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ACCENTURE | COGNIZANT | IBM | CAPGEMINI

ACCENTURE | COGNIZANT | IBM | CAPGEMINI

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Company: Capgemini Role: SAP SD Experience Required: Minimum 6 months to 3 Years of genuine experience in any domain (non-IT experience is also acceptable) Package: ₹5.5L + 25k bonus (5.75LPA) Location: PAN India Process Duration: Approximately 1 month Notice Period: Immediate joiners only (Upto 30 days notice period accepted) Eligibility: Open to both male and female candidates Year of passing: 2021-2024 Process - 1.Registration. 2.Online Exam 3.Technical Interview 4.LOI 5.Offer letter All Rounds will be Virtual Note : candidate should have 6 months genuine work experience(IT or NON-IT) including payslips and bank statement. Interested people can reach out @MLCODER2

Capgemini offer letter for SAP role ✅ Contact : @MLCODER2
Capgemini offer letter for SAP role ✅ Contact : @MLCODER2

import heapq from collections import defaultdict def solve(n, m, k, treasures, bridges, queries): graph = defaultdict(list) for u, v, w in bridges: graph[u - 1].append((v - 1, w)) results = [] for start, end in queries: start -= 1 end -= 1 pq = [(-treasures[start], 0, start)] visited = {} while pq: neg_tres, time, node = heapq.heappop(pq) total_treasure = -neg_tres if node == end: results.append((total_treasure, time)) break if node in visited and visited[node] >= total_treasure: continue visited[node] = total_treasure for nei, wt in graph[node]: if nei not in visited or visited[nei] < total_treasure + treasures[nei]: heapq.heappush(pq, (-(total_treasure + treasures[nei]), time + wt, nei)) return results n, m, k = map(int, input().split()) treasures = list(map(int, input().split())) bridges = [tuple(map(int, input().split())) for _ in range(m)] queries = [tuple(map(int, input().split())) for _ in range(k)] result = solve(n, m, k, treasures, bridges, queries) for treasure, time in result: print(treasure, time) q3 //quantiphi ✅

def max_points(points): n = len(points) if n == 0: return 0 if n == 1: return points[0] dp = [0] * n dp[0] = points[0] dp[1] = max(points[0], points[1]) for i in range(2, n): dp[i] = max(dp[i-1], points[i] + dp[i-2]) return dp[-1] n = int(input()) points = list(map(int, input().split())) print(max_points(points)) q2 //quantiphi ✅

import math def is_possible(K, houses, H): total_time = 0 for house in houses: total_time += math.ceil(house / K) return total_time <= H def find_min_K(n, H, houses): low = 1 high = max(houses) answer = high while low <= high: mid = (low + high) // 2 if is_possible(mid, houses, H): answer = mid high = mid - 1 else: low = mid + 1 return answer n, H = map(int, input().split()) houses = list(map(int, input().split())) print(find_min_K(n, H, houses)) q1 //quantiphi✅

Capgemini ✅✅ Contact: @MLCODER2
Capgemini ✅✅ Contact: @MLCODER2

Capgemini 12pm slots available ✅ Contact: @MLCODER2

company : Capgemini Role : Associate software Engineer Batches : 2023/3034/3035/ Location : Bangalore/Chennai Link to apply : https://careers.capgemini.com/job/Bangalore-Associate-Software-Engineer/1225820501/

ION all slots ✅✅ Contact : @MLCODER2
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ION all slots ✅✅ Contact : @MLCODER2

IBM✅✅
+1
IBM✅✅

Paypal exam done & dusted ✅✅ Python 4+ years experienced ✅
+3
Paypal exam done & dusted ✅✅ Python 4+ years experienced ✅

Q2 done & dusted✅✅
Q2 done & dusted✅✅

Done & Dusted ✅✅✅
Done & Dusted ✅✅✅

Flipkart OA cleared ✅ Contact: @MLCODER2
Flipkart OA cleared ✅ Contact: @MLCODER2

def ArrayChallenge(strArr): s1, s2 = strArr[0], strArr[1] n, m = len(s1), len(s2) dp = [[0] * (m + 1) for _ in range(n + 1)] for i in range(1, n + 1): for j in range(1, m + 1): if s1[i - 1] == s2[j - 1]: dp[i][j] = dp[i - 1][j - 1] + 1 else: dp[i][j] = max(dp[i - 1][j], dp[i][j - 1]) return dp[n][m] AssestSense ✅ //q1

q2 AssestSense✅
q2 AssestSense✅

def MathChallenge(num): coins = [1, 5, 7, 9, 11] dp = [float('inf')] * (num + 1) dp[0] = 0 for i in range(1, num + 1): for coin in coins: if i >= coin: dp[i] = min(dp[i], dp[i - coin] + 1) return dp[num] AssestSense✅ //q2

Epam12pm slot done & dusted ✅✅ Contact: @MLCODER2
+1
Epam12pm slot done & dusted ✅✅ Contact: @MLCODER2

12PM & 2pm Epam exam help Available Contact : @MLCODER2

EPAM ✅ Magic spell ✔️ sum-Two pairs ✔️ Contact: @MLCODER2