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-924 години
-247 днів
-4730 день
Архів дописів
A. 15
B. 20
C. 40
D. 75
10
If m∗n=(mn−nm
) for m, n belong to R, evaluate -3*4
A. −2512
B. −712
C. 712
D. 2512
11
The sum of two numbers is twice their difference. If the difference of the numbers is P, find the larger of the two numbers
A. p/2
B. 3p/2
C. 5p/2
D. 3p
12
A binary operation * is defined by a*b = ab+a+b for any real number a and b. if the identity element is zero, find the inverse of 2 under this operation.
A. 2/3
B. 1/2
C. -1/2
D. -2/3
13
Factorize completely x2+2xy+y2+3x+3y−1
8
.
A. (x+y+6)(x+y-3)
B. (x-y-6)(x-y+3)
C. (x-y+6)(x-y-3)
D. (x+y-6)(x+y+3)
14
Tope bought X oranges at N5.00 each and some mangoes at N4.00 each. if she bought twice as many mangoes as oranges and spent at least N65.00 and at most N130.00, find the range of values of X.
A. 4≤X≤5
B. 5≤X≤8
C. 5≤X≤10
D. 8≤X≤10
15
Three consecutive positive integers k, l and m are such that l2
= 3(k+m). Find the value of m.
A. 4
B. 5
C. 6
D. 7
16
Express 1x3−1
in partial fractions
A. 13(1x−1−(x+2)x2+x+1)
B. 13(1x−1−x−2x2+x+1)
C. 13(1x−1−(x−2)x2+x+1)
D. 13(1x−1−(x−1)x2−x−1)
17
The first term of a geometric progression is twice its common ratio. Find the sum of the first two terms of the G.P if its sum to infinity is 8.
A. 8/5
B. 8/3
C. 72/25
D. 56/9
18
Divide 4x3
– 3x + 1 by 2x – 1
A. 2x2-x+1
B. 2x2-x-1
C. 2x2+x+1
D. 2x2+x-1
19
Find a positive value of α
if the coordinate of the centre of a circle x2 + y2 – 2αx + 4y – α = 0 is (α
, -2) and the radius is 4 units.
A. 1
B. 2
C. 3
D. 4
20
A man 1.7m tall observes a bird on top of a tree at an angle of
30°. if the distance between the man’s head and the bird is 25m, what is the height of the tree?
A. 26.7m
B. 14.2m
C. 1.7+(253√3m
D. 1.7+(252√2m
21
In ∆MNO, MN = 6 units, MO = 4 units and NO = 12 units. If the bisector of and M meets NO at P, calculate NP.
A. 4.8 units
B. 7.2 units
C. 8.0 units
D. 18.0 units
22
Find the tangent to the acute angle between the lines 2x + y = 3 and 3x – 2y = 5.
A. -7/4
B. 7/8
C. 7/4
D. 7/2
23
From a point P, the bearings of two points Q and R are N670W and N230E respectively. If the bearing of R from Q is N680E and PQ = 150m, calculate PR
A. 120m
B. 140m
C. 150m
D. 160m
24
Find the equation of the locus of a point P(x,y) such that PV = PW, where V = (1,1) and W = (3,5)
A. 2x + 2y = 9
B. 2x + 3y = 8
C. 2x + y = 9
D. x + 2y = 8
25
Find the area bounded by the curve y = x(2-x). The x-axis, x = 0 and x = 2.
A. 4 sq units
B. 2 sq units
C. 43squnits
D. 13squnits
26
Evaluate: ∫z0(sinx−cosx)dxWhereletterz=π4.(π=pi)
A. 2+1−−−−√
B. 2–√−1
C. −2–√−1
D. 1−2–√
27
Find the volume of solid generated when the area enclosed by y = 0, y = 2x, and x = 3 is rotated about the x-axis.
A. 81 π cubic units
B. 36 π cubic units
C. 18 π cubic units
D. 9 π cubic units
28
What is the derivative of t2 sin (3t – 5) with respect to t?
A. 6t cos (3t – 5)
B. 2t sin (3t – 5) – 3t2 cos (3t – 5)
C. 2t sin (3t – 5) + 3t2 cos (3t – 5)
D. 2t sin (3t – 5) + t2 cos 3t
29
Evaluate ∫1−2(x−1)2dx
A. −103
B. 7
C. 9
D. 11
30
Find the value of x for which the function y = x3 – x has a minimum value.
