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public static void arrayManipulation(int n, List arr,int q, List> qarr)      {         HashMap mp = new HashMap();         ArrayList ans = new ArrayList();         int flg = 1;         for (int i = 0; i < n; i++)         {             mp.put(arr.get(i), i);         }         for (int i = 0; i < q; i++)         {             List a = qarr.get(i);                         if (a.get(0) == 1)                 flg *= -1;                         else if (a.get(0) == 2)             {                 int x = a.get(1);                 if (flg == -1)                     ans.add(n - mp.get(x) - 1);                 else                     ans.add(mp.get(x));             }                         else             {                 int x = a.get(1);                 int y = a.get(2);                                                 int x1 = a.get(1);                 int y1 = a.get(2);                 if (flg == -1)                 {                     y = n - y - 1;                     x = n - x - 1;                 }                                 y = arr.get(y);                 x = arr.get(x);                                 int temp = arr.get(x1);                 arr.set(x1, arr.get(y1));                 arr.set(y1, temp);                 mp.put(x, mp.get(y));                 mp.put(y, temp);             }         }                 for (int x : ans)         {           if(x==-1) x = 0;             System.out.print(x + " ");         }     }

XOR Subsequences Python def bit_count(x):     cnt = 0     while x > 0:         cnt += x & 1         x >>= 1     return cnt n = int(input()) a = list(map(int, input().split())) dp = [set() for i in range(n)] dp[0].add((a[0],)) ans = 0 for i in range(1, n):     dp[i].add((a[i],))     for b in dp[i-1]:         if a[i] > b[-1]:             b2 = b + (a[i],)             dp[i].add(b2)         if len(b) > 1 and bit_count(b[-2] ^ b[-1]) == bit_count(b[-2] ^ a[i]):             b2 = b[:-1] + (a[i],)             dp[i].add(b2)     for b in dp[i]:         x = b[0]         for j in range(1, len(b)):             x ^= b[j]         ans |= x print(bin(ans).count('1'))

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XOR Subsequences Python Trilogy Innovations def bit_count(x):     cnt = 0     while x > 0:         cnt += x & 1         x >>= 1     return cnt n = int(input()) a = list(map(int, input().split())) dp = [set() for i in range(n)] dp[0].add((a[0],)) ans = 0 for i in range(1, n):     dp[i].add((a[i],))     for b in dp[i-1]:         if a[i] > b[-1]:             b2 = b + (a[i],)             dp[i].add(b2)         if len(b) > 1 and bit_count(b[-2] ^ b[-1]) == bit_count(b[-2] ^ a[i]):             b2 = b[:-1] + (a[i],)             dp[i].add(b2)     for b in dp[i]:         x = b[0]         for j in range(1, len(b)):             x ^= b[j]         ans |= x print(bin(ans).count('1')) XOR Subsequences Python Trilogy Innovations

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Good Arrays Code int n = arr.size();     int A = arr[0];     int B = arr[n-1];     int k = 0;     for (int i = 1; i < n-1; i++) {         if (arr[i] > A) {             k++;         }     }     long long ways = 1;     for (int i = 1; i <= k; i++) {         ways = (ways * i) % 1000000007;     }     return ways;

#include <bits/stdc++.h> using namespace std; int count_ways_to_make_array_good(vector<int>& arr) {     int n = arr.size();     int A = arr[0];     int B = arr[n-1];     int k = 0;     for (int i = 1; i < n-1; i++) {         if (arr[i] > A) {             k++;         }     }     long long ways = 1;     for (int i = 1; i <= k; i++) {         ways = (ways * i) % 1000000007;     }     return ways; } int main() {     int n;     cin >> n;     vector<int> arr(n);     for (int i = 0; i < n; i++) {         cin >> arr[i];     }     int ans = count_ways_to_make_array_good(arr);     cout << ans << endl;     return 0; } Good array C++✅ Share our channel to ur frd..❤️😁

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n = int(input()) j=1 print(chr(26-n+97)) for i in range(26-n,25): print(chr(i+1+97)*j + chr(i+97)) j+=1 Python✅

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