀𝘁 𝗽𝗹𝗮𝗰𝗲 𝗳𝗼𝗿 𝗣𝘆𝘁𝗵𝗼𝗻 𝗖𝗼𝗱𝗲𝗿𝘀 😀
• 𝗙𝗿𝗲𝗲 𝗣𝗿𝗼𝗴𝗿𝗮𝗺𝗺𝗶𝗻𝗴 𝗖𝗼𝘂𝗿𝘀𝗲𝘀 & 𝗧𝘂𝘁𝗼𝗿𝗶𝗮𝗹𝘀📒
• 𝗗𝗮𝘁𝗮 𝗦𝗰𝗶𝗲𝗻𝗰𝗲📊 | 𝗠𝗮𝗰𝗵𝗶𝗻𝗲 𝗟𝗲𝗮𝗿𝗻𝗶𝗻𝗴 | 𝗔𝗜 🤖
• 𝗗𝗮𝗶𝗹𝘆 𝗗𝗼𝘇𝗲 𝗼𝗳 𝗣𝗿𝗼𝗷𝗲𝗰𝘁𝘀 🧠”
Yuqori yangilanish chastotasi (oxirgi ma’lumot 26 Avgust, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
74 610
Obunachilar
-4224 soatlar
-3177 kunlar
-1 44230 kunlar
Postlar arxiv
74 610
Do you want Certification of Full Stack Website Development by PhysicsWallah at Free of Cost 🤔 ---> Yes / No 🤔
74 610
- 📌 Python Logo Source Code📌 -
import turtle
t = turtle.Turtle()
s = turtle.Screen()
s.bgcolor("black")
t.speed(10)
t.pensize(2)
t.pencolor("white")
def s_curve():
for i in range(90):
t.left(1)
t.forward(1)
def r_curve():
for i in range(90):
t.right(1)
t.forward(1)
def l_curve():
s_curve()
t.forward(80)
s_curve()
def l_curve1():
s_curve()
t.forward(90)
s_curve()
def half():
t.forward(50)
s_curve()
t.forward(90)
l_curve()
t.forward(40)
t.left(90)
t.forward(80)
t.right(90)
t.forward(10)
t.right(90)
t.forward(120) #on test
l_curve1()
t.forward(30)
t.left(90)
t.forward(50)
r_curve()
t.forward(40)
t.end_fill()
def get_pos():
t.penup()
t.forward(20)
t.right(90)
t.forward(10)
t.right(90)
t.pendown()
def eye():
t.penup()
t.right(90)
t.forward(160)
t.left(90)
t.forward(70)
t.pencolor("black")
t.dot(35)
def sec_dot():
t.left(90)
t.penup()
t.forward(310)
t.left(90)
t.forward(120)
t.pendown()
t.dot(35)
t.fillcolor("#306998")
t.begin_fill()
half()
t.end_fill()
get_pos()
t.fillcolor("#FFD43B")
t.begin_fill()
half()
t.end_fill()
eye()
sec_dot()
def pause():
t.speed(2)
for i in range(100):
t.left(90)
pause()
74 610
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--- Do you like me Source Code ---
import tkinter as tk
import random
def show_popup():
popup = tk.Toplevel(root)
popup.title("Popup")
label = tk.Label(popup, text="Thanks for Accepting")
label.pack(padx=20, pady=20)
def move_button(event):
x = random.randint(0, 350)
y = random.randint(0, 350)
no_button.place(x=x, y=y)
root = tk.Tk()
root.title("instagram: @python.coder_")
root.geometry("400x400")
question_label = tk.Label(root, text="Do you like me?")
question_label.pack(pady=20)
yes_button = tk.Button(root, text="Yes", command=show_popup)
yes_button.pack()
no_button = tk.Button(root, text="No")
no_button.pack()
no_button.bind("<Enter>", move_button)
root.mainloop()
74 610
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