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#include <iostream> #include <vector> #include <algorithm> using namespace std; int nSk(int n, int k){ if (n < 2) return 1; if (k > n-2) return 0; vector<int> numbers; numbers.reserve(n - 2); for (int i = 0; i < n - 2; ++i){ numbers.push_back(i + 2); } std::vector<bool> v(numbers.size()); std::fill(v.end() - k, v.end(), true); int ret = 0; do { int tmpnum = 1; for (int j = 0; j < numbers.size(); ++j) { if (v[j]) { tmpnum *= numbers[j]; } } ret += tmpnum; } while (std::next_permutation(v.begin(), v.end())); return ret; } int main(){ int n, d; cin >> n; cin >> d; int sum = 0; for (int k = 0; k < d; ++k){ sum += nSk(n, k); } //sum *= 2; cout<< sum; } Coins code

Take one loop for array a and inside the loop take another loop for array b and traverse and check the elements of both array

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