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Codeforces|Leetcode|Codechef free solutions

Codeforces|Leetcode|Codechef free solutions

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Free codeforces, Codechef, Leetcode solutions are available 😍😍😍😍😍😍 Helped More than 200+ students to crack coding round in 2022 and helped placed them in Good companies. 🥳🥳🥳🤩🤩🤩 Dm @Cpsoln if you want help in coding round.

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Oracle codes available Dm @Cpsoln

Futures first slots available

Oracle slots available Dm @Cpsoln

C will be posted for free after 4150 subscribers

If you want oa help in any company Dm @Cpsoln

We will upload more codes for free just subscribe and share channel link with your friends😊😊😊

Just copy paste

H1 code guys🥳🥳🥳

include <bits/stdc++.h> using namespace std; const int MAX_N = 1000000 + 100; int n, m; unordered_map<int, char> grid[MAX_N]; unordered_map<int, int> component_id[MAX_N]; unordered_map<int, int> component_size; int curr_id; #define ll long long int dfs(int i, int j) { if (i < 0 || i >= n || j < 0 || j >= m || grid[i][j] == '.' || component_id[i][j] != -1) { return 0; } component_id[i][j] = curr_id; int size = 1; size += dfs(i - 1, j); size += dfs(i + 1, j); size += dfs(i, j - 1); size += dfs(i, j + 1); return size; } int main() { int t; cin >> t; while (t--) { cin >> n >> m; component_size.clear(); for (int i = 0; i < n; i++) { for (int j = 0; j < m; j++) { cin >> grid[i][j]; component_id[i][j] = -1; } } curr_id = 1; int ans = 0; for (int i = 0; i < n; i++) { for (int j = 0; j < m; j++) { if (grid[i][j] == '#' && component_id[i][j] == -1) { component_size[curr_id] = dfs(i, j); ans = max(ans, component_size[curr_id]); curr_id++; } } } int max_size = ans; for (int i = 0; i < n; i++) { int extra = 0; unordered_set<int> s; for (int j = 0; j < m; j++) { if (grid[i][j] == '#') { s.insert(component_id[i][j]); } else { extra++; // checking any other component is present in the same row or column // check up down left and right of the current cell if (i > 0 && grid[i - 1][j] == '#') { s.insert(component_id[i - 1][j]); } if (i < n - 1 && grid[i + 1][j] == '#') { s.insert(component_id[i + 1][j]); } if (j > 0 && grid[i][j - 1] == '#') { s.insert(component_id[i][j - 1]); } if (j < m - 1 && grid[i][j + 1] == '#') { s.insert(component_id[i][j + 1]); } } } auto it = s.begin(); while (it != s.end()) { extra += component_size[*it]; it++; } max_size = max(max_size, extra); } // do this for column also for (int j = 0; j < m; j++) { int extra = 0; unordered_set<int> s; for (int i = 0; i < n; i++) { if (grid[i][j] == '#') { s.insert(component_id[i][j]); } else { extra++; // checking any other component is present in the same row or column // check up down left and right of the current cell if (i > 0 && grid[i - 1][j] == '#') { s.insert(component_id[i - 1][j]); } if (i < n - 1 && grid[i + 1][j] == '#') { s.insert(component_id[i + 1][j]); } if (j > 0 && grid[i][j - 1] == '#') { s.insert(component_id[i][j - 1]); } if (j < m - 1 && grid[i][j + 1] == '#') { s.insert(component_id[i][j + 1]); } } } auto it = s.begin(); while (it != s.end()) { extra += component_size[*it]; it++; } max_size = max(max_size, extra); } cout << max_size << endl; } return 0; }

As I promised you I have uploaded both codes😊😊

Codeforces F 🥳🥳🥳🥳

#include <bits/stdc++.h> using namespace std; typedef long long ll; ll H; bool check(vector<ll> &a, vector<ll> &b, ll val) { ll dmg = 0; for(int i=0; i<a.size(); i++) { ll curDmg = ((val/b[i])+1)*a[i]; dmg += curDmg; if(dmg >= H) return true; } return dmg >= H; } void sol() { ll h, n; cin >> h >> n; H = h; vector<ll> a(n), c(n); for(int i=0; i<n; i++) { cin >> a[i]; } for(int i=0; i<n; i++) { cin >> c[i]; } ll lo = 0; ll hi = 1e12; while(hi - lo > 1) { ll mid = (lo+hi)/2; if(check(a, c, mid)) { hi = mid; }else { lo = mid; } } if(check(a, c, lo)) { cout << lo+1 << endl; return; } cout << hi+1 << endl; } int main() { int t = 1; cin >> t; while(t--) sol(); return 0; }

We will post F soon after 3930 subscribers😁😁

Codeforces E code 🥳🥳🥳🥳🥳

#include <iostream> #include<bits/stdc++.h> #define int long long using namespace std; #define pb push_back void sol(){ int x,y,z,k; cin>>x>>y>>z>>k; int count = 0; for(int i = 1;i<=x;i++){   for(int j = 1;j<=y;j++){     if(k%(i*j)==0&&(k/(i*j)<=z)){       count=max(count,(x-i+1)*(y-j+1)*(z-(k/(i*j))+1));     }   } } cout<<count<<endl;   return; } signed main() {     int test;   cin>>test;   while(test--){     sol();   }        return 0; }

F also done ✅✅✅

So share the channel with your friends..

After 1920 subscribers I will post E code for free in this channel

Dm @Cpsoln for cheap rate

Codeforces A B C D E done ✅✅✅✅