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Codehub

Codehub

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📈 Аналитический обзор Telegram-канала Codehub

Канал Codehub (@pythonadvisorai) языкового сегмента Английский является активным участником. Сейчас сообщество объединяет 31 531 подписчиков, занимая 4 219 место в категории Технологии и приложения и 1 037 место в регионе Малайзия.

📊 Показатели аудитории и динамика

С момента создания невідомо проект демонстрирует стремительный рост, собрав аудиторию из 31 531 подписчиков.

Согласно последним данным от 27 октября, 2026, канал показывает стабильную активность. За последние 30 дней изменение числа участников составило -436, а за последние 24 часа — -9, при этом общий охват остаётся высоким.

  • Статус верификации: Не верифицирован
  • Уровень вовлечённости (ER): Средний показатель вовлечённости аудитории составляет 7.54%. В первые 24 часа после публикации контент обычно набирает N/A% реакций от общего числа подписчиков.
  • Охват публикаций: В среднем каждый пост получает 0 просмотров. В течение первых суток публикация набирает 0 просмотров.
  • Реакции и взаимодействия: Аудитория активно поддерживает контент: среднее количество реакций на один пост — 0.

📝 Описание и контентная политика

Автор описывает ресурс как площадку для выражения субъективного мнения:
“Free Programming resources.”

Благодаря высокой частоте обновлений (последние данные получены 28 октября, 2026) канал поддерживает актуальность и высокий уровень охвата публикаций. Аналитика показывает, что аудитория активно взаимодействует с контентом, что делает его важной точкой влияния в категории Технологии и приложения.

31 531
Подписчики
-924 часа
-1027 дней
-43630 дней
Архив постов
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is a roadmap for becoming a full stack developer in 200 days..","articleBody":"Here is a roadmap for becoming a full stack developer in 200 days..","datePublished":"2023-02-04T12:50:33Z","dateModified":"2023-02-04T12:50:40Z","author":{"@type":"Organization","name":"Codehub","url":"https://telemetr.io/ru/channels/1320428598-pythonadvisorai","image":"https://img.telemetr.io/c/1rmnNs/6105153474644348728?ty=x"},"publisher":{"@type":"Organization","name":"Codehub","url":"https://telemetr.io/ru/channels/1320428598-pythonadvisorai","image":"https://img.telemetr.io/c/1rmnNs/6105153474644348728?ty=x"},"commentCount":0,"interactionStatistic":[{"@type":"InteractionCounter","interactionType":"https://schema.org/ViewAction","userInteractionCount":1}]}},{"@type":"ListItem","position":19,"item":{"@type":"SocialMediaPosting","@id":"https://telemetr.io/ru/channels/1320428598-pythonadvisorai/posts/716","url":"https://telemetr.io/ru/channels/1320428598-pythonadvisorai/posts/716","mainEntityOfPage":"https://telemetr.io/ru/channels/1320428598-pythonadvisorai/posts/716","headline":"A step by step guide to make money with ChatGpt 🤑👇 https://medium.com/@inprogrammer/make-money-with-chatgpt-b…","articleBody":"A step by step guide to make money with ChatGpt 🤑👇\nhttps://medium.com/@inprogrammer/make-money-with-chatgpt-bd80d33e7406","datePublished":"2023-02-04T07:40:23Z","dateModified":"2023-02-04T07:40:23Z","author":{"@type":"Organization","name":"Codehub","url":"https://telemetr.io/ru/channels/1320428598-pythonadvisorai","image":"https://img.telemetr.io/c/1rmnNs/6105153474644348728?ty=x"},"publisher":{"@type":"Organization","name":"Codehub","url":"https://telemetr.io/ru/channels/1320428598-pythonadvisorai","image":"https://img.telemetr.io/c/1rmnNs/6105153474644348728?ty=x"},"commentCount":0,"interactionStatistic":[{"@type":"InteractionCounter","interactionType":"https://schema.org/ViewAction","userInteractionCount":8638},{"@type":"InteractionCounter","interactionType":"https://schema.org/ShareAction","userInteractionCount":36}]}},{"@type":"ListItem","position":20,"item":{"@type":"SocialMediaPosting","@id":"https://telemetr.io/ru/channels/1320428598-pythonadvisorai/posts/715","url":"https://telemetr.io/ru/channels/1320428598-pythonadvisorai/posts/715","mainEntityOfPage":"https://telemetr.io/ru/channels/1320428598-pythonadvisorai/posts/715","headline":"A 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Codehub
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Codehub
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Doraemon (1).py0.04 KB

Codehub
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photo content

Codehub
31 531
Which one of the following is not a keyword in Python language?
Anonymous voting

Codehub
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import turtle screen = turtle.Screen() screen.setup(550, 600, startx=0, starty=100) t = turtle.Turtle() turtle.bgcolor('black') turtle.color('yellow') turtle.speed(11) turtle.right (45) for i in range(150): turtle.circle(25) if 7 < i < 62: turtle. left(5) if 80 < i < 133: turtle.right(5) if i < 80: turtle.forward(10) else: turtle.forward(5)

Codehub
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Learn for Free🧑‍💻😍
Learn for Free🧑‍💻😍

Codehub
31 531
What will be the output of this function? >>round (4.576)
Anonymous voting

Codehub
31 531
Important DSA important questions.
+7
Important DSA important questions.