A. −3–√
B. −33−−√
C. 33−−√
D. 3–√
31
If the minimum value of y = 1 + hx – 3x2 is 13, find h.
A. 13
B. 12
C. 11
D. 10
32
Let P = {1, 2, u, v, w, x}; Q = {2, 3, u, v, w, 5, 6, y} and R = {2, 3, 4, v, x, y}.
Determine (P-Q) ∩ R
A. {1, x}
B. {x y}
C. {x}
D.
.
JAMB Mathematics Questions That Will Mostly Likely Come out
1
A group of market women sell at least one of yam, plantain and maize. 12 of them sell maize, 10 sell yam and 14 sell plantain. 5 sell plantain and maize, 4 sell yam and maize, 2 sell yam and plantain only while 3 sell all the three items. How many women are in the group?
A. 25
B. 19
C. 18
D. 17
2
If log 10 to base 8 = X, evaluate log 5 to base 8 in terms of X.
A. 12
X
B. X-14
C. X-13
D. X-12
3
Find the value of X if 2√x+2√=1x−2√
A. 3√2+4
B. 3√2-4
C. 3-2√2
D. 4+2√2
4
If (a2b−3c)34a−1b4c5=apbqcr
What is the value of p+2q?
A. (5/2)
B. -(5/4)
C. -(25/4)
D. -10
5
If {(a2b-3c)3/4/a-1b4c5} = apbqcr; what is the value of p+2q?
A. (5/2)
B. -(5/4)
C. -(25/4)
D. -10
6
A trader bought 100 oranges at 5 for N1.20, 20 oranges got spoilt and the remaining were sold at 4 for N1.50. Find the percentage gain or loss.
A. 30% gain
B. 25% gain
C. 30% loss
D. 25% loss
7
What is the answer when 24346 is divided by 426?
A. 236
B. 356
C. 526
D. 556
8
If 29
x (Y3)9 = 35 x (Y3)5
, find the value of Y.
A. 4
B. 3
C. 2
D. 1
9
Simplify (0.0023×750)(0.00345×1.25)−−−−−−−−−√
Note: all multiplication and division must start from your left.
BODMAS
This is an old trick we used during our days to solve maths with out the help of anyone, so i will recommend this to you
Explanation:
B → Brackets first (parentheses)
O → Of (orders i.e. Powers and Square Roots, Cube Roots, etc.)
DM → Division
Multiplication (start from left to right)
AS → Addition and Subtraction (start from left to right)
🟥VERY VERY IMPORTANT 👂🧏 🟥
Note: Remember that your formula is your tool, so i will advise you to cram all your formula.
Before you start answering the jamb Mathematics questions make sure you read all the instructions and rules set by the board.
Once you enter the correct one, the question assigned to you will appear on the screen.
Once your Jamb mathematics question appear, I normally advise candidates to cross check the details that appear on the screen to confirm its their, else your might be answering someone else’s questions.
Dont forget the simple rules which every smart candidate always applies in any exam. What’s the rule? ” start answering the questions you know first before coming back to try your hands on the one you don’t know”
. 🔺Jamb Mathematics Questions How many questions are we to answer?🔺
You are expected to answer nothing more than 50 jamb mathematics questions.
You are not expected to go in with any scientific calculator as the board will provide one for you.
Always remember that the time is ticking and you are expected to answer all the jamb questions before the system shutdown,in such a situation you have to allocate just 3 to 4 minutes on each mathematics question.
Any question you don’t know just mark it down and quickly move over to the next ones you know.
*HERE ARE JAMB 2023 LIKELY MATHEMATICS QUESTIONS*
Get ready
👇👇👇
1. Change 71base10 to base 8
A. 107 base 8 ✔️
B. 106 base 8
C. 71 base 8
D. 17 base 8
*SOLUTION*
8|71
8|8 REM 7
8|1 REM 0
8|0 REM 1
ANSWER = 107 base 8 (A)
2. If N225.00 yields N 27.00 in x years simple interest at the rate of 4% per annum , find X
A. 3✔️
B. 4
C. 12
D. 17
*SOLUTION*
Principal = N225.00
Interest = N 27.00
Year = X
Rate = 4%
S.I = PTR / 100
27 = 225 × 4 × X / 100
T (years) = 3yrs
3. Calculate the standard deviation of the following data :
7,8,9,10,11,12,13.
