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ACCENTURE | COGNIZANT | IBM | CAPGEMINI

ACCENTURE | COGNIZANT | IBM | CAPGEMINI

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DELOITTE SOLUTIONS GROUP: T

DELOITTE ✅✅✅✅ Contact: @MLCODER2
+1
DELOITTE ✅✅✅✅ Contact: @MLCODER2

TechMahindra round-2 ✅✅ Contact:@MLCODER2
TechMahindra round-2 ✅✅ Contact:@MLCODER2

TechMahindra Exam cleared ✅ Contact:@MLCODER2
TechMahindra Exam cleared ✅ Contact:@MLCODER2

DELOITTE SOLUTIONS GROUP: https://t.me/deloitte_oa

INFOSYS ON-CAMPUS EXAM ✅✅✅ contact: @MLCODER2
INFOSYS ON-CAMPUS EXAM ✅✅✅ contact: @MLCODER2

TECHMAHINDRA ROUND-1 ✅✅✅ CONTACT:@MLCODER2
+2
TECHMAHINDRA ROUND-1 ✅✅✅ CONTACT:@MLCODER2

IBM SLOTS AVAILABLE ✅✅ CONTACT:@MLCODER2
IBM SLOTS AVAILABLE ✅✅ CONTACT:@MLCODER2

naveensammireddy@ybl

TechMahindra ON-CAMPUS EXAM ✅✅✅ contact: @MLCODER2
+1
TechMahindra ON-CAMPUS EXAM ✅✅✅ contact: @MLCODER2

TechMahindra ON-CAMPUS EXAM ✅✅ Contact: @MLCODER2
+2
TechMahindra ON-CAMPUS EXAM ✅✅ Contact: @MLCODER2

*IBM Hiring for Associate Systems Engineer| 2024 - BE/BTECH/MCA/MTech/MSC-CS,IT,ECE,EEE Only |Location: Bangalore |Package: 4.5LPA + 25K* *Only for 2024 Graduates…🎓* *Official Links 🔗:* Registration Process: • Step 1. Apply to the job opening below on IBM career portal: Link - https://ibm.biz/BdGs58 • Step 2. Note the Person ID which will be shared in an email from IBM Talent Acquisition < talent@ibm.com>. Ensure you keep this ID handy for the next step. • Step 3. Go to the link below and complete the radancy form. • ⁠ Link - https://ibm.biz/BdGs5s Kindly ensure that you provide accurate academic information in the Radancy form. *Apply Asap 🔥* *Note: Apply asap. Don’t Delay*

HCL EXAM DONE SUCCESSFULLY ✅✅✅ Contact: @MLCODER2
HCL EXAM DONE SUCCESSFULLY ✅✅✅ Contact: @MLCODER2

HCL EXAM ✅ ✅ Contact: @MLCODER2
+5
HCL EXAM ✅ ✅ Contact: @MLCODER2

n=int(input()) arr=[int(i) for i in input().split()] k=int(input()) print(*(arr[-k:]+arr[:-k]))

WIPRO 12PM SLOT DONE SUCCESSFULLY ✅ Contact: @MLCODER2
+3
WIPRO 12PM SLOT DONE SUCCESSFULLY ✅ Contact: @MLCODER2

Wipro 12 pm ✅✅
Wipro 12 pm ✅✅

x,y,z=map(int,input().split()) print(sum(sorted([x,y,z])[1:])) #sum_of_maximum_two_numbers

print(sum(int(i) for i in input().split() if int(i)<0)) #sum of negative numbers

n=int(input()) arr=[int(i) for i in input().split()] p=[i for i in arr if i>0] mid=len(p)//2 if mid%2==0:print(p[mid-1]) else:print(p[mid]) #positviemidindex