ru
Feedback

Не попадитесь на канал ботавода! Telemetrio находит и помечает такие каналы 👉 Хотите видеть метку — оформите подписку

ACCENTURE EXAM SOLUTIONS

ACCENTURE EXAM SOLUTIONS

Открыть в Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

Больше

📈 Аналитический обзор Telegram-канала ACCENTURE EXAM SOLUTIONS

Канал ACCENTURE EXAM SOLUTIONS (@coding_are) языкового сегмента Английский является активным участником. Сейчас сообщество объединяет 14 041 подписчиков, занимая 14 513 место в категории Образование и 28 436 место в регионе Индия.

📊 Показатели аудитории и динамика

С момента создания невідомо проект демонстрирует стремительный рост, собрав аудиторию из 14 041 подписчиков.

Согласно последним данным от 13 октября, 2026, канал показывает стабильную активность. За последние 30 дней изменение числа участников составило -124, а за последние 24 часа — -6, при этом общий охват остаётся высоким.

  • Статус верификации: Не верифицирован
  • Уровень вовлечённости (ER): Средний показатель вовлечённости аудитории составляет 3.63%. В первые 24 часа после публикации контент обычно набирает 1.83% реакций от общего числа подписчиков.
  • Охват публикаций: В среднем каждый пост получает 510 просмотров. В течение первых суток публикация набирает 257 просмотров.
  • Реакции и взаимодействия: Аудитория активно поддерживает контент: среднее количество реакций на один пост — 2.
  • Тематические интересы: Контент сосредоточен на ключевых темах, таких как placement, gaurntee, suree, capgemini, infosy.

📝 Описание и контентная политика

Автор описывает ресурс как площадку для выражения субъективного мнения:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Благодаря высокой частоте обновлений (последние данные получены 14 октября, 2026) канал поддерживает актуальность и высокий уровень охвата публикаций. Аналитика показывает, что аудитория активно взаимодействует с контентом, что делает его важной точкой влияния в категории Образование.

14 040
Подписчики
-624 часа
-377 дней
-12430 дней
Архив постов
----- PICK UP SERVICE ----- from collections import defaultdict def pick_up_service(N, start, connections):     graph = defaultdict(list)          taxes = defaultdict(int)     for i in range(N - 1):         city1, city2, goods, tax = connections[i]         # graph[city1].update({city2: (goods, tax)})         # graph[city2].update({city1: (goods, tax)})         graph[city1].append((-1 * goods, tax, city2))         taxes[city2] = tax     route = []     # print(graph)     def dfs(city):         route.append(city)         for n in sorted(graph[city]):             dfs(n[2])             route.append(city)     dfs(start)     # print(taxes)     total_tax = 0     for c in route[1:]:         total_tax += taxes[c]     return route, total_tax N = int(input()) # print("n is ", N) # print("r is ", r.split('\n')) cons = [] for _ in range(N-1):     l = input()     ls = l.split()     cons.append((ls[0], ls[1], int(ls[2]), int(ls[3])))    ans, t = pick_up_service(N, cons[0][0], cons) print("-".join(ans)) print(t, end="") PICKUP SERVICE CODE TCS CODEVITA SOLUTIONS Python3 SHARE ✅✅ @codeing_area @codeing_area

----- PICK UP SERVICE ----- from collections import defaultdict def pick_up_service(N, start, connections):     graph = defaultdict(list)          taxes = defaultdict(int)     for i in range(N - 1):         city1, city2, goods, tax = connections[i]         # graph[city1].update({city2: (goods, tax)})         # graph[city2].update({city1: (goods, tax)})         graph[city1].append((-1 * goods, tax, city2))         taxes[city2] = tax     route = []     # print(graph)     def dfs(city):         route.append(city)         for n in sorted(graph[city]):             dfs(n[2])             route.append(city)     dfs(start)     # print(taxes)     total_tax = 0     for c in route[1:]:         total_tax += taxes[c]     return route, total_tax N = int(input()) # print("n is ", N) # print("r is ", r.split('\n')) cons = [] for _ in range(N-1):     l = input()     ls = l.split()     cons.append((ls[0], ls[1], int(ls[2]), int(ls[3])))    ans, t = pick_up_service(N, cons[0][0], cons) print("-".join(ans)) print(t, end="") PICKUP SERVICE CODE TCS CODEVITA SOLUTIONS Python3 SHARE ✅✅ @codeing_area

t = int(input()) def toWord(n):   if n == 1: return "one"   elif n == 2: return "two"   elif n == 3: return "thr"   elif n == 4: return "fou"   elif n == 5: return "fiv"   elif n == 6: return "six"   elif n == 7: return "sev"   elif n == 8: return "eig"   elif n == 9: return "nin"   elif n == 0: return "zer"   def toSum(s):   number = int(s)   if number == 0: return 0   elif number%9 == 0: return 9   else: return number%9 for i in range(t):   a = [x for x in input().split()]   n = a[0]   name = a[1]   d1 = 0   if "." in n:     d1 = n.index('.')   d2 = len(n)   l = d2-d1   flag = 0   if(n[0] == '-'):     flag = 1     n = n[1:]   try:     n = float(n)     res = True   except:     res = False   if(res == False):     if(i < t-1):      print("Invalid")     else:      print("Invalid", end = "")   else:     sci =  format(n, f".{l}e")     part = sci.split('e')     num = part[0].split('.')     k = int(part[1])     if(flag == 1): res = "-"     else: res = ""     res += toWord(int(num[0])) +"."+toWord(toSum(num[1])) +"e"     if(k > 0):         res += '+'     elif(k<0): res += '-'     res += toWord(abs(int(part[1]))) +"@"     if(k%2 != 0):       for x in range(0,len(name),2):         res += name[x]     else:       for x in range(1,len(name),2):         res += name[x]         if(i < t-1):      print(res)     else:      print(res, end="") Password Generator only public case working

I am not asking money 💰💰 We want share my group everyone Then I will share all correct 💯 code very soon Share @codeing_area Share ✅ share✅ share✅

Broo now share everyone ✅✅✅✅✅ I am posted all correct answer ✅👍👍 Share @codeing_area

Proof everyone
Proof everyone

Share share ✅✅✅✅☺️

Fully paased ✅🎉🎉🎉🎉🎉🎉✅💯💯

import math def calculate_distance(point1, point2):     return abs(point1[0] - point2[0]) + abs(point1[1] - point2[1]) def assign_vehicles(passengers, vehicles):     allocated_vehicles = {}     total_distance = 0     for passenger in sorted(passengers):         min_distance = math.inf         closest_vehicle = ""         passenger_coordinates = passengers[passenger]         for vehicle in vehicles:             if vehicles[vehicle] == "":                 vehicle_coordinates = vehicles[vehicle + "_coordinates"]                 distance = calculate_distance(passenger_coordinates, vehicle_coordinates)                 if distance < min_distance or (distance == min_distance and vehicle < closest_vehicle):                     min_distance = distance                     closest_vehicle = vehicle                 allocated_vehicles[passenger] = closest_vehicle         vehicles[closest_vehicle] = passenger         total_distance += min_distance     return total_distance N, M = map(int, input().split()) passengers = {} vehicles = {} for _ in range(N):     name, x, y = input().split()     passengers[name] = (int(x), int(y)) for _ in range(M):     vehicle, x, y = input().split()     vehicles[vehicle] = ""     vehicles[vehicle + "_coordinates"] = (int(x), int(y)) minimum_distance = assign_vehicles(passengers, vehicles) print(minimum_distance,end="") Solo rider✅✅ Python 3 @codeing_area ✅✅✅ Share share ✅✅✅✅

@
@

Next code will upload soon....✅✅

Share group everyone fastttt✅✅✅✅ @codeing_area

photo content

Warehouse Fully paased ✅💯👍
Warehouse Fully paased ✅💯👍

def generate_password(number, name):     # Check if name consists of only lowercase letters     if name.isalpha() and name.islower():         # Convert number to absolute value to handle negative numbers         abs_number = abs(number)                 # Ensure length of name is within the specified range         name_length = min(max(len(name), 1), 100)                 # Generate password using a combination of number and name         password = str(abs_number) + name[:name_length]         return password     else:         return "Invalid" try:     # Input: Number of test cases     T = int(input())     # Process each test case     for _ in range(T):         # Input: Number and Name separated by space         test_input = input().split()         if len(test_input) == 2:             number = int(test_input[0])             name = test_input[1]             # Output: Print the password for each test case in a new line             result = generate_password(number, name)             print(result)         else:             print("Invalid input format") except Exception as e:     print("An error occurred:", e) password generator updated all passed

def minVehicles(weights, limit): weights.sort() # Sort the weights in ascending order left, right = 0, len(weights) - 1 vehicles = 0 while left <= right: if weights[left] + weights[right] <= limit: left += 1 right -= 1 vehicles += 1 return vehicles # Python 3 compatibility try: # Python 3 raw_input = input except NameError: # Python 2 pass weights = list(map(int, raw_input().split())) limit = int(raw_input()) result = minVehicles(weights, limit) # Output the result without extra spaces or newline characters print(result, end="") Warehouse public passed ✅✅✅... python 3 Shared @codeing_area fastt everyone

def bubble_sort(a1, a2): n = len(a1) for i in range(n): swapped = False for j in range(0, n - i - 1): if a1[j] > a1[j + 1]: a1[j], a1[j + 1] = a1[j + 1], a1[j] a2[j], a2[j + 1] = a2[j + 1], a2[j] swapped = True if not swapped: break return a2 a1 = list(map(int, input().split())) a2 = list(map(int, input().split())) result = bubble_sort(a1, a2) print(*result) Bubble sort in python Full working ✅💯💯💯💯 Share @codeing_area

I will post all code after 10am 💯💯 So don't worry everyonee ✅✅✅ Share @codeing_are Fastt

Sahre fasttt everyone group I am not asking money....you need to sahare group only

photo content