Oldin Matematika, keyin barchasi!

Uchta merganning o'qni nishonga tekkizish ehtimollari mos ravishda 0.4 0.7 va 0.8 ga teng. Demak P(a)=0.4 P(b)=0.7 va P(c)=0.8 Bu merganlar baravariga o'q uzganda: Savol: 1. Hech birining nishonga tekkiza olmaslik ehtimolini toping. Yechim: P(d)=[1-P(a)]•[1-P(b)]•[1-P(c)]=0.6•0.3•0.2=0.036 2. Uchalasining ham o'qni nishonga tekkizish ehtimolini toping. Yechim: P(f)=P(a)•P(b)•P(c)=0.4•0.7•0.8=0.224 3. Birinchi mergan nishonga tekkizib, ikkinchi va uchinchi merganlar nishonga tekkiza olmaslik ehtimolini toping. Yechim: P(g)=P(a)•[1-P(b)]•[1-P(c)]=0.4•0.3•0.2=0.024 4. Ikkinchi merganniki tegib birinchi va uchinchi merganniki tegmaslik ehtimoli P(h)=[1-P(a)]•P(b)•[1-P(c)] 5. Uchinchi merganniki tegib, birinchi va ikkinchi merganniki tegmaslik ehtimoli P(j)=[1-P(a)]•[1-P(b)]•P(c) 6.Birinchi va ikkinchi merganniki tegib, uchinchi merganniki tegmaslik ehtimoli P(k)=P(a)•P(b)•[1-P(c)] 7. Birinchi va uchinchi merganniki tegib, ikkinchi merganniki tegmaslik ehtimoli P(l)=P(a)•[1-P(b)]•P(c) 8. Ikkinchi va uchinchi merganniki tegib, birinchi merganniki tegmaslik ehtimoli P(z)=[1-P(a)]•P(b)•P(c) 9. Aniq (faqat) bittasiniki nishonga tegish ehtimoli P(x)=P(g)+P(h)+P(j) 10. Hech bo'lmaganda ( kamida) bittasining nishonga tekkizish ehtimoli P(v)=1-P(d) 11.Aniq (faqat) 2 tasining nishonga tekkizish ehtimoli P(n)=P(k)+P(l)+P(z) 12. Hech bo'lmaganda ( kamida) ikkitasining nishonga tekkizish ehtimoli P(m)=P(n)+P(f) Kanalimizga ulanish uchun 👇👇👇👇👇👇👇👇 @mat_fiz_inf_olami

❓Integralni hisoblashga qiynalyapsizmi? ✅ Unda bu dastur siz uchun. Oʻqituvchilar, talabalar va abituriyentlar uchun juda muhim dastur. ✍ Ishlanish yoʻligacha koʻrsatib beradi. 👉 @studyandmath