OSSSC / OSSC MATH AND REASONING
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𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH
نمایش بیشتر
شبکه:📈 تحلیل کانال تلگرام OSSSC / OSSC MATH AND REASONING
کانال OSSSC / OSSC MATH AND REASONING (@pinnacle_math_reasoning) در بخش زبانی انگلیسی بازیگری فعال است. در حال حاضر جامعه شامل 11 514 مشترک است و جایگاه 17 145 را در دسته آموزش و رتبه 33 527 را در منطقه الهند دارد.
📊 شاخصهای مخاطب و پویایی
از زمان ایجاد در невідомо، پروژه رشد سریعی داشته و 11 514 مشترک جذب کرده است.
بر اساس آخرین دادهها در تاریخ 27 سپتامبر, 2026، کانال فعالیت پایداری دارد. در ۳۰ روز گذشته تغییر اعضا برابر 166 و در ۲۴ ساعت گذشته برابر -6 بوده و همچنان دسترسی گستردهای حفظ شده است.
- وضعیت تأیید: تأیید نشده
- نرخ تعامل (ER): میانگین تعامل مخاطب 18.24% است و در ۲۴ ساعت نخست پس از انتشار، محتوا معمولاً 4.61% واکنش نسبت به کل مشترکان کسب میکند.
- دسترسی پستها: هر پست به طور میانگین 2 100 بازدید دریافت میکند. در اولین روز معمولاً 531 بازدید جمعآوری میشود.
- واکنشها و تعامل: مخاطبان بهطور فعال حمایت میکنند؛ میانگین واکنش به هر پست 2 است.
- علایق موضوعی: محتوا بر موضوعات کلیدی مانند ʜᴇʀᴇ, cgle, cgl, mcqs, mcq تمرکز دارد.
📝 توضیح و سیاست محتوایی
نویسنده این فضا را محل بیان دیدگاههای شخصی توصیف میکند:
“𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS
Join our YouTube Channel: https://shorturl.at/Ulwjw
🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY
🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH”
به لطف بهروزرسانیهای پرتکرار (آخرین داده در تاریخ 28 سپتامبر, 2026)، کانال همواره بهروز و دارای دسترسی بالاست. تحلیلها نشان میدهد مخاطبان بهطور فعال با محتوا تعامل دارند و آن را به نقطه اثرگذاری مهم در دسته آموزش تبدیل کردهاند.
11 514
مشترکین
-624 ساعت
+157 روز
+16630 روز
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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬
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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ After giving two successive discounts of 20% and 25% a cycle is sold for Rs. 4200. What is the marked price (in Rs) of the cycle ?
𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤA cuboid is formed by adding two cubes of 5 cm. Find the total surface area of the cuboid.
Given
👉12 men 6 days
👉18 women = 8 days
Calculation
👉12men x 6 days = 18women x 8
👉72 men = 144 women
👉1 men = 2 women
👉1 women = 1/2 men
👉2 women = 1 men 4 women = (1/2) x 4 men 4 women = 2 men. .................(1) 👉Total number of men = 12 men + 4 women =12 men + 2 men (from 1) Total number of men = 14 Number of days required by 12 men and 4 women 👉(12 x 6)/14 = 72/14 = 36/7
👉5.14 days(approx) or 5 days .: 12 men and 4 women complete a work in 5 days.
𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ12 men can do a piece of work in 6 days while 18 women can do it in 8 days. In how many days can 12 men and 4 women.
Three bottles of equal capacity are containing a mixture of milk and water in ratio 2:1, 3:7 and 4:11 respectively. These three bottles are emptied into a large bottle. What is the ratio of milk and water respectively in this large bottle ?👆👆👆
𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤThree bottles of equal capacity are containing a mixture of milk and water in ratio 2:1, 3:7 and 4:11 respectively. These three bottles are emptied into a large bottle. Wh
For same distance,
Time is inversely proportional to velocity.
Ratio of time taken = ((((1/10) / 1) / 12) / 1) / 15
LCM of 10, 12 and 15 = 60
The required ratio = 60 x 1/10: 60 × 1/12: 60 x 1/15 = (6/5) / 4
.. The required ratio is 6:5: 4.
𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤThe ratio of the speed of P, Q and R is 10:12:15 respectively. What is the ratio of the time taken by P, Q and R respectively to cover the same distance ?
𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤIf a certain sum becomes 4 times in 4 years at compound interest, then in how many years, it will become 64 times ?
👉Sum of 11 results = 11 * 182 = 2002
👉Sum of first 6 results = 6 * 199 = 1194
👉Sum of last 6 results = 6 * 161 = 966
👉Total sum = 2160
👉6 (th) result = 2160 - 2002 = 158