Codehub
31 531
You want DSA important questions. 😇
Anonymous voting

Codehub
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import turtle gg = turtle.Turtle() turtle.bgcolor("black") gg.color("#4285F4","#4285F4") gg.pensize(5) #gg.speed(0) # [ google color codes ] # red = #DB4437 # blue = #4285F4 # green = #0F9D58 # yellow = #F4B400 def google(): gg.forward(120) gg.right(90) gg.circle(-150,50) gg.color("#0F9D58") gg.circle(-150,100) gg.color("#F4B400") gg.circle(-150,60) gg.color("#DB4437","#DB4437") gg.begin_fill() gg.circle(-150,100) gg.right(90) gg.forward(50) gg.right(90) gg.circle(100,100) gg.right(90) gg.forward(50) gg.end_fill() gg.begin_fill() gg.color("#F4B400","#F4B400") gg.right(180) gg.forward(50) gg.right(90) gg.circle(100,60) gg.right(90) gg.forward(50) gg.right(90) gg.circle(-150,60) gg.end_fill() gg.right(90) gg.forward(50) gg.right(90) gg.circle(100,60) gg.color("#0F9D58","#0F9D58") gg.begin_fill() gg.circle(100,100) gg.right(90) gg.forward(50) gg.right(90) gg.circle(-150,100) gg.right(90) gg.forward(50) gg.end_fill() gg.right(90) gg.circle(100,100) gg.color("#4285F4","#4285F4") gg.begin_fill() gg.circle(100,25) gg.left(115) gg.forward(65) gg.right(90) gg.forward(42) gg.right(90) gg.forward(124) gg.right(90) gg.circle(-150,50) gg.right(90) gg.forward(50) gg.end_fill() google() gg.hideturtle() turtle.done()

Codehub
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You want Googlelogo?😍
Anonymous voting

Codehub
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Source Code 👇 ----------------------------------------------------- <html> <head> <style> .outer{ margin:auto; height:300px; width:400px; border:2px solid black; position:relative } p{ margin-left:80px; } .in{ margin-left:80px; padding:10px } #bt{ margin-top:20px; position:absolute; left:150px; } #bt:hover{ background:green; font-size:13px; cursor:pointer; color:white; } </style> <script> function fa(){ if(a.value=="" || b.value==""){ f() document.getElementById("a").style.border="3px solid red" document.getElementById("b").style.border="3px solid red" bt.value="Pahila data tak" } else{ document.getElementById("a").style.border="3px solid green" document.getElementById("b").style.border="3px solid green" bt.value="Ha thik ahe ata" bt.style.left="120px"; } } flag=1 function f(){ if(flag==1){ bt.style.left="210px" flag=2 } else if(flag==2){ bt.style.left="80px" flag=1 } } </script> </head> <body> <div class="outer"> <h1 style="text-align:center">Legend form</h1> <p>Enter Id</p> <input class="in" type="text" placeholder="Enter id" id="a"/> <p>Enter Confirm Pass</p> <input class="in" type="password" placeholder="Enter password" id="b"/> <br> <input type="submit" onmouseenter="fa()" onclick="alert('waaaa')" id="bt" /> </div> </body> </html>

Codehub
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Codehub
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What do we use to define a block of code in Python Programming language ?
Anonymous voting

Codehub
31 531
What do we use to define a block of code in Python Programming language ?
Anonymous voting

Codehub
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Codehub
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Here is a roadmap for becoming a full stack developer in 200 days..
Here is a roadmap for becoming a full stack developer in 200 days..

Codehub
31 531
Here is a roadmap for becoming a full stack developer in 200 days..

Codehub
31 531
A step by step guide to make money with ChatGpt 🤑👇 https://medium.com/@inprogrammer/make-money-with-chatgpt-bd80d33e7406
A step by step guide to make money with ChatGpt 🤑👇 https://medium.com/@inprogrammer/make-money-with-chatgpt-bd80d33e7406

Codehub
31 531
A step by step guide to make money with ChatGpt 🤑👇 https://medium.com/@inprogrammer/make-money-with-chatgpt-bd80d33e7406