A. 2✔️
B. 4
C. 10
D. 11
*SOLUTION*
Firstly find X , hence X = ( £x / N )
Ex = 7+8+9+10+11+12+13 = 70
N = 7
.°. X = 70/7 = 10
x | x – x | (x – x )²
7| -3 | 9
8| -2 | 4
9| -1 | 1
10| 0 | 1
11| 1 | 1
12| 2 | 4
13| 3 | 9
S.D = ( √£(×-×)²/N ) Note square root applies for both numerator and denominator.
= ( √£d²/N )
= √28/7
= √4 = 2 (A)
4. If y = 3t³ + 2t² – 7t + 3 , find dy/dt at t = -1
A. -1
B. 1
C. -2 ✔️
D. 2
*SOLUTION*
dy/dt = 9t² + 4t – 7
When t = -1
dy/dt = 9(-1)² + 4(-1) – 7
= 9 – 4 – 7
= -2 (C)
5. A man wishes to keep some money in a savings deposit at 25% compound interest so that after 3 years he can buy a car of N150,000 . How much does he need to deposit now ?
A. N76800.00✔️
B. N85714.28
C. N96000.00
D. N112000.50
*SOLUTION*
A =N150,000
r = 25%
n = 3
Remember A = P(1 + r/100)^n
150,000 = P ( 1 + 0.25 ) ³
150,000 = P (1.25)³
P = 150,000 / 1.25³
= N76800.00(A)
6. A trader bought goats for N4000 each. He sold them for N180,000 at a loss of 25%. How many goats did he buy ?
A. 50
B. 60✔️
C. 36
D. 45
*SOLUTION*
Loss % = (c.p – s.p)/c.p × 100%
25 = (c.p – 180,000)/c.p × 100
25 = 100(c.p – 180,000)/c.p
25 = 100cp – 18,000,000 / cp
Cross multiply
25cp = 100cp –18,000,000
18,000,000 = 100cp – 25cp
18,000,000 = 75cp
C.P = N240,000
Number of goats =
240,000 / 4000
= 60 (B)
7. The range of the data K+2 , k-3 , k+4 , k-2, k-5 , k+3 , k-1 and k+6 is
A. 11✔️
B. 10
C. 8
D. 6
*SOLUTION*
RANGE = highest – lowest
( K + 6 ) – ( K – 5 )
K + 6 – k + 5
= 11 (A)
8. What is the area between two concentric circles of diameters 26cm and 20cm ?
A. 100π
B. 169π
C. 69π✔️
D. 9π
E. 269π
*SOLUTION*
Area between two concentric circles is πR² – πr²
=π(13² – 10²)
= 69π (C)
9. Find the sum to infinity of the following series 3 + 2 + 4/3 + 8/9 + 16/27 + ____
A. 1270
B. 190
C. 18
D. 9✔️
*SOLUTION*
3 + 2 + 4/3 + 8/9 + 16/27
a = 3 , r = 2/3 ,
S∞ = a / 1 – r
= 3/1-2/3
= 9(D)
_EXAMSUCCESS
09042001981_
10. The derivative of cosec x is
A. tan x cosec x
B. – cot x cosec x✔️
C. tan x sec x
D. – cot x sec x
11. If y = ( 1 + x )² , find dy/dx
A. -1
B. 2 + 2x✔️
C. 1 + 2x
D. 2x – 1
*SOLUTION*
If y = ( 1 + x )²
dy/dx = 2( 1 + x )
= 2 + 2x (B)
12. At what rate will the interest on N400 increase to N24 in 3years reckoning in simple interest?
A. 3%
B. 2%✔️
C. 5%
D. 4%
*SOLUTION*
S.I = PTR / 100
where P denotes principal = N400
T denotes time = 3years
R denotes Rate = ?
