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2) => 2×(2^2y) -5(2^y)+2=0
Put 2^y=a
=> 2a²-5a+2=0
Solving quadratically,
a= 1/2 or 2
=> 2^y=1/2 or 2
=> 2^y=2-¹ or 2¹
Comparing both sides,
=> y=-1 or 1
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