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1Malaysia Science Stream Student ‼️‼️ 🌟 share notes/exercises/tips #AchieveStraightAsTogether 🌟Biology 🌟Chemistry 🌟Physic 🌟Mathematic 🌟Addmath chat here :)) https://t.me/studylikerorychat

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okayy take it with a pinch of salt

yg penting baca2 jangan skip juga exp lain

jangan ambik bulat2, or too confident tmr is gonna be heat of displacement

credit studylink08

BM!

AMALI KIMIA KERTAS 3🌟🌟🌟 Eksperimen Jangkaan : Haba penyesaran ( termokimia ) / Penyesaran logam ( redoks ) So far admin cuma tahu larutan diberi CuSO4 Dan serbuk logam X & Y ✅Pemerhatian - Mendakan Perang Terbentuk - (Larutan) : Warna larutan biru CuSO4 berubah menjadi tidak bewarna / pudar ( IKUT MASA EKSPERIMEN ) & *WAJIB MENTION PERUBAHAN WARNA* Inferens :🚨WAJIB SELARI DENGAN PEMERHATIAN (❌HARAM JIKA BERBEZA DENGAN PEMERHATIAN) ✅Mendakan Perang Terbentuk kerana Ion Cu 2+ diturunkan kepada logam Cu ✅Warna biru CuSO4 menjadi pudar kerana7 ion Cu 2+ semakin berkurang Hipotesis : ( PERLU ADA MV + RV ) Contoh : Apabila logam X disesarkan Maka haba penyesaran lebih tinggi manakala Apabila logam Y disesarkan haba Maka haba penyesaran lebih rendah D.O (Definisi operasi ) WYD ( WHAT YOU DO ) + WYO ( WHAT YOU OBSERVE ) ✅ Pembebasan Haba apabila logam X dimasukkan ke dalam larutan kuprum(II) sulfat untuk menyesarkan 1 mol kuprum(WYD) bacaan termometer meningkat( WYO) .Apabila logam Y dimasukkan ke dalam larutan kuprum(II) sulfat untuk menyesarkan 1 mol kuprum ,bacaan thermometer meningkat lebih tinggi . Jadual : PERLU SALIN BULAT II DARI TAJUK ( HARAM PENDEKKAN TAJUK UNTUK JADUAL) ✅one d.p kecuali buret Pemboleh ubah : Manipulasi : Jenis logam (Boleh juga mentioned logam specific yang diberi atau label ) Dimalarkan : Isipadu Dan kepekatan larutan kuprum(II) sulfat ( WAJIB TULIS ISIPADU DAN KEPEKATAN) ❌isipadu larutan kuprum(II) sulfat PENJELASAN MENDAKAN PERANG TERBENTUK : logam X lebih elektropositif / E° lebih negatif daripada kuprum .Boleh menyesarkan kuprum daripada larutan kuprum(II) sulfat .Ion Cu2+ diturunkan membentuk atom Cu PENJELASAN MENGAPA LOGAM X HABA PENYESARAN LEBIH TINGGI DARIPADA LOGAM Y : ✅Logam X lebih elektropositif / E° lebih negatif drpd logam Y. Bergerak balas : Haba penyesaran ✅ Bacaan thermometer ❌ ( IKUT TUJUAN EKSPERIMEN) Langkah Berjaga - Jaga : (i) Mengacau larutan perlahan-lahan sepanjang eksperimen dijalankan untuk memastikan suhu campuran adalah sekata. (ii) Pepejal logam ditambahkan dengan cepat dan cermat✅ (iii) Menggunakan serbuk logam bukan ketulan supaya memastikan tindak balas berlaku dengan lebih cepat✅ ❌Menutup kipas Modifikasi alat : Contoh soalan : Cadangkan ubahsuai radas untuk memastikan haba tidak terbebas ke persekitaran ✅Memasangkan penutup mengelakkan Pembebasan Haba ke persekitaran Meramal: 🧡Ramalkan bacaan suhu jika logam X diganti dengan logam plumbum. ( Rendah daripada nilai data ) Kerana Logam X lebih elektropositif daripada logam plumbum 🧡Adakah nilai haba penyesaran Cu akan sama jika larutan kuprum(II) sulfat diganti dengan larutan kuprum(II) nitrat ? Sama. Haba penyesaran masih melibatkan ion kuprum yang terdapat dalam larutan kuprum(II) nitrat. 🧡Mengapakah nilai eksperimen tidak sama dengan nilai teori ? - Sebahagian haba dibebaskan ke persekitaran Jenis t/b : Eksotermik ✅Cari tahu cara buat persamaan kimia & ion ✅penyelesaian kira ii haba penyesaran ✅Klasifikasi logam lebih elektropositif ✅Lukisan graf eksotermik Prosedur : 1) Sukat 25 cm3 larutan kuprum(II) sulfat, CuSO4 , 0.2 mol dm−3 dan tuangkan ke dalam ....... 2. Masukkan termometer ke dalam larutan itu dan biarkannya selama dua minit. 3. Catatkan suhu awal larutan dalam jadual. 4. Tambahkan satu spatula serbuk magnesium,.... dengan cepat dan cermat ke dalam . ... 5. kacau campuran dengan termometer. 6. Catatkan suhu tertinggi campuran. 7. Ulangi langkah 1 hingga 6 dengan menggunakan serbuk ....bagi menggantikan serbuk magnesium,...

soalan ramalkan 1. perubahan warna sekiranya larutan kuprum ( II ) sulfat digantikan dengan laturan kuprum ( II ) nitrat = sama , kerana bilangan ion kuprum ( II ) adalah sama 2. perubahan suhu sekiranya serbuk logam Zn / Mg digantikan kepada serbuk Argentum = tiada perubahan , Ag kurang elektropositif daripada Cu @ Ag tidak dapat menurunkan ion Cu²+ 3. kenapa serbuk logam digunakan secara berlebihan ? = supaya haba penyesaran berlaku secara lengkap 4. logam yang bole disesarkan = Stanum , Ferum , Aluminium 5. logam yang tak boleh disesarkan = Argentum 6. Cth t.balas endo ? = fotosintesis 7. Cth t.balas ekso ? = Respirasi , Pembakaran , Pengaratan besi

Prediction Questions (Translated) 1. Colour change if copper(II) sulfate solution is replaced with copper(II) nitrate solution = The same, because the number of copper(II) ions is the same. --- 2. Temperature change if Zn / Mg metal powder is replaced with silver (Ag) powder = No change, because Ag is less electropositive than Cu and cannot reduce/displace Cu²⁺ ions. --- 3. Why is excess metal powder used? = To ensure the displacement reaction occurs completely / to ensure complete heat of displacement. --- 4. Metals that can be displaced (by Cu²⁺) = Tin (Sn), Iron (Fe), Aluminium (Al) --- 5. Metals that cannot be displaced = Silver (Ag) --- 6. Example of an endothermic reaction = Photosynthesis --- 7. Example of an exothermic reaction = Respiration, Combustion, Rusting of iron

English vers

Here is the full translation into English, keeping the format, tone, and all important exam-style keywords exactly as required: --- CHEMISTRY EXPERIMENT PAPER 3 🌟🌟🌟 Expected Experiment: Heat of displacement (thermochemistry) / Metal displacement (redox) So far the admin only knows the solution given is CuSO₄ and metal powders X & Y --- ✅ Observations A brown precipitate is formed (Solution): The blue colour of CuSO₄ becomes colourless / fades (DEPENDING ON THE EXPERIMENT TIME) and YOU MUST MENTION THE COLOUR CHANGE Inference: 🚨 MUST MATCH THE OBSERVATION (❌FORBIDDEN IF DIFFERENT FROM OBSERVATION) A brown precipitate is formed because Cu²⁺ ions are reduced to copper metal The blue colour of CuSO₄ fades because the Cu²⁺ ions decrease --- Hypothesis: (MUST HAVE MV + RV) Example: When metal X displaces copper, the displacement heat is higher, whereas when metal Y displaces copper, the displacement heat is lower. --- Operational Definition (O.D.) WYD (WHAT YOU DO) + WYO (WHAT YOU OBSERVE) Heat is released when metal X is added to copper(II) sulfate solution to displace 1 mol of copper (WYD). The thermometer reading increases (WYO). When metal Y is added to copper(II) sulfate solution to displace 1 mol of copper, the thermometer reading increases more. --- Table: MUST COPY EXACTLY FROM TITLE (FORBIDDEN TO SHORTEN THE TITLE) Use one decimal place except for burette readings. --- Variables Manipulated variable: Type of metal (may mention the exact metal given or label) Controlled variables: Volume AND concentration of copper(II) sulfate solution (MUST STATE BOTH VOLUME AND CONCENTRATION) ❌ Not: volume of copper(II) sulfate solution (alone is not enough) --- Explanation for Brown Precipitate Formation Metal X is more electropositive / has a more negative E° value than copper. It displaces copper from copper(II) sulfate solution. Cu²⁺ ions are reduced to Cu atoms. --- Explanation Why Metal X Has Higher Displacement Heat Than Metal Y Metal X is more electropositive / has a more negative E° value compared to metal Y. --- Type of Reaction: Exothermic --- Precautions (i) Stir the solution gently throughout the experiment to ensure a uniform temperature. (ii) Add the metal powder quickly and carefully. (iii) Use metal powder instead of metal pieces to ensure the reaction occurs faster. ❌ Do NOT write “switch off the fan”. --- Apparatus Modification Example question: Suggest a modification to prevent heat from escaping to the surroundings. ✅ Add a lid/cover to prevent heat loss to the surroundings. --- Prediction 🧡 Predict the temperature reading if metal X is replaced with lead (Pb). → Lower than the original value because metal X is more electropositive than lead. 🧡 Will the displacement heat of copper be the same if copper(II) sulfate is replaced with copper(II) nitrate? → Yes. Displacement heat still involves Cu²⁺ ions found in copper(II) nitrate solution. 🧡 Why is the experimental value not equal to the theoretical value? → Some heat is lost to the surroundings. --- What you need to know How to write balanced chemical equations and ionic equations Calculation of heat of displacement Classification of metals by electropositivity Drawing an exothermic graph/energy profile --- Procedure (Translated) 1. Measure 25 cm³ of 0.2 mol dm⁻³ copper(II) sulfate solution, CuSO₄, and pour it into a __. 2. Insert a thermometer into the solution and leave it for two minutes. 3. Record the initial temperature of the solution in the table. 4. Add one spatula of magnesium powder, __, quickly and carefully into the __. 5. Stir the mixture with the thermometer. 6. Record the highest temperature of the mixture. 7. Repeat steps 1 to 6 using _ powder to replace magnesium powder. --- If you want, I can also prepare: ✅ Complete sample PEKA-style report ✅ Full chemical equations + ionic equations ✅ Complete heat of displacement calculations ✅ Sample graph Just tell me!

okay2 chem

Girl same. I buat 10 ha.ha.ha.ha. its okay la move on, focus for tmrw...and don't repeat the same mistake 💪benda ni jdi pengajaran kt kita☺️

Mind you, my sch tak off kipas from the beginning pun lol.. 💀

tak.. I buat 20 oscillation, I tak baca properly patut 5

I'm so sad guys

I don't think i did well.. I didn't read the instruction correctly.. (oscillation)

selesai

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doa usaha ikhtiar takawal 🤞🏽🫶🏽 goodluck