24 = 400×3×R / 100
24×100 = 400×3×R
R = 2% (B)
13. If x*y = x + y² , find the value of ( 2*3 )*5
A. 25
B. 11
C. 55
D. 36✔️
*SOLUTION*
(2*3)*5 = (2+3²)*5
= (2+9)*5
= 11*5
Hence 11*5 = 11+5²
= 11+25
= 36(D)
14. Simplify ( √6 + 2 )² ( √6 – 2 )²
A. 2√6
B. 4√6
C. 8√6✔️
D. 16√6
*SOLUTION*
( √6 + 2 )² (√6 – 2 )²
(√6 + 2 + √6 – 2)(√6 + 2 -√6 + 2)
(2√6 ) (4)
= 8√6 (C)
XamGod SolutioN Team
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~EXAMGOD~ ,we lead why others follow`JAMB ROLLS OUT NEW GUIDELINES FOR 2024 DIRECT ENTRY REGISTRATION
As part of the efforts to ensure a seamless 2024 Direct Entry registration, the Joint Admissions and Matriculation Board(JAMB) has putin place a series of critical and practical measures aimed at further fine-tuning the exercise. The Board, at a virtual meeting with the Nigeria Integrated Secondary Education Data System (NIPEDS),the JAMB Professional Registration Centres (PRCs) and service providers held on Wednesday, 12th March, 2024, said the various measures were aimed at perfecting and addressing some challenges and issues arising from the ongoing 2024 DE registration exercise nationwide. In his remarks on the occasion, the Chairman, NIPEDS, Prof. Yahuza Bello, commended the Registrar, Prof. Is-haq Oloyede for his passion and commitment to education, particularly as it relates to the selection of top-notch candidates for admission into tertiary institutions. Prof. Bello expressed appreciation to the Registrar for his support and his timely response to addressing some teething problems associated with the verification of A'level results and other concerns as they relate to DE registration. Earlier, while declaring open the meeting, the Registrar cautioned PRCs to work according to guidelines and laid down rules and regulations governing the registration exercise. He urged them to work with the institutional lists made available to them, adding that the names must be in line with the ones emanating from JAMB. In essence, the names regiatered with JAMB must correspond with those provided by the institutions, like IJMB, JUPEB, etc.
While warning against criminal alterations of candidates' data, he stressed that whatever is approved for institutions is what they should upload.The Registrar also reminded the PRCs to ensure that they uploaded the appropriate statement of results and the approved year of graduation. He stated that for the years 2021, 2022, 2023, statements of results can be accepted in lieu of certificates while awaiting result status is only admissible with respect to applications emanating specifically from 2024 graduates. In his contribution, the IT Consultant, Mr. Damilola Bamiro said with respect to questions on qualifications, the Board had listed 12 A' level qualifications for consideration for DE registration and advised applicants to take cognisance of the series of advertisements in both print and social media on the 2024 DE registration. Furthermore, he disclosed that as a proactive body, the Board had resolved various issues arising from previous registration exercises. These, he said included but not limited to: error messages, invalid emails, incoherent names and certificates, incompatible admission letters and subject combination, non-inclusion of IEls certificates, among others, all of which he stated, had been resolved.
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*ONCE THE 2024 TIMETABLE FOR SCHOOL WAEC AND NECO IS OFFICIALLY OUT, I WILL INFORM YOU ALL IMMEDIATELY*
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Today is the final day for the correction of UTME wrong subject combination , so kindly go and do your correction now (today) if you make any mistake with your subjects combination , I don't want to here story in my dm after jamb examination ,
Take note ,even if you like score 400/400 in your jamb , with wrong subject combination no uni will admit you .
*TAKE NOTE*
Printing of 2024 UTME Examination Slips: 10th April, 2024.
`
2024 UTME Examination Date: Friday 19th April to Monday 29th April, 2024.🔊🔊🔊🔊🔊🔊🔊🔊🔊🔊
*📍Note: OUR THESE YEAR 2024 WAEC ,NECO AND NABTEB EXPO PAYMENT IS ACTIVELY ONGOING NOW📛*
🔊🔊🔊🔊🔊🔊🔊🔊🔊
👇👇👇
*RAMADAN SPECIAL PROMO HAS OFFICIALLY STARTED TODAY AND WILL END ON APRIL 13th OF NEXT MONTH 🧏🔊🔊*
✅ _All 2024 WAEC QUESTIONNS and answers Ramadan promo price👉N6,000# only_
_*✅ All 2024 NECO QUESTIONNS AND answer Ramadan promo price👉 N6,000# only_
_*✅All 2024 NABTEB questionns and answeres promo price 👉*N6,000# only_
*make your payment NOW Because once the promo deadline reach the price will go up to the initial price of 19000#*
*IMMEDIATELY AFTER YOUR PAYMENT, YOU WILL BE ADDED TO OUR VIP BROADCAST LIST ,WHERE YOU WILL GET QUESTION AND ANSWERS TO YOUR EXAMS*
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~EXAMGOD~ ,we lead why others follow`