C Programming Language || Hands On Coding
Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii
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Канал C Programming Language || Hands On Coding (@c_programming_language_coding) языкового сегмента Английский является активным участником. Сейчас сообщество объединяет 12 821 подписчиков, занимая 9 572 место в категории Технологии и приложения и 31 202 место в регионе Индия.
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С момента создания невідомо проект демонстрирует стремительный рост, собрав аудиторию из 12 821 подписчиков.
Согласно последним данным от 28 августа, 2026, канал показывает стабильную активность. За последние 30 дней изменение числа участников составило -213, а за последние 24 часа — -1, при этом общий охват остаётся высоким.
- Статус верификации: Не верифицирован
- Уровень вовлечённости (ER): Средний показатель вовлечённости аудитории составляет 6.87%. В первые 24 часа после публикации контент обычно набирает 2.42% реакций от общего числа подписчиков.
- Охват публикаций: В среднем каждый пост получает 881 просмотров. В течение первых суток публикация набирает 310 просмотров.
- Реакции и взаимодействия: Аудитория активно поддерживает контент: среднее количество реакций на один пост — 2.
- Тематические интересы: Контент сосредоточен на ключевых темах, таких как input, string, scanf("%d, array, element.
📝 Описание и контентная политика
Автор описывает ресурс как площадку для выражения субъективного мнения:
“Hands-on C programming language challenges for beginners. Learn building logic by solving programs.
Owner: @Pradeep_saii”
Благодаря высокой частоте обновлений (последние данные получены 29 августа, 2026) канал поддерживает актуальность и высокий уровень охвата публикаций. Аналитика показывает, что аудитория активно взаимодействует с контентом, что делает его важной точкой влияния в категории Технологии и приложения.
const qualifier for constants
#include <stdio.h>
int main() {
const int meaningOfLife = 42;
const float pi = 3.14159;
const char initial = 'J';
printf("The meaning of life: %dn", meaningOfLife);
printf("The value of pi: %fn", pi);
printf("My initial: %cn", initial);
int radius = 5;
float area = pi * radius * radius;
printf("Area of a circle with radius %d: %fn", radius, area);
return 0;
}const keyword. Before declaring the variable, use the const keyword to indicate that the variable's value cannot be changed after initialization. Specify the data type (e.g., int, float, char) before const.
Step 2: Initialize the constant variable. Assign a value to the const variable at the time of its declaration. This is mandatory as you cannot change its value later.
Step 3: Use the constant variable in your program. Utilize the constant variable as needed within your program's logic, just like any other variable, but remember you can't modify it.
Step 4: Compile and run the code. The compiler will flag an error if you attempt to modify a const variable after its initialization.
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❤️ Understood | 👎 Not Understoodconst qualifier for constants
Write a C program that calculates the area of a circle. Define the value of PI as a constant using the const qualifier. The program should take the radius as input from the user and print the calculated area.\n (newline), \t (tab), \b (backspace), \\ (backslash), \" (double quote), \' (single quote), and \r (carriage return). Understand how they are used to represent special characters within strings.
Step 2: Write Basic printf Statements: Start with simple printf statements that print strings without using any escape sequences. For example: printf("Hello, world!\n");. This establishes a baseline.
Step 3: Introduce Escape Sequences in printf: Modify the printf statements to incorporate different escape sequences. Example: printf("Hello\tworld!\n"); (using tab). Observe the output and understand how the escape sequence affects it.
Step 4: Experiment with Combinations: Combine multiple escape sequences in a single printf statement to create more complex formatting. Example: printf("This is a string with \"quotes\" and a backslash \\.\n");. Pay close attention to the output.
Step 5: Use scanf (If Needed): If you need to accept input containing characters that need to be represented using escape sequences, you can use scanf. Be aware that scanf handles escape sequences automatically, so you don't typically need to input \ followed by a character. The main use in input is handling \n if necessary. Example: While less common, you can use scanf(" %[^\n]s", string); to read a line including spaces but will also include \n.
Step 6: Test and Verify: Compile and run your code, carefully examining the output to ensure the escape sequences are working as expected. Adjust the escape sequence usage until the desired output is achieved.
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Write a C program that demonstrates the use of common escape sequences like \t (tab), \b (backspace), \" (double quote), \\ (backslash), and \n (newline) within a string literal. The program should output the modified string to the console, showcasing the effects of each escape sequence.float) to another data type (e.g., int) explicitly using type casting.
Step 2: Declare Variables: Declare the variable you want to convert and the variable where you will store the converted value. Make sure they are of the appropriate types.
Step 3: Perform Type Casting: Use the following syntax: (data_type) variable_to_convert. For example, to convert a float named myFloat to an integer, you would write (int) myFloat.
Step 4: Assign the Result: Assign the result of the type cast operation to the variable that will hold the converted value. For example: myInt = (int) myFloat;.
Step 5: Print the Result: Use printf to display the value of the converted variable, confirming the explicit type conversion.
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❤️ Understood | 👎 Not Understoodint to float.
Step 4: Print the value of both the integer and float variables using printf. This displays the original integer value and the converted float value, allowing you to see the effect of the implicit conversion.
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❤️ Understood | 👎 Not Understoodint, float, double, char using sizeof operator
#include <stdio.h>
int main() {
size_t int_size = sizeof(int);
size_t float_size = sizeof(float);
size_t double_size = sizeof(double);
size_t char_size = sizeof(char);
printf("Size of int: %zu bytesn", int_size);
printf("Size of float: %zu bytesn", float_size);
printf("Size of double: %zu bytesn", double_size);
printf("Size of char: %zu bytesn", char_size);
return 0;
}printf function for displaying the sizes.
Step 2: Use the sizeof operator to determine the size of each data type. The sizeof operator returns the size (in bytes) of a variable or data type. Apply it to int, float, double, and char.
Step 3: Use printf to print the sizes of each data type. The printf function is used to display the size of each data type to the console. Use the format specifier %zu (or %lu for older compilers that don't fully support %zu) to print the size_t (or unsigned long) value returned by sizeof. Also include descriptive text for each output.
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❤️ Understood | 👎 Not Understoodint, float, double, char using sizeof operator
Write a C program to determine and print the sizes (in bytes) of the fundamental data types int, float, double, and char. Utilize the sizeof operator to obtain the size of each data type and display the results to the console.