Coding & AI Resources
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نمایش بیشتر📈 تحلیل کانال تلگرام Coding & AI Resources
کانال Coding & AI Resources (@leadcoding) در بخش زبانی انگلیسی بازیگری فعال است. در حال حاضر جامعه شامل 35 474 مشترک است و جایگاه 5 368 را در دسته آموزش و رتبه 11 814 را در منطقه الهند دارد.
📊 شاخصهای مخاطب و پویایی
از زمان ایجاد در невідомо، پروژه رشد سریعی داشته و 35 474 مشترک جذب کرده است.
بر اساس آخرین دادهها در تاریخ 11 ژوئن, 2026، کانال فعالیت پایداری دارد. در ۳۰ روز گذشته تغییر اعضا برابر 70 و در ۲۴ ساعت گذشته برابر -4 بوده و همچنان دسترسی گستردهای حفظ شده است.
- وضعیت تأیید: تأیید نشده
- نرخ تعامل (ER): میانگین تعامل مخاطب 3.50% است و در ۲۴ ساعت نخست پس از انتشار، محتوا معمولاً N/A% واکنش نسبت به کل مشترکان کسب میکند.
- دسترسی پستها: هر پست به طور میانگین 1 241 بازدید دریافت میکند. در اولین روز معمولاً 0 بازدید جمعآوری میشود.
- واکنشها و تعامل: مخاطبان بهطور فعال حمایت میکنند؛ میانگین واکنش به هر پست 6 است.
- علایق موضوعی: محتوا بر موضوعات کلیدی مانند learning, link:-, element, programming, analytic تمرکز دارد.
📝 توضیح و سیاست محتوایی
نویسنده این فضا را محل بیان دیدگاههای شخصی توصیف میکند:
“📚Get daily updates for :
✅ Free resources
✅ All Free notes
✅ Internship,Jobs
and a lot more....😍
📍Join & Share this channel with your friends and college mates ❤️
Managed by: @love_data
Buy ads: https://telega.io/c/leadcoding”
به لطف بهروزرسانیهای پرتکرار (آخرین داده در تاریخ 12 ژوئن, 2026)، کانال همواره بهروز و دارای دسترسی بالاست. تحلیلها نشان میدهد مخاطبان بهطور فعال با محتوا تعامل دارند و آن را به نقطه اثرگذاری مهم در دسته آموزش تبدیل کردهاند.
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Subject: Application For The [Role] at [Company Name] Dear [Hiring Manager’s Name], I hope you’re doing great. I came across the [Position Title] role at [Company Name] and was really excited about the opportunity to apply. With my experience in [mention key relevant experience], I believe I could bring value to your team. I’ve attached my Resume for your review. I trust my background aligns with what you’re looking for, I’d love the chance to discuss how I can contribute to your team. Looking forward to hearing your thoughts! Best regards, [Your Name] [Link To Linkedin] [Link To Resume]📩 Message to a Recruiter After Seeing Their Job Posting
Subject: Excited to Apply for [Position Title] at [Company Name] Hi [Recruiter’s Name], I trust you have a awesome day today 🙂 I just saw your post about the [Position Title] opening at [Company Name], and I couldn’t wait to reach out! I’ve been following [Company Name] for a while now, and I truly admire [mention something specific—company’s projects, culture, values, recent achievements]. With my expertise in [mention relevant skills/experience], I believe I’d be a great fit for this role. I’ve attached my Resume for your review, and I’d love the chance to discuss how my experience can contribute to your team. Would you be open to a quick chat? Looking forward to your thoughts! [Your Resume]✉️ Warm Networking DM
Subject: Exploring Opportunities at [Company Name] Hi [First Name], I believe you have a wonderful day today 😊 I’m a [Your Role] specializing in [mention key skills]. I’ve been following [Company Name] for a while and love [mention something specific about their work, culture, or achievements]. With experience in [mention a key project or skill], I believe I could bring value to your team. If you’re open to it, I’d love to chat about any opportunities, where my skills could be a great fit. I know you must get a ton of messages, so I really appreciate your time. Looking forward to hearing from you! Warm, [Your Name] [Your Resume]
def is_palindrome(s):
return s == s[::-1]
print(is_palindrome("madam")) # True
print(is_palindrome("hello")) # False
2. How to find the factorial of a number using recursion?
def factorial(n):
if n == 0 or n == 1:
return 1
return n * factorial(n - 1)
print(factorial(5)) # 120
3. How to merge two dictionaries in Python?
dict1 = {'a': 1, 'b': 2}
dict2 = {'c': 3, 'd': 4}
# Method 1 (Python 3.5+)
merged_dict = {**dict1, **dict2}
# Method 2 (Python 3.9+)
merged_dict = dict1 | dict2
print(merged_dict)
4. How to find the intersection of two lists?
list1 = [1, 2, 3, 4]
list2 = [3, 4, 5, 6]
intersection = list(set(list1) & set(list2))
print(intersection) # [3, 4]
5. How to generate a list of even numbers from 1 to 100?
even_numbers = [i for i in range(1, 101) if i % 2 == 0]
print(even_numbers)
6. How to find the longest word in a sentence?
def longest_word(sentence):
words = sentence.split()
return max(words, key=len)
print(longest_word("Python is a powerful language")) # "powerful"
7. How to count the frequency of elements in a list?
from collections import Counter
my_list = [1, 2, 2, 3, 3, 3, 4]
frequency = Counter(my_list)
print(frequency) # Counter({3: 3, 2: 2, 1: 1, 4: 1})
8. How to remove duplicates from a list while maintaining the order?
def remove_duplicates(lst):
return list(dict.fromkeys(lst))
my_list = [1, 2, 2, 3, 4, 4, 5]
print(remove_duplicates(my_list)) # [1, 2, 3, 4, 5]
9. How to reverse a linked list in Python?
class Node:
def __init__(self, data):
self.data = data
self.next = None
def reverse_linked_list(head):
prev = None
current = head
while current:
next_node = current.next
current.next = prev
prev = current
current = next_node
return prev
# Create linked list: 1 -> 2 -> 3
head = Node(1)
head.next = Node(2)
head.next.next = Node(3)
# Reverse and print the list
reversed_head = reverse_linked_list(head)
while reversed_head:
print(reversed_head.data, end=" -> ")
reversed_head = reversed_head.next
10. How to implement a simple binary search algorithm?
def binary_search(arr, target):
low, high = 0, len(arr) - 1
while low <= high:
mid = (low + high) // 2
if arr[mid] == target:
return mid
elif arr[mid] < target:
low = mid + 1
else:
high = mid - 1
return -1
print(binary_search([1, 2, 3, 4, 5, 6, 7], 4)) # 3
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اکنون در دسترس! پژوهش تلگرام ۲۰۲۵ — مهمترین بینشهای سال